Chapter 9: Problem 32
Graph the parabola whose equation is given $$y=x^{2}-4$$
Short Answer
Expert verified
The graph of the function \(y = x^2 - 4\) is a parabola opening upwards, with vertex at (0, -4) and intercepts at x = 2, x = -2 and y = -4.
Step by step solution
01
Identify the type of function and its vertex
The given function \(y = x^2 - 4\) is a quadratic function, and it is in vertex form \(y=a(x-h)^2 + k\), where (h, k) is the vertex of the parabola. In our case, the function can be rewritten as \(y=(x-0)^2 - 4\). Thus the vertex of the parabola is at the point (0, -4).
02
Find the intercepts
To find the x-intercepts, we need to set y=0 in our equation and solve for x: \(0 = x^2 - 4\), and solving it gives \(x = 2\)and \(x = -2\). Thus, our x-intercepts are (2,0) and (-2,0). The y-intercept is found by setting \(x = 0\) in our equation, which gives \(y = -4\), hence, the y-intercept is at (0, -4).
03
Plot the graph
Start by drawing the coordinate axes. Mark the vertex point (0, -4), the x-intercepts (2, 0) and (-2, 0), and y-intercept (0, -4) on the graph. Now, plot the parabola using these points. The parabola opens upwards as the coefficient of \(x^2\) is positive.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola Graphing
Graphing a parabola is an enjoyable way to visualize quadratic functions. A parabola is the u-shaped curve you get when you graph a quadratic equation like \( y = x^2 - 4 \). The most distinctive feature of a parabola is its symmetry about a straight line, known as the axis of symmetry. This specific equation, which is in the standard form \( y = ax^2 + bx + c \), simplifies to \( y = (x-0)^2 - 4 \), meaning the graph is symmetrical about the y-axis.
To graph the parabola, start by pinpointing essential points: the vertex, x-intercepts, and y-intercept. Connect these points with a smooth curved line that reflects the symmetrical nature of parabolas. Since the coefficient of \( x^2 \) is positive, this parabola opens upwards. Finding these key characteristics helps in accurately sketching the graph.
To graph the parabola, start by pinpointing essential points: the vertex, x-intercepts, and y-intercept. Connect these points with a smooth curved line that reflects the symmetrical nature of parabolas. Since the coefficient of \( x^2 \) is positive, this parabola opens upwards. Finding these key characteristics helps in accurately sketching the graph.
Vertex of a Parabola
The vertex of a parabola is a pivotal point on its graph. It represents the highest or lowest point, depending on the direction the parabola opens. In the equation \( y = x^2 - 4 \), the vertex form is already revealed as \( y = (x-0)^2 - 4 \), indicating that the vertex is at \( (0, -4) \).
The vertex provides crucial information:
The vertex provides crucial information:
- It tells us the minimum point of the parabola since the graph opens upwards.
- It also indicates the parabola's line of symmetry, which is the vertical line \( x=0 \) in this case.
X-Intercepts
The x-intercepts of a parabola are the points where the graph crosses the x-axis. To find these intercepts, we set \( y=0 \) in the equation \( y = x^2 - 4 \) and solve for \( x \). This gives:
- \( 0 = x^2 - 4 \)
- \( x^2 = 4 \)
- \( x = \pm 2 \)
Y-Intercepts
The y-intercept of a parabola is the point where the graph meets the y-axis. This is easily found by setting \( x = 0 \) in the equation. For \( y = x^2 - 4 \), substituting gives:
- \( y = (0)^2 - 4 \)
- \( y = -4 \)