/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Simplify each exponential expres... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify each exponential expression. Assume that variables represent nonzero real numbers. $$\left(\frac{6 x^{7}}{2 x^{2}}\right)^{-4}$$

Short Answer

Expert verified
The simplified form of the given exponential expression is \(\frac{1}{3^4x^{20}}\) or \(\frac{1}{81x^{20}}\)

Step by step solution

01

Simplify the inner fraction

First, simplify the fraction inside the parenthesis. Divide 6 by 2 to get 3, and subtract the exponent of \(x^2\) from the exponent of \(x^7\) to get \(x^5\). So, the inside of the parenthesis simplifies to \(3x^5\). Our equation now looks like this: \((3x^{5})^{-4}\)
02

Apply the negative exponent rule

The negative exponent rule states that \((a^{-n}) = \frac{1}{a^n}\). So, applying this rule, our expression becomes: \(\frac{1}{(3x^{5})^4}\)
03

Apply the power of a quotient rule

The power of a quotient rule states that \((\frac{a}{b})^n = \frac{a^n}{b^n}\). So, applying this rule, we get: \(\frac{1^4}{(3x^{5})^4} = \frac{1}{3^4x^{20}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Exponent Rule
When dealing with exponential expressions, the negative exponent rule is a fundamental concept that students must master. In essence, it states that any non-zero base raised to a negative exponent is equal to the inverse of the base raised to the positive of that exponent. Mathematically, if you have an expression of the form \(a^{-n}\), where \(a\) is a non-zero real number and \(n\) is a positive integer, it can be rewritten as \(\frac{1}{a^n}\).

Applying this in our textbook exercise, when you see \((3x^{5})^{-4}\), it might seem confusing at first glance. However, with the negative exponent rule, it is simply a matter of writing the reciprocal of the base raised to the positive exponent: \(\frac{1}{(3x^{5})^4}\), moving the entire expression from the numerator to the denominator and flipping the sign of the exponent from negative to positive. This is a critical step in simplifying expressions and also plays a vital role in solving more complex algebraic equations.
Power of a Quotient Rule
The power of a quotient rule is another key principle in managing exponential expressions, particularly when a fraction is involved. This rule allows us to distributively apply the exponent to both the numerator and the denominator separately. To put it simply, if you have a fraction \(\frac{a}{b}\) raised to an exponent \(n\), then each term in the fraction is raised to the power \(n\), giving us \(\frac{a^n}{b^n}\).

Considering our exercise example, after applying the negative exponent rule, we face the expression \(\frac{1}{(3x^{5})^4}\). Now we can apply the power of a quotient rule; we raise both 3 and \(x^5\) in the denominator to the fourth power, resulting in \(\frac{1^4}{3^4x^{20}}\). It's important to note that while \(1^4\) simply equals 1, raising a power to a power, such as \(x^{5}\) to the 4th power, involves multiplying the exponents (5 times 4), which gives us \(x^{20}\), effectively applying the rule to simplify the expression.
Exponent Subtraction
In the realm of exponential expressions, exponent subtraction comes into play when dividing like bases. According to the laws of exponents, when you divide powers with the same base, you subtract the exponents: \(a^m \div a^n = a^{m-n}\). This effectively reduces the expression by cancelling out common factors.

In the initial step of our example from the textbook, we start with \(\frac{6x^7}{2x^2}\). Before we can simplify using the quotient rule, we subtract the exponents of \(x\) terms because they share the same base, resulting in \(x^{7-2}\) which simplifies to \(x^5\). It's essential to accurately apply exponent subtraction as this sets up the problem for further simplification using the aforementioned rules and brings us closer to the solution. This operation vastly reduces the complexity of expressions, paving the way for the application of additional rules, like the negative exponent and power of a quotient rule, to simplify the expressions further.

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