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Find a general term, \(a_{n},\) for each sequence. More than one answer may be possible. $$-1,1,-1,1, \dots$$

Short Answer

Expert verified
The general term \(a_{n}\) for the given sequence is \(a_{n}=(-1)^n\).

Step by step solution

01

Observation of the pattern

The given sequence is -1, 1, -1, 1, ... . Here, it can be noticed that all the terms in even places are 1 while all the terms in odd places are -1.
02

Formulate the general term

The general term of a sequence is represented as \(a_{n}\), where n is the term number. As observed, the sequence gives -1 when n is odd and 1 when n is even. This observation can be mathematically represented using the (-1) power n. Hence, the general term \(a_{n}=(-1)^n\)
03

Testing the General Term

To verify that this is the suitable formula, plug in some values of n corresponding to the sequence. When n=1, \(a_{1}=(-1)^1=-1\), when n=2, \(a_{2}=(-1)^2=1\). This pattern continues, and thus verifies the correctness of \(a_{n}=(-1)^n\) as the general term of the sequence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

General Term
In arithmetic, the general term is like a recipe telling us how to cook up any specific term in a sequence without writing out all the terms. It is denoted usually as \(a_n\), where \(n\) represents the position number in the sequence. For our particular sequence, \(-1, 1, -1, 1, \ldots\), we want to find a way to determine any term directly. The essence is to create a formula that delivers the appropriate term when given its position. In this case, through our observations, we see that an even \(n\) results in \(1\) and an odd \(n\) results in \(-1\). Thus, the general term for this sequence can be expressed using powers of \(-1\), simply written as \(a_n = (-1)^n\).
This formula cleverly uses the properties of exponents. When \(-1\) is raised to an even number, the result is \(1\), and when raised to an odd number, it is \(-1\). This matches perfectly with our sequence.
Pattern Recognition
Pattern recognition in sequences is like solving a puzzle by spotting recurring themes or properties. In the sequence \(-1, 1, -1, 1, \ldots\), recognizing the pattern is key to understanding and predicting the sequence's behavior without listing every term.
First, you dive into the sequence to see what's repeating. For our sequence, the terms switch back and forth between \(-1\) and \(1\). This alternation suggests a systematic pattern based on the parity (odd or even nature) of their positions. By recognizing that alternate terms have different values, you can deduce that:- Terms in odd positions are \(-1\)
- Terms in even positions are \(1\)
This insight not only helps in deciphering this specific sequence but also hones your ability to tackle similar sequence puzzles in the future.
Even and Odd Sequences
Understanding even and odd sequences plays a pivotal role in algebraic pattern recognition. Our sequence, \(-1, 1, -1, 1, \ldots\), is a perfect illustration. We leverage the concept of even and odd numbers to predict the sequence's behavior.
In simple terms, even numbers (like 2, 4, 6, ...), when used as exponents of \(-1\), yield positive \(1\). Conversely, odd numbers (like 1, 3, 5, ...) result in \(-1\). This gives a neat alternation of values as seen in our sequence.
  • Even indexed positions show a consistent pattern of \(1\)
  • Odd indexed positions consistently hold the value \(-1\)
Thus, by using the properties of even and odd numbers, we managed not only to understand the sequence fully but also engineered its general term \(a_n = (-1)^n\), capitalizing on this insight into numerical parity.

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Most popular questions from this chapter

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