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Use the Binomial Theorem to expand each expression and write the result in simplified form. $$\left(x^{2}+x^{-3}\right)^{4}$$

Short Answer

Expert verified
The expansion and simplification of \((x^{2}+x^{-3})^{4}\) using the Binomial Theorem is \(x^{8} + 4x^{3} + 6x^{-2} + 4x^{-7} + x^{-12}\)

Step by step solution

01

Understand the Binomial Theorem

The Binomial Theorem states that for any number n, \((a+b)^{n} = \sum_{k=0}^{n} {n \choose k}a^{n-k}b^{k}\). Here, \({n \choose k}\) is the binomial coefficient which represents the number of ways to choose k elements from a set of n elements.
02

Apply the Binomial Theorem

Apply the formula to \((x^{2}+x^{-3})^{4}\) and calculate the value of each term. This gives us 5 terms (from k=0 to k=4): \({4 \choose 0}(x^{2})^{4}(x^{-3})^{0} + {4 \choose 1}(x^{2})^{3}(x^{-3})^{1} + {4 \choose 2}(x^{2})^{2}(x^{-3})^{2} + {4 \choose 3}(x^{2})^{1}(x^{-3})^{3} + {4 \choose 4}(x^{2})^{0}(x^{-3})^{4}\)
03

Simplify the expression

Simplify each individual term to obtain the final result. This yields \(x^{8} + 4x^{3} + 6x^{-2} + 4x^{-7} + x^{-12}\)

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