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The function $$N(t)=\frac{30,000}{1+20 e^{-1.5 t}}$$ describes the number of people, \(N(t),\) who become ill with influenza \(t\) weeks after its initial outbreak in a town with \(30,000\) inhabitants. The horizontal asymptote in the graph indicates that there is a limit to the epidemic's growth. (GRAPH CAN'T COPY) a. How many people became ill with the flu when the epidemic began? (When the epidemic began, \(t=0\).) b. How many people were ill by the end of the third week? c. Why can't the spread of an epidemic simply grow indefinitely? What does the horizontal asymptote shown in the graph indicate about the limiting size of the population that becomes ill?

Short Answer

Expert verified
a. Approximately 1429 people fell ill when the epidemic began. b. Approximately 15037 people were ill by the end of the third week. c. The spread of an epidemic can't grow indefinitely due to the finite number of people. The horizontal asymptote in the graph indicates the maximum number of people that can fall ill from the flu, which is the total population in this case.

Step by step solution

01

Determine the initial number of individuals ill

To find the number of individuals who fell ill when the epidemic began, we plug in \(t=0\) into the function \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\). This yields, \(N(0)=\frac{30,000}{1+20 e^{-1.5*0}} = \frac{30,000}{1+20*1} = \frac{30,000}{21} = 1428.57\). It isn't feasible to have a fractional number of individuals, thus we round it to 1429 individuals.
02

Determine the number of individuals ill by the end of third week

To find the number of individuals who fell ill by the end of third week, we plug in \(t=3\) into the function \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\). This yields, \(N(3)=\frac{30,000}{1+20 e^{-1.5*3}} = \frac{30,000}{1+20*0.04979} = \frac{30,000}{1.9958} = 15036.81\). After rounding it off, we get approximately 15037 individuals by the end of third week.
03

Understanding the spread of epidemic

A health epidemic can't grow forever because there is a finite population. In this case, the town has 30,000 inhabitants and that sets the upper limit. The horizontal asymptote in the graph represents a 'limiting value' that the function approaches as \(t\rightarrow \infty\), but never reaches. In this context, it signifies the maximum number of people that can fall ill from the flu, assuming everyone in the town is susceptible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Epidemic Growth
When an epidemic strikes, the rate at which an illness spreads through a population can often be modeled with exponential functions. Initially, the number of cases increases rapidly, as each infected individual can spread the illness to others. However, as more people become ill, this rapid growth begins to slow. This change in growth rate signifies "epidemic growth," which typically shows an S-curve pattern in the graph. This is due to a high initial increase followed by a leveling off. The exponential function in our exercise, \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\), captures this aspect by showing a fast increase in the number of cases at first, which decelerates as it nears the town's entire population. Epidemic growth is vital for understanding and predicting the spread of diseases, enabling public health officials to implement control measures efficiently.
Horizontal Asymptote
In the context of our epidemic function \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\), a horizontal asymptote is a line that the graph approaches but never quite reaches. It represents the maximum potential number of people who could become infected in the town.When we evaluate the function for very large values of \(t\), the exponential term \(e^{-1.5t}\) becomes exceedingly small. This means the denominator in the function approaches 1, and \(N(t)\) approaches 30,000.The horizontal asymptote at 30,000 means that theoretically, if no immunity develops and everyone is susceptible, the entire population could eventually become ill. In reality, external factors such as vaccinations, natural immunity, or medical interventions typically prevent reaching this limit.
Population Modeling
Population modeling is a mathematical framework used to represent the growth of populations under specific conditions. In epidemiological models, like the one in our problem, population modeling helps predict the spread of infectious diseases. The function \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\) is a logistic model, which is suitable for describing how an epidemic spreads within a finite population.
  • **Logistic Functions**: Generally characterized by an S-shaped curve, representing both exponential growth and the eventual tendency toward a carrying capacity or maximum limit.
  • **Parameters**: In this model, the carrying capacity is 30,000, corresponding to the town’s total population.
Population models are crucial for planning and managing resources during an epidemic, helping to predict peak times and healthcare demands, and deciding when interventions should occur.
Limit of a Function
A limit of a function is a fundamental concept in calculus that describes the behavior of a function as the input approaches a certain value. In our epidemic scenario, this concept helps us understand the long-term behavior of the disease's spread in the population. For the function \(N(t)=\frac{30,000}{1+20 e^{-1.5 t}}\), as \(t\) approaches infinity, the exponential component \( e^{-1.5 t} \) approaches zero. Consequently, the expression simplifies, making the function tend to its horizontal asymptote of 30,000.Understanding the limit of the function offers valuable insights: - It highlights that \(N(t)\) will never exceed 30,000, reinforcing that such a trend reflects real-world scenarios where external constraints limit indefinite growth.- This concept is vital in ensuring models are realistic, acknowledging that no population can sustain unchecked exponential growth indefinitely due to finite resources and other natural constraints.

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