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Solve each system by the addition method. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\\{\begin{array}{l}x+y=-3 \\ x-y=11\end{array}\right.$$

Short Answer

Expert verified
The system has one unique solution expressed in set notation as \(\{(4, -7)\}\)

Step by step solution

01

Setup the equation

The problem has already provided the two equations: \(x + y = -3\) and \(x - y = 11\). They are already set up perfectly for the addition method because the y's in both equations are opposites, therefore they will cancel each other out when added.
02

Apply the addition method

Add the two equations together: \[(x + y) + (x - y) = -3 + 11\]. Here, y in the first equation and -y in the second equation cancel each other out, and you are left with \(2x = 8\). This simplifies to the solution \(x = 4\).
03

Solve for the other variable

Substitute \(x = 4\) into the first of the original equations (you can choose either equation, but the first is a bit simpler since it doesn't have a negative): \(4 + y = -3\). Solve for y to get \(y = -3 - 4 = -7\)
04

Express the answer in set notation

The system of linear equations has one unique solution, which is the pair (x = 4, y = -7). Express this solution in set notation as \(\{(4, -7)\}\). This means the set of all solutions of the system is the set consisting of only that one pair. If no solutions or infinite solutions existed instead, you would state that appropriately.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Systems of Equations
The ability to solve systems of equations is a foundational skill in algebra. It involves finding the values of variables that make all the equations work simultaneously. In our exercise, we tackled a system using the addition method, a strategic technique for eliminating one variable to isolate the other. This method is particularly useful when the coefficients of one variable are opposites, as we saw with the variables 'y'.

By adding both equations, the variable 'y' was eliminated, leading us to find the value of 'x'. Once 'x' was known, substituting it back into either equation allowed for solving 'y'. The step-by-step solution is clear, but students should remember that this process can be applied to any similar system of equations. Practice is crucial, so try solving various systems to become fluent in this algebraic operation. Additionally, always verify the solution by plugging the values back into the original equations to ensure they satisfy both conditions.
Algebraic Set Notation
Set notation is the language used to describe collections of objects, in this case, solutions to an equation or system of equations. In algebra, it provides a concise way to represent complex information. The solution set to a system of linear equations can be a single ordered pair, multiple pairs, or even no solution at all. For instance, in our problem, the single unique solution \(x = 4, y = -7\) is represented as \(\{(4, -7)\}\).

Understanding set notation is essential for communicating mathematical solutions effectively. It’s a stepping stone to more advanced topics in mathematics, where set theory plays a crucial role. When dealing with solution sets, remember that curly brackets \(\{ \}\) encompass all potential solutions, and each solution within is separated by commas if there are more than one.
Linear Algebra
Linear algebra is a significant branch of mathematics focusing on linear equations, vectors, and matrices. Our exercise illustrates a key aspect of linear algebra: solving linear systems. While this example is a simple 2-variable case, linear algebra techniques expand to handle the much larger and complex systems found in various applications, from computer graphics to engineering.

By using the addition method to solve the system of equations, we are essentially performing a linear operation to reduce the system to a solvable form. Linear algebra's fundamentals begin with these basic operations but later involve more advanced concepts such as vector spaces and transformations. Grasping these building blocks is vital, as they form the basis for understanding how to navigate the vast and intricate landscapes of linear systems in higher-level mathematics and applied fields.

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Most popular questions from this chapter

One apartment is directly above a second apartment. The resident living downstairs calls his neighbor living above him and states, "If one of you is willing to come downstairs, we'll have the same number of people in both apartments." The upstairs resident responds, "We're all too tired to move. Why don't one of you come up here? Then we'll have twice as many people up here as you've got down there." How many people are in each apartment?

Solve each system by the method of your choice. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. Explain why you selected one method over the other two. $$\left\\{\begin{array}{l}y=2 x+4 \\ y=2 x-1\end{array}\right.$$

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. The equations \(y=x-1\) and \(x=y+1\) are dependent.

A telephone plan has a monthly fee of 20 dollar with a charge of 0.05 dollar per minute. a. What is the total monthly cost for the plan if there are 200 minutes of calls? b. Write a formula that describes the total monthly cost of the plan, \(y,\) for \(x\) minutes of calls.

Use the four-step strategy to solve each problem. Use \(x, y,\) and \(z\) to represent unknown quantities. Then translate from the verbal conditions of the problem to a system of three equations in three variables. A certain brand of razor blades comes in packages of \(6,12,\) and 24 blades, costing \(\$ 2, \$ 3,\) and \(\$ 4\) per package, respectively. A store sold 12 packages containing a total of 162 razor blades and took in \(\$ 35 .\) How many packages of each type were sold?

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