/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 113 Explain why \(x^{2}-1\) is facto... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain why \(x^{2}-1\) is factorable, but \(x^{2}+1\) is not.

Short Answer

Expert verified
\(x^{2}-1\) is factorable because it has two real solutions \(x=1\) and \(x=-1\), while \(x^{2}+1\) is not factorable using real numbers because it does not have real solutions, but two complex ones \(x=i\) and \(x=-i\).

Step by step solution

01

Factoring \(x^{2}-1\)

The equation \(x^{2}-1=0\) can be factored into \((x-1)(x+1)=0\), which appeals to the difference of squares formula \(a^{2}-b^{2}=(a+b)(a-b)\), where \(a=x\) and \(b=1\). Here both solutions, \(x=1\) and \(x=-1\), are real.
02

Trying to Factor \(x^{2}+1\)

The equation \(x^{2}+1=0\) can supposedly be factored as \((x-i)(x+i)=0\), referring to the sum of squares formula \(a^{2}+b^{2}=(a+ib)(a-ib)\), where \(a=x\) and \(b=1\). However, the solutions \(x=i\) and \(x=-i\) are not real but complex numbers. In the realm of real numbers, it is not possible to factor \(x^{2}+1\).
03

Conclusion

Since the polynomial \(x^{2}-1\) has real solutions, it can be factored using real numbers. On the other hand, the polynomial \(x^{2}+1\) does not have real solutions, hence it cannot be factored using only real numbers. The roots need to be real for the factorization to happen hence proving the initial question. This concludes the analysis of the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
Understanding the difference of squares is crucial when dealing with polynomial factorization. This method applies when you have a polynomial in the form of \(a^2 - b^2\), which breaks down into \((a+b)(a-b)\). A classic example of this is \(x^2 - 1\), which factors neatly into \((x-1)(x+1)\).

In this process, we identify two squares, \(a^2\) and \(b^2\), and express them as a subtraction, thus allowing us to factor them into a product of binomials. The solutions derived from this factorization are real numbers, meaning they can be plotted on the real number line and used in real-world applications.
Complex Numbers
When we encounter equations like \(x^2 + 1\), we delve into the world of complex numbers. These numbers include a real part and an imaginary part, often expressed as \(a + bi\), where \(i\) represents the imaginary unit \(\sqrt{-1}\). Complex numbers expand our ability to find solutions for equations that do not have real solutions. In our example \(x^2 + 1 = 0\), factoring leads to solutions involving \(i\), namely \(x = i\) and \(x = -i\). Although it might seem odd, complex numbers are fully legitimate in the mathematical universe and are widely used in fields such as engineering, physics, and signal processing.
Real Solutions
Real solutions to polynomial equations are the 'x' values that satisfy the equation when graphed on the standard Cartesian plane. These solutions do not involve the imaginary unit \(i\) and are considered 'real' because they can represent quantities or measurements in the physical world. For instance, the equation \(x^2 - 1 = 0\) provides us with real solutions \(x = 1\) and \(x = -1\), which imply that the original expression can factor over the set of real numbers. Real solutions are often expected in basic algebraic tasks and real-world problem-solving scenarios.
Sum of Squares
Contrary to the difference of squares, the sum of squares does not factor in a straightforward manner using just real numbers. When we have a polynomial like \(x^2 + 1\), we can't use real numbers to break it down into simpler factors. That's because there are no real numbers that squared, would add up to a negative result (necessary to cancel out the +'1' when factoring). Thus, this is where complex numbers come into play. While the difference of squares is a fundamental identity in algebra, the sum of squares does not possess a similar easy-to-use identity within the realm of real numbers. It's a subtle but important distinction that illustrates the limits of real solutions and the need for complex numbers in certain situations.

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