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Multiply as indicated. $$\left(y^{2}-16\right) \cdot \frac{3}{y-4}$$

Short Answer

Expert verified
The simplified form of the given expression is \(3(y + 4)\)

Step by step solution

01

Identify and factorize perfect squares

In this expression, \(y^{2}-16\) is a difference of squares as 16 is a perfect square. Difference of squares can be factorized as \((a+b)(a-b)\). So, \(y^{2} - 16\) can be factorized as \((y - 4)(y + 4)\).
02

Replace the original expression

Replace the expression \(y^{2}-16\) in the original expression with its factorized form which gives \((y - 4)(y + 4) \cdot \frac{3}{y - 4}\)
03

Simplify the expression

Here, we can directly cancel the same term \((y - 4)\) in the numerator and the denominator which results in \((y + 4) \cdot 3\).
04

Write the final result

Rearrange the expression to get the final form, which is \(3(y + 4)\).

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