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Use the method of your choice to factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$2 x^{2}+3 x y+y^{2}$$

Short Answer

Expert verified
The factorized form of the trinomial \(2x^{2}+3xy+y^{2}\) is \((\sqrt{2}x + y)^{2}\)

Step by step solution

01

Identify the form of the trinomial

The trinomial \(2x^{2}+3xy+y^{2}\) is in the form of the perfect square trinomial \(a^{2}+2ab+b^{2}\). On comparing, we have \(a = x\), \(b = y\), and the coefficient of \(x^{2}\) (which is \(2\)) is \(a^{2}\). Take square root of \(2\) and write \(a\) in the new term.
02

Factorize the trinomial

We can factorize \(2x^{2}+3xy+y^{2}\) as \((\sqrt{2}x + y)^{2}\).
03

Verify your factorization

To verify the factorization, we'll use the FOIL multiplication method (First Outer Inner Last). Multiply \((\sqrt{2}x+y)\) by itself: First: \((\sqrt{2}x) * (\sqrt{2}x) = 2x^{2}\), Outer: \((\sqrt{2}x) * y = \sqrt{2}xy\), Inner: \(y * (\sqrt{2}x) = y\sqrt{2}x\), Last: \(y * y = y^{2}\). Add these up: \(2x^{2} + \sqrt{2}xy + y\sqrt{2}x + y^{2} = 2x^{2} + 2\sqrt{2}xy + y^{2}\), which simplifies to \(2x^{2} +3xy + y^{2}\), the original trinomial. Hence, the factorization was correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

FOIL Multiplication
Understanding FOIL multiplication is like learning a dance move that can help you solve algebraic problems with grace. FOIL is an acronym that stands for First, Outer, Inner, Last. It is a straightforward technique used for multiplying two binomials. Let’s take the binomials \(a+b\) and \(c+d\). When using FOIL:

  • \(First\) refers to multiplying the first terms of each binomial, which is \(a \times c\).
  • \(Outer\) means multiplying the outermost terms, or \(a \times d\).
  • \(Inner\) refers to the inner terms, giving us \(b \times c\).
  • Finally, \(Last\) points to the last terms of the binomials, \(b \times d\).

So the product of \(a+b\) and \(c+d\) using the FOIL method is \(ac + ad + bc + bd\). This method can also be used to check the factorization of trinomials to ensure that the right terms and constants have been paired to recreate the original expression.
Perfect Square Trinomial
A perfect square trinomial is a special type of trinomial that can be factored into a binomial multiplied by itself. It follows the formula \(a^{2}+2ab+b^{2}= (a+b)^{2}\). When faced with a trinomial like \(2x^{2}+3xy+y^{2}\), identifying it as a perfect square can be like recognizing a familiar face in a crowd. It fits the pattern, where \(a\) and \(b\) are the square roots of \(2x^{2}\) and \(y^{2}\) respectively, while \(2ab\) aligns with \(3xy\).

Factoring it involves writing it as \(a+b\) squared, which, in this case, is \(\sqrt{2}x + y\) squared. The charm of a perfect square is in its simplicity – it achieves a complex task of factorization by channeling it through the square of a binomial, providing a quick and elegant solution to otherwise daunting algebraic expressions. Recognizing and factoring perfect square trinomials is a skill that greatly simplifies the process of solving quadratic equations and other algebraic challenges.
Intermediate Algebra
Intermediate algebra is the branch of mathematics that deals with the properties and manipulation of expressions with variables. It sets the stage for advanced mathematical topics and real-world problem-solving involving unknown quantities. In the realm of intermediate algebra, factorization plays a starring role. It is a method of breaking down complex expressions into simpler ones, which can be easily solved or used in further calculations.

Factorization techniques require an understanding of various concepts like greatest common factors, the difference of squares, sum and difference of cubes, and the factoring of trinomials such as perfect square trinomials and others. In our example, involving the factorization of the trinomial \(2x^{2}+3xy+y^{2}\), we see intermediate algebra in action. By recognizing patterns and applying formulas to factorize expressions, students prepare themselves to handle more complicated math, including polynomial functions, graphing, and even calculus further down the line. As the launching pad for future exploration into the mathematical universe, mastering intermediate algebra is an essential step for any aspiring mathematician or professional in a STEM field.

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