Chapter 8: Problem 4
Solve each radical equation. $$\sqrt{x}-9=0$$
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Chapter 8: Problem 4
Solve each radical equation. $$\sqrt{x}-9=0$$
These are the key concepts you need to understand to accurately answer the question.
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In Exercises \(94-97,\) determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\frac{3 \sqrt{x}}{x \sqrt{6}}=\frac{\sqrt{6 x}}{2 x} \text { for } x>0$$
Without using a calculator and knowing that \(\sqrt{2} \approx 1.4142\) rationalizing the denominator of \(\frac{1}{\sqrt{2}}\) makes division to obtain a decimal approximation for \(\frac{1}{\sqrt{2}}\) easier to perform. Because 10 and 8 share a common factor of \(2,\) I simplified \(\frac{\sqrt{10}}{8}\) to \(\frac{\sqrt{5}}{4}\)
Simplify by first writing the expression in radical form. If applicable, use a calculator to verify your answer. $$(-64)^{-\frac{2}{3}}$$
In Exercises \(75-82\), rationalize each denominator. Simplify, if possible $$\frac{\sqrt{2}}{\sqrt{3}}+\frac{\sqrt{3}}{\sqrt{2}}$$
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$81^{\frac{1}{4}} \cdot 125^{\frac{1}{3}} \text { is an integer. }$$
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