Chapter 11: Problem 47
Solve each equation by the method of your choice. Simplify solutions, if possible. $$(2 x-6)(x+2)=5(x-1)-12$$
Short Answer
Expert verified
The solutions to the equation are \( x = (7 + 3i \sqrt{5}) / 4 \) and \( x = (7 - 3i \sqrt{5}) / 4 \).
Step by step solution
01
Expand Both Sides of the Equation
Firstly, use the FOIL method (First, Outer, Inner, Last) to multiply \( (2x-6)(x+2) \). Similarly, multiply 5 with \( (x-1) \). The equation becomes: \( 2x^2+4x-6x-12=5x-5-12 \). This simplifies to \( 2x^2-2x-12=5x-17 \).
02
Rearrange the Equation
Rearrange the equation to move all terms to one side, to form a standard quadratic equation. The equation becomes: \( 2x^2-2x-5x+12+17=0 \). Simplify this to get: \( 2x^2-7x+29=0 \).
03
Factor the Equation
The quadratic equation in the form \( ax^2 + bx + c = 0 \) can be solved by factoring, completing the square or using the quadratic formula. Unfortunately, the equation \(2x^2-7x+29=0\) doesn't factor easily. So we will use the quadratic formula \( x = [ -b \pm \sqrt{b^2 - 4ac}] / (2a) \).
04
Solve for x
Using the quadratic formula with \(a=2\), \(b=-7\), and \(c=29\), the solution for x is \( x = (7 \pm \sqrt{(-7)^2 - 4*2*29}) / (2*2) \). This simplifies to \( x = (7 \pm 3i \sqrt{5}) / 4 \), where \( i^2 = -1 \) represents the imaginary unit.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a universal tool used to find the roots of any quadratic equation. A quadratic equation is of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. The formula itself is given by: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This equation provides two solutions for \( x \), which can be real or complex.
- \( -b \) is the opposite of \( b \), which shifts the parabola horizontally.
- \( \sqrt{b^2 - 4ac} \) is called the discriminant. It determines the nature of the roots.
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, there is exactly one real root.
- If it's negative, the roots are complex, involving imaginary numbers.
FOIL Method
The FOIL method is an acronym that stands for First, Outer, Inner, Last. It's a technique used to multiply two binomials. Let's apply it to the equation from our problem: - \((2x-6)(x+2)\) Using FOIL, we multiply the terms:
- First: Multiply the first terms: \( 2x \cdot x = 2x^2 \).
- Outer: Multiply the outer terms: \( 2x \cdot 2 = 4x \).
- Inner: Multiply the inner terms: \( -6 \cdot x = -6x \).
- Last: Multiply the last terms: \( -6 \cdot 2 = -12 \).
Completing the Square
Completing the square is another method used to solve quadratic equations. The idea is to convert the equation into a perfect square trinomial, making it easier to solve. Here’s a simple explanation of completing the square:
- First, ensure the coefficient of \( x^2 \) is 1. If not, divide through by this coefficient.
- Move the constant term to the right side of the equation.
- Add \( \left( \frac{b}{2} \right)^2 \), where \( b \) is the coefficient of \( x \), to both sides.
- This transforms the left-hand side into a perfect square trinomial \( \left(x + \frac{b}{2}\right)^2 \).
Complex Numbers
Complex numbers arise when solving equations that have no real solutions. They are written in the form \( a + bi \), where \( i \) is the imaginary unit and \( i^2 = -1 \). While real numbers lie on the number line, complex numbers can be visualized as points in a two-dimensional plane.- In the quadratic formula, complex roots occur when the discriminant \( b^2 - 4ac \) is negative. For example, in our equation, the discriminant \( 49 - 232 = -87 \) was negative, which resulted in complex solutions. Thus, the solutions for \( x \) were \( \frac{7 \pm 3i\sqrt{5}}{4} \). In this result:
- The real part is \( \frac{7}{4} \).
- The imaginary part is \( \pm \frac{3i\sqrt{5}}{4} \), where the \( i \) denotes the imaginary component.