Chapter 9: Problem 9
Find the \(x\) -intercepts for the parabola whose equation is given. If the \(x\) -intercepts are irrational numbers, round your answers to the nearest tenth. $$y=x^{2}+2 x-4$$
Short Answer
Expert verified
The \(x\)-intercepts of the given parabola are \(x = 1.2\) and \(x = -3.2\).
Step by step solution
01
Convert given equation
Set \(y\) equal to 0 to convert the equation into quadratic form. This will provide the equation \(0=x^{2}+2x-4\).
02
Apply Quadratic Formula
Rearrange the equation in terms of \(x\) using the quadratic formula, \(x=-b\pm\sqrt{b^2-4ac} / 2a\), where \(a=1\), \(b=2\), and \(c=-4\). Substitution of the given values into the formula gives us \(x= \frac{-2\pm\sqrt{(2)^2-4(1)(-4)}}{2(1)}\).
03
Simplify the square root
Calculate the value under the square root (the discriminant) to get 20. The equation becomes \(x= \frac{-2\pm\sqrt{20}}{2}\).
04
Solve for \(x\)
Simplify and solve for \(x\) to find \(x= -1\pm\sqrt{5}\). These are the exact values, but since we are asked for irrational \(x\)-intercepts to the nearest tenth, we need to further simplify and round our answers.
05
Approximate to Rational Numbers
Approximate to the nearest tenth to get the final solution: \(x = -1 + \sqrt{5}\) is about 1.2 and \(x = -1 - \sqrt{5}\) is about -3.2. Therefore, the \(x\)-intercepts are at \(x = 1.2\) and \(x = -3.2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a unique curve, usually represented on a graph by a quadratic equation, like the one in our exercise, given by \(y = x^2 + 2x - 4\). This function is specifically a type of polynomial equation, which graphically forms a 'U' or an inverted 'U' shape. Understanding the structure of a parabola helps us know the nature of its intercepts and vertices.
A parabola has several distinctive parts that you should know about:
A parabola has several distinctive parts that you should know about:
- Vertex: The turning point of the parabola. In our case, it's influenced by the coefficients of our quadratic equation.
- Axis of Symmetry: A vertical line that passes through the vertex, dividing the parabola into two mirror images.
- Direction: Parabolas can open upwards or downwards depending on the sign of the leading coefficient (\(a\)). For \(y = x^2 + 2x - 4\), since \(a\) is 1, an upward opening is indicated.
- X-intercepts: These points, where the function crosses the x-axis, are our main focus here, requiring us to solve the equation \(x^2 + 2x - 4 = 0\).
Quadratic Formula
The Quadratic Formula is a powerful tool for finding the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). It is expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula derives solutions by calculating the values where the expression equals zero, which determines the x-intercepts of the parabola.
Using the quadratic formula involves several stages:
Using the quadratic formula involves several stages:
- Identify \(a, b,\) and \(c\): These are coefficients from the equation. In our case, \(a = 1\), \(b = 2\), and \(c = -4\).
- Calculate the Discriminant: The expression under the square root, \(b^2 - 4ac\), is vital as it reveals the nature of the roots. A positive discriminant suggests two real roots, a zero indicates one, while a negative predicts complex roots. Here, \((2)^2 - 4(1)(-4) = 20\) means two distinct real roots.
- Apply the Formula: Place the values into the formula to solve for \(x\). For instance, we calculated \(x= \frac{-2 \pm \sqrt{20}}{2}\).
- Simplify: Perform calculations accurately to reach an exact or approximate solution as required.
X-intercepts
X-intercepts are crucial points where the graph of a function touches or crosses the x-axis. In the equation \(y = x^2 + 2x - 4\), finding these intercepts requires setting \(y\) to zero, resulting in a quadratic form that can be solved with the quadratic formula.
When solving for x-intercepts:
When solving for x-intercepts:
- Set the Equation to Zero: Transform the equation to \(x^2 + 2x - 4 = 0\) to identify where the parabola intersects the x-axis.
- Use the Quadratic Formula: Plug into the quadratic formula to find potential roots, which are the x-coordinates of the intercepts.
- Exact and Approximate Solutions: For our example, solving yields exact values \(x = -1 \pm \sqrt{5}\). Further approximation gives the rounded values \(x = 1.2\) and \(x = -3.2\), indicating intercepts on the graph.