/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Solve the systems. $$\left\\{\... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the systems. $$\left\\{\begin{array}{l} \log _{y} x=3 \\ \log _{y}(4 x)=5 \end{array}\right.$$

Short Answer

Expert verified
The solution of the system is (x, y) = (8, 2).

Step by step solution

01

Conversion to Exponential Form

The first step is to convert these logarithmic equations into their exponential forms. The relationship between logarithmic and exponential forms is: if \( \log_{b} a = c \), then \( b^{c} = a \). Using this relationship, the first equation \( \log_{y} x = 3 \) becomes \( y^{3} = x \), and the second equation \( \log_{y}(4 x) = 5 \) becomes \( y^{5} = 4x \).
02

Substitution

Next, we substitute the value of \( x \) from the first equation into the second equation. That is, we substitute \( y^{3} \) for \( x \) in the equation \( y^{5} = 4x \) to obtain \( y^{5} = 4y^{3} \).
03

Solve for y

In the equation \( y^{5} = 4y^{3} \), we can solve for \( y \) by dividing both sides by \( y^{3} \) (assuming \( y \neq 0 \)), which gives us \( y^{2} = 4 \). The solution for \( y \) is then found by taking the square root of both sides, thus \( y = \sqrt{4} = \pm 2 \). We need to remember that for the logarithmic forms, \( y \) must be positive
04

Solve for x

We then substitute \( y = 2\) into \( y^{3} = x \) to solve for \( x \) to get \( x = 2^{3} = 8 \). Verify this as a solution: it should satisfy both original equations. \( \log_{2} 8 = 3 \) and \( \log_{2}(4 \times 8) = 5 \), therefore (x, y) = (8, 2) is the solution to the system of equations.

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