Chapter 6: Problem 87
Factor completely. $$-32 x^{2} y^{4}+20 x y^{4}+12 y^{4}$$
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Chapter 6: Problem 87
Factor completely. $$-32 x^{2} y^{4}+20 x y^{4}+12 y^{4}$$
These are the key concepts you need to understand to accurately answer the question.
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In Exercises \(142-146,\) use the \([\mathrm{GRAPH}]\) or \([\text { TABLE }]\) feature of a graphing utility to determine if the polynomial on the left side of each equation has been correctly factored. If not, factor the polynomial correctly and then use your graphing utility to verify the factorization. $$\begin{aligned} &3 x^{3}-12 x^{2}-15 x=3 x(x+5)(x-1) ;[-5,7,1] \text { by }\\\ &[-80,80,10] \end{aligned}$$
Simplify: \(\left(2 x^{2} y^{3}\right)^{4}\left(5 x y^{2}\right) .\) (Section 5.7, Example 5)
If \((x+2)(x-4)=0\) indicates that \(x+2=0\) or \(x-4=0,\) explain why \((x+2)(x-4)=6\) does not mean \(x+2=6\) or \(x-4=6 .\) Could we solve the equation using \(x+2=3\) and \(x-4=2\) because \(3 \cdot 2=6 ?\)
Make Sense? In Exercises \(115-118\), determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. Although I can factor the difference of squares and perfect square trinomials using trial-and-error, recognizing these special forms shortens the process.
Solve: \(5 x+28=6-6 x\). (Section \(2.2,\) Example 7 )
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