Chapter 11: Problem 32
Use the vertex and intercepts to sketch the graph of each quadratic function. Use the graph to identify the function's range. $$f(x)=5-4 x-x^{2}$$
Short Answer
Expert verified
The range of the function is \(-\infty, 7]\).
Step by step solution
01
Locate the vertex of the function
The formula for the x-coordinate of the vertex in a quadratic function is given by \(-b/2a\). In the given function, \(a = -1\) and \(b = -4\). So, it makes the x-coordinate of the vertex \(-(-4)/2*(-1) = -2 \). The y-coordinate is found by subbing -2 back into the original function so the y-coordinate is \(5 - 4(-2) - (-2)^2 = 7\). Hence the vertex is \(-2, 7\).
02
Identify the x-intercepts of the function
To find the x-intercepts, we set \(y = 0\), giving us \(0 = 5 - 4x - x^2 = -x^2 - 4x + 5\). This can be factored as \(-(x - 1)(x - 5) = 0\). This gives us two possible solutions for \(x\), which are \(x = 1\) and \(x = 5\), these are the x-intercepts.
03
Sketch the graph
Using the x-intercepts (1, 0) and (5, 0) and the vertex \(-2, 7\), draw the downward-opening parabola of the function.
04
Identify the range
Examining the graph, we see that the highest point or the 'peak' of the function is the vertex at \(-2, 7\). Since this is a downward-opening parabola, it will extend to negative infinity. Therefore, the range of the function is \(-\infty, 7]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
In any quadratic function of the form \(f(x) = ax^2 + bx + c\), the vertex is a crucial point that represents either the highest or lowest point on the graph, depending on the parabola's orientation. To find the vertex, we use the formula for the x-coordinate: \(-\frac{b}{2a}\). This formula helps us capture the line of symmetry of the parabola.
In our exercise, with \(f(x) = 5 - 4x - x^2\), we have \(a = -1\) and \(b = -4\). Thus, the x-coordinate of the vertex is \(-\frac{-4}{2(-1)} = -2\). By substituting \(x = -2\) back into the function, we determine the y-coordinate to be \(7\). Therefore, the vertex is \((-2, 7)\).
It's essential to know that the vertex \((h, k)\) informs us about the parabola's position and symmetry. For a downward-opening parabola like ours (since \(a < 0\)), the vertex represents the maximum value the function can achieve.
In our exercise, with \(f(x) = 5 - 4x - x^2\), we have \(a = -1\) and \(b = -4\). Thus, the x-coordinate of the vertex is \(-\frac{-4}{2(-1)} = -2\). By substituting \(x = -2\) back into the function, we determine the y-coordinate to be \(7\). Therefore, the vertex is \((-2, 7)\).
It's essential to know that the vertex \((h, k)\) informs us about the parabola's position and symmetry. For a downward-opening parabola like ours (since \(a < 0\)), the vertex represents the maximum value the function can achieve.
X-intercepts
The x-intercepts of a quadratic function are the points where the graph crosses the x-axis. These points are found by setting the function equal to zero and solving for \(x\). The solutions to this equation are the function's x-intercepts.
For the function \(f(x) = 5 - 4x - x^2\), setting it to zero gives us: \(0 = -x^2 - 4x + 5\). By factoring, we find that \( -(x - 1)(x - 5) = 0 \). Solving these, we get the x-intercepts as \(x = 1\) and \(x = 5\). These intercepts correspond to the points \((1, 0)\) and \((5, 0)\) on the graph.
Understanding x-intercepts is vital because they tell us where the parabola crosses the x-axis. This also helps in sketching the graph, as it defines the points where the graph touches or cuts through the axis.
For the function \(f(x) = 5 - 4x - x^2\), setting it to zero gives us: \(0 = -x^2 - 4x + 5\). By factoring, we find that \( -(x - 1)(x - 5) = 0 \). Solving these, we get the x-intercepts as \(x = 1\) and \(x = 5\). These intercepts correspond to the points \((1, 0)\) and \((5, 0)\) on the graph.
Understanding x-intercepts is vital because they tell us where the parabola crosses the x-axis. This also helps in sketching the graph, as it defines the points where the graph touches or cuts through the axis.
Range of a Function
The range of a quadratic function is the set of possible y-values that the function can take. For parabolas, the range largely depends on the vertex and the parabola's orientation (whether it opens upwards or downwards).
In our quadratic function \(f(x) = 5 - 4x - x^2\), which opens downward (because \(a = -1\)), the highest point on the graph is the vertex at \((-2, 7)\). The y-coordinate of the vertex determines the upper limit of the range. Since the parabola opens downward, the function values will go from 7 down to negative infinity.
Therefore, the range of this function is \((-\infty, 7]\). The notation \([\cdot]\) indicates that 7 is included in the range, while \((\cdot)\) signifies that the function continues indefinitely in the indicated direction.
In our quadratic function \(f(x) = 5 - 4x - x^2\), which opens downward (because \(a = -1\)), the highest point on the graph is the vertex at \((-2, 7)\). The y-coordinate of the vertex determines the upper limit of the range. Since the parabola opens downward, the function values will go from 7 down to negative infinity.
Therefore, the range of this function is \((-\infty, 7]\). The notation \([\cdot]\) indicates that 7 is included in the range, while \((\cdot)\) signifies that the function continues indefinitely in the indicated direction.