Chapter 5: Problem 91
Use a vertical format to find each product. $$\begin{array}{l}x^{2}+7 x-3 \\\x^{2}-x-1 \\\\\hline\end{array}$$
Short Answer
Expert verified
The product of the two polynomials \(x^{2}+7x-3\) and \(x^{2}-x-1\) is \(x^{4}+6x^{3}+3x^{2}-10x+3\).
Step by step solution
01
Distribute Terms
First, distribute each term in the first polynomial to every term in the second polynomial. That is, calculate:\(x^{2} \cdot x^{2}\), \(x^{2} \cdot -x\), \(x^{2} \cdot -1\), \(7x \cdot x^{2}\), \(7x \cdot -x\), \(7x \cdot -1\), \(-3 \cdot x^{2}\), \(-3 \cdot -x\), and \(-3 \cdot -1\).
02
Combine Like Terms
Next, sum up all the products. Group together the terms that have the same power of x, and finally write out the result in descending power of x.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Multiplication
Polynomial multiplication is a critical concept in algebra that involves combining two polynomials to produce a new polynomial. It operates under the same principles as multiplying numbers, but here, we are dealing with expressions that include variables raised to various powers. Imagine you have two polynomials, such as a quadratic (a second-degree polynomial) and another of the same degree. When you multiply them, you should expect to get a polynomial of degree four—that's because the highest degree terms, when multiplied, determine the degree of the resulting polynomial.
For instance, let’s watch the process unfold in the exercise given: We multiply every term of the first polynomial, \(x^{2}+7x-3\), by each term of the second polynomial, \(x^{2}-x-1\). This leads to a series of multiplications, each producing a term that contributes to the final, expanded polynomial. It's like piecing together a puzzle where each product is a piece that fits into the bigger picture.
For instance, let’s watch the process unfold in the exercise given: We multiply every term of the first polynomial, \(x^{2}+7x-3\), by each term of the second polynomial, \(x^{2}-x-1\). This leads to a series of multiplications, each producing a term that contributes to the final, expanded polynomial. It's like piecing together a puzzle where each product is a piece that fits into the bigger picture.
Distributive Property
The distributive property is a cornerstone of polynomial multiplication. It allows us to evenly distribute a multiplication operation over addition or subtraction within parentheses. In simple terms, it shows us, algebraically, how to ‘share out’ or ‘distribute’ a multiplier across different terms.
Applying this property in our exercise, we take each term from the first polynomial and multiply it by every term in the second polynomial. This is done systematically, so for example, the term \(x^{2}\) 'visits' every term in the second polynomial: \(x^{2} \times x^{2}\), \( (x^{2} \times -x)\), and \( (x^{2} \times -1)\). This method ensures that no term is left behind, and each multiplication is accounted for.
Applying this property in our exercise, we take each term from the first polynomial and multiply it by every term in the second polynomial. This is done systematically, so for example, the term \(x^{2}\) 'visits' every term in the second polynomial: \(x^{2} \times x^{2}\), \( (x^{2} \times -x)\), and \( (x^{2} \times -1)\). This method ensures that no term is left behind, and each multiplication is accounted for.
Combining Like Terms
Once you've multiplied the terms across polynomials using the distributive property, you’ll often find you have terms that are similar—these are called 'like terms'. Like terms are those that have the exact same variables raised to the same power, though they might have different coefficient numbers.
After distributing and multiplying in our given example, the next step is to combine these like terms. This means adding or subtracting the coefficients of terms that have the same power of \(x\). Doing so simplifies the expression and makes it much easier to understand and work with. It’s an essential step in reaching the most compact form of the polynomial, contributing towards a tidy and correct solution.
After distributing and multiplying in our given example, the next step is to combine these like terms. This means adding or subtracting the coefficients of terms that have the same power of \(x\). Doing so simplifies the expression and makes it much easier to understand and work with. It’s an essential step in reaching the most compact form of the polynomial, contributing towards a tidy and correct solution.
Vertical Format Multiplication
The vertical format multiplication method offers a structured approach to multiplying polynomials—think back to how you might have multiplied numbers in grade school. We simply write one polynomial above the other, align the terms with similar degrees, and draw a line underneath. Then, we proceed to distribute each term of the upper polynomial across the terms of the lower polynomial, one at a time, writing down the results in rows.
In the exercise we're investigating, we've used this exact approach. After each distribution, we write the product underneath, aligning like degrees of \(x\). Finally, like in traditional multiplication, we add down the columns, combining like terms. This approach ensures systematic processing and minimizes error during multiplication. It's a neat, visual way to track each step and appreciate the build-up towards the solution.
In the exercise we're investigating, we've used this exact approach. After each distribution, we write the product underneath, aligning like degrees of \(x\). Finally, like in traditional multiplication, we add down the columns, combining like terms. This approach ensures systematic processing and minimizes error during multiplication. It's a neat, visual way to track each step and appreciate the build-up towards the solution.