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Find each product. In each case, neither factor is a monomial. $$(x-12)(x+8)$$

Short Answer

Expert verified
The product of the two binomials is \(x^2 -4x -96\).

Step by step solution

01

Distribute \(x\)

Distribute \(x\) from the first binomial to both terms in the second binomial. This gives \(x(x) + x(8) = x^2 + 8x\).
02

Distribute \(-12\)

Distribute \(-12\) from the first binomial to both terms in the second binomial. This gives \(-12(x) -12(8) = -12x - 96\).
03

Combine Similar Terms

Combine the expressions obtained in Step 1 and Step 2. This gives \(x^2 + 8x -12x - 96 = x^2 -4x -96\) .

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