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Find each product. In each case, neither factor is a monomial. $$(y-3)\left(y^{2}-3 y+4\right)$$

Short Answer

Expert verified
The product of \( (y-3) \left(y^{2}-3 y+4\right) \) is \( y^{3} - 6y^{2} + 13y - 12 \).

Step by step solution

01

Expand the Expression

The first set of terms is \( (y-3) \) and the second set of terms is \( \left(y^{2}-3 y+4\right) \). To solve this, each term in the first set of parenthesis should be multiplied by each term in the second set, resulting in: \( y(y^{2}-3 y+4) - 3(y^{2}-3 y+4) \).
02

Distribute the Terms

Multiply \( y \) through \( y^{2}-3 y+4 \) and \( 3 \) through the same set. This gives us: \( y^{3} - 3y^{2} + 4y - 3y^{2} + 9y - 12 \).
03

Combine Like Terms

Combine the terms that have the same powers of \( y \). Identifying these and combining them gives us a result of \( y^{3} - 6y^{2} + 13y - 12 \).

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