Chapter 13: Problem 5
In Exercises \(1-10,\) write the standard form of the equation of the circle with the given center and radius. $$\text { Center }(-1,4), r=2$$
Short Answer
Expert verified
The standard form of the equation of the given circle is \( (x + 1)^2 + (y - 4)^2 = 4 \)
Step by step solution
01
Identify the center and radius
From the problem, we have the center of the circle of \((-1,4)\) and the radius of \(2\). Identify the coordinates of the center as \((-h, -k)\) and the radius as \(r\).
02
Substitute the center and radius into the standard form equation
Substitute \(h = -1\), \(k = 4\), and \(r = 2\) into the standard form equation, resulting in \( (x - (-1))^2 + (y - 4)^2 = 2^2 \)
03
Simplify the equation
Simplify the equation to get the standard form of the equation of the circle. The simplified equation becomes \( (x + 1)^2 + (y - 4)^2 = 4\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form of a Circle Equation
The standard form of a circle's equation involves using a format that makes it easy to determine both the center and radius of a circle. This form is essential when working with circles in geometry and algebra. The standard equation is
- \( (x - h)^2 + (y - k)^2 = r^2 \)
- \( (x + 1)^2 + (y - 4)^2 = 4 \)
Center and Radius in Circle Equations
Understanding the center and radius of a circle is crucial when dealing with circle equations. The center \((h, k)\) is a point in the coordinate plane indicating the middle of the circle. It helps in positioning the circle accurately. In practice:
- The center is derived from the expression \((x - h)^2 + (y - k)^2\).
- In our example, \(h = -1\) and \(k = 4\), which means the center is at \((-1, 4)\).
- The equation becomes \(r^2 = 4\).
Geometry Concepts in Circle Equations
Geometry helps us understand how circles are positioned and interact with other geometrical figures. A circle is a set of points equidistant from a center point. A few essential geometry concepts when working with circles are:
- Diameter: This is twice the radius and represents the longest distance across the circle.
- Circumference: This is the perimeter or boundary of the circle.
- Area: This represents the space inside the circle and is calculated as \(\pi r^2\).
Solving Algebra Problems with Circle Equations
Algebra provides the tools to manipulate the circle's equation and solve various problems. When given a circle's equation, you might be tasked with finding specific points, distances, or intersections. Subviews of algebraic problem-solving with circles include:
- Substitution: Inserting known values for coordinates or radius into the equation to find missing values.
- Rearrangement: Adjusting the equation to make it simpler or to extract more straightforward expressions for rapid calculations.
- Factoring: Sometimes necessary when dealing with higher level problems or when intersecting with lines or other circles.