/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 Determine whether each statement... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\frac{2}{x}+1=\frac{2+x}{x}, x \neq 0$$

Short Answer

Expert verified
The given statement is true.

Step by step solution

01

Evaluate the Left Side

The left side of the equation is \( \frac{2}{x} + 1 \). It cannot be simplified any further. Therefore, the expression for the left side remains \( \frac{2}{x} + 1 \).
02

Evaluate the Right Side

The right side of the equation as it appears is \( \frac{2+x}{x} \). To simplify it in order to match the format of the left side, divide each term in the numerator by the denominator. The right side becomes \( \frac{2}{x} + \frac{x}{x} \). The expression \( \frac{x}{x} \) simplifies to 1. Therefore, the simplified expression for the right side becomes \( \frac{2}{x} + 1 \).
03

Compare the Left and Right Sides

Both sides of the equation have been simplified to \( \frac{2}{x} + 1 \). This shows that the equation is correct. Therefore, the statement is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.