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Solve each system by the substitution method. $$\left\\{\begin{array}{l} x-y=-1 \\ y=x^{2}+1 \end{array}\right.$$

Short Answer

Expert verified
The system of equations has no real solutions.

Step by step solution

01

Express x in terms of y

From equation 1, \(x - y = -1\) , we can express x in terms of y by adding y to both sides. This gives us \(x = y + 1\).
02

Substitute x into the second equation

Now that we have x in terms of y, we can substitute this into the second equation, \(y = x^2 + 1\). After substituting, we have \(y = (y+1)^2 + 1\).
03

Simplify the resulting equation

We now have a quadratic equation in terms of y. We can simplify this by expanding the square and collecting like terms. After simplifying, it becomes \(y = y^2 + 2y + 1 + 1\). When this is rearranged, we find \(0 = y^2 + y + 2\).
04

Solve for y

Unfortunately, the quadratic equation \(y^2 + y + 2 = 0\) has no real roots (you can confirm this by attempting to use the quadratic formula). This tells us that the original system of equations has no real solutions.

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