Chapter 10: Problem 121
Factor: \(64 x^{3}-27 .\) (Section 6.4, Example 8)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 10: Problem 121
Factor: \(64 x^{3}-27 .\) (Section 6.4, Example 8)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
In Exercises \(129-132\), determine if each operation is performed correctly by graphing the function on each side of the equation with your graphing utility. Use the given viewing rectangle. The graphs should be the same. If they are not, correct the right side of the equation and then use your graphing utility to verify the correction. $$\begin{aligned} &(\sqrt{x}-1)(\sqrt{x}-1)=x+1\\\ &[0,5,1] \text { by }[-1,2,1] \end{aligned}$$
Divide: $$\frac{3 x^{2}-12}{x^{2}+2 x-8} \div \frac{6 x+18}{x+4}$$ (Section 7.2, Example 6)
In Exercises \(75-92,\) rationalize each denominator. Simplify, if possible. $$\frac{12}{\sqrt{7}+\sqrt{3}}$$
In Exercises \(105-112,\) add or subtract as indicated. Begin by rationalizing denominators for all terms in which denominators contain radicals. $$\frac{5}{\sqrt{2}+\sqrt{7}}-2 \sqrt{32}+\sqrt{28}$$
In Exercises \(129-132\), determine if each operation is performed correctly by graphing the function on each side of the equation with your graphing utility. Use the given viewing rectangle. The graphs should be the same. If they are not, correct the right side of the equation and then use your graphing utility to verify the correction. $$\begin{aligned} &(\sqrt{x}+1)^{2}=x+1\\\ &[0,8,1] \text { by }[0,15,1] \end{aligned}$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.