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Write the first four terms of each sequence whose general term is given. $$a_{n}=(-3)^{n}$$

Short Answer

Expert verified
The first four terms of the sequence are -3, 9, -27, and 81.

Step by step solution

01

Substitute n = 1

Substitute \(n = 1\) into the formula \(a_{n}=(-3)^{n}\) to get the first term. The calculation is: \(a_{1}=(-3)^{1} = -3\).
02

Substitute n = 2

Substitute \(n = 2\) into the formula \(a_{n}=(-3)^{n}\) to get the second term. The calculation is: \(a_{2}=(-3)^{2} = 9\).
03

Substitute n = 3

Substitute \(n = 3\) into the formula \(a_{n}=(-3)^{n}\) to get the third term. The calculation is: \(a_{3}=(-3)^{3} = -27\).
04

Substitute n = 4

Substitute \(n = 4\) into the formula \(a_{n}=(-3)^{n}\) to get the fourth term. The calculation is: \(a_{4}=(-3)^{4} = 81\).

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