/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Solve each exponential equation ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$4^{2 x-1}=64$$

Short Answer

Expert verified
The solution to the equation \(4^{2x-1} = 64\) is \(x = 2\).

Step by step solution

01

Rewriting the equation

We start by identifying that \(64\) can be written as \(4^3\). This allows us to rewrite the equation as \(4^{2x-1} = 4^3\).
02

Equating the exponents

Since the bases on both sides of the equation are the same (both are base 4), we can equate the exponents. Therefore, we get \(2x - 1 = 3\).
03

Solving for x

Solving for x, we first add 1 to both sides of the equation, yielding \(2x = 4\). We then divide by 2 on both sides to solve for x, resulting in \(x = 2\).

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