/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Solve each quadratic equation by... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each quadratic equation by the square root property. If possible, simplify radicals or rationalize denominators. $$3 x^{2}-5=0$$

Short Answer

Expert verified
The solutions are x = \(+\sqrt{\frac{5}{3}}\) and x = \(-\sqrt{\frac{5}{3}}\)

Step by step solution

01

Rearranging the Equation

Firstly, add 5 to both sides to move the -5 from the left side of the equation. This will give you the equation \(3x^{2}=5\).
02

Getting x Squared Alone

Next, divide both sides of the equation by 3 to isolate \(x^{2}\) on one side. This will give the equation \(x^{2} = \frac{5}{3}\).
03

Isolating x

Lastly, take the square root of both sides to solve for x. Remember, there are two possible solutions: x = \(+\sqrt{\frac{5}{3}}\) and x = \(-\sqrt{\frac{5}{3}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Solving quadratic equations is a fundamental skill in algebra that allows us to find the values of an unknown variable that make the equation true. Quadratics are polynomial equations of degree 2, generally written in the form of \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. The square root property is a useful method for solving quadratics when the equation is in the form \(ax^2 = c\).

To use the square root property, as shown in the textbook exercise, we first isolate the squared term by getting \(x^2\) alone on one side of the equation. Once we have \(x^2 = \) (some value), we take the square root of both sides, being careful to consider both the positive and negative square roots, since \((\pm \sqrt{x})^2 = x\). It's vital to remember to include both roots, as each represents a possible solution to the original equation.
Simplifying Radicals
Upon solving the quadratic using the square root property, students will often encounter radicals, which are expressions that indicate the root of a number. The most common radical found in quadratics is the square root. Simplifying radicals involves finding an equivalent expression where the radical has the simplest possible form.

Breaking down Radicals

To simplify a radical, look for perfect square factors. For example, if you have \(\sqrt{50}\), you can break this down into \(\sqrt{25 \cdot 2}\), which simplifies to \(5\sqrt{2}\). This process makes it easier to work with the radical by reducing it to its simplest form, which can be particularly helpful if you need to add, subtract, or multiply these expressions with other radicals or integrate them into more complex equations.
Rationalizing Denominators
Radicals in the denominator of a fraction can be perplexing, which is why rationalizing the denominator is necessary. This process involves altering the expression so that the denominator is a rational number.

For instance, if we have \(\frac{1}{\sqrt{3}}\), we can multiply both the numerator and the denominator by \(\sqrt{3}\) to eliminate the radical from the denominator, resulting in \(\frac{\sqrt{3}}{3}\). This maneuver does not change the value of the expression but makes it more palatable for further operations. When rationalizing the denominator, the main goal is to ensure that there are no radicals left in the denominator, enabling easier addition and subtraction of fractions and a clearer understanding of their value.
Isolating Variables in Algebra
Isolating variables is a technique used to find the value of an unknown in an algebraic expression. This is a crucial step in solving equations, including quadratic equations, and serves as a foundational skill in all of algebra.

The process involves using arithmetic operations: addition, subtraction, multiplication, division, and taking roots, to get the variable alone on one side of the equation. For example, the exercise began by rearranging the equation to isolate \(x^2\). At its essence, algebra is about maintaining balance. Whatever operation you perform on one side of the equation, you must also perform on the other side to keep the equation equal. Being adept at isolating variables not only helps solve basic equations but also aids in comprehending more complex algebraic concepts and systems of equations.

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Most popular questions from this chapter

Will help you prepare for the material covered in the next section. $$\text { Factor: } x^{2}+8 x+16$$

a. Use a graphing utility to graph \(y=2 x^{2}-82 x+720\) in a standard viewing rectangle. What do you observe? b. Find the coordinates of the vertex for the given quadratic equation. c. The answer to part (b) is \((20.5,-120.5) .\) Because the leading coefficient, 2 of \(y=2 x^{2}-82 x+720\) is positive, the vertex is a minimum point on the graph. Use this fact to help find a viewing rectangle that will give a relatively complete picture of the parabola. With an axis of symmetry at \(x=20.5,\) the setting for \(x\) should extend past this, so try Xmin \(=0\) and \(\mathrm{Xmax}=30 .\) The setting for \(y\) should include (and probably go below) the \(y\) -coordinate of the graph's minimum point, so try Ymin \(=-130 .\) Experiment with Ymax until your utility shows the parabola's major features. d. In general, explain how knowing the coordinates of a parabola's vertex can help determine a reasonable viewing rectangle on a graphing utility for obtaining a complete picture of the parabola.

Write 0.00397 in scientific notation.

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