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Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$\left(x^{2}+y\right)^{4}$$

Short Answer

Expert verified
\(x^8 + 4x^6y + 6x^4y^2 + 4x^2y^3 + y^4\)

Step by step solution

01

Identify the elements and the power in the binomial

Here, the binomial given is \((x^{2}+y)\) and the power to which it is raised is \(4\). Thus in our binomial theorem, \(a = x^2, b = y, n = 4\).
02

Apply the binomial theorem

Next, we will apply the binomial theorem to expand the binomial expression. The expression becomes: \[\binom{4}{0}(x^2)^4y^0 + \binom{4}{1}(x^2)^3y^1 + \binom{4}{2}(x^2)^2*y^2 + \binom{4}{3}(x^2)^1*y^3 + \binom{4}{4}(x^2)^0*y^4\]. Here \(\binom{4}{k} = \frac{4!}{k!(4-k)!}\) where \( ! \) denotes factorial.
03

Calculate coefficients and simplify the expression

We will calculate the binomial coefficients and simplify each term to get the final expression. The final expression becomes: \(x^8 + 4x^6y + 6x^4y^2 + 4x^2y^3 + y^4\) after calculating coefficients and simplifying.

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