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Chapter 3: Problem 97

Explain why \((5,-2)\) and \((-2,5)\) do not represent the same point.

Short Answer

Expert verified
The points \((5,-2)\) and \((-2,5)\) represent different locations on the Cartesian plane because their x-coordinates \(5 \neq -2\) and their y-coordinates \(-2 \neq 5\). Therefore, the points \((5,-2)\) and \((-2,5)\) do not represent the same point.

Step by step solution

01

Understand the coordinate system

A point in the two-dimensional Cartesian coordinate system is represented by an ordered pair of numbers \((x, y)\), called coordinates. This pair represents the horizontal (x) and vertical (y) distances from the origin, usually denoted as \((0,0)\)
02

Identify the coordinates of the two points

The two given points are \((5,-2)\) and \((-2,5)\). Here, for the point \((5,-2)\), the x-coordinate is 5 and the y-coordinate is -2 whereas for the point \((-2,5)\), the x-coordinate is -2 and the y-coordinate is 5.
03

Determine if the two points are the same

Two points are the same if and only if both of their x-coordinates are the same and their y-coordinates are the same. Comparing the two points, the first point has an x-coordinate of 5, which doesn't match the x-coordinate of the second point, -2. Similarly, the first point has a y-coordinate of -2, while the second point has a y-coordinate of 5. Since neither the x-coordinates nor the y-coordinates are the same, the points \((5,-2)\) and \((-2,5)\) are not the same.

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Most popular questions from this chapter

Write an equation in slope-intercept form of the line satisfying the given conditions. The line passes through \((-6,4)\) and is perpendicular to the line that has an \(x\) -intercept of 2 and a \(y\) -intercept of \(-4\)

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In Exercises \(13-26,\) begin by solving the linear equation for \(y .\) This will put the equation in slope-intercept form. Then find the slope and the \(y\) -intercept of the line with this equation. $$-9 x+y=5$$

How do you determine whether an ordered pair is a solution of an equation in two variables, \(x\) and \(y ?\)

When finding the slope of the line passing through \((-1,5)\) and \((2,-3),\) I must let \(\left(x_{1}, y_{1}\right)\) be \((-1,5)\) and \(\left(x_{2}, y_{2}\right)\) be \((2,-3)\).
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