/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Solve each equation using the ad... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each equation using the addition property of equality. Be sure to check your proposed solutions. $$13-3 r+2+6 r-2 r-1=3+2 \cdot 9$$

Short Answer

Expert verified
The solution to the equation is \( r = 7 \).

Step by step solution

01

Simplify Both Sides

Combine like terms on both sides of the equation: \( 13 - 3r + 2 + 6r - 2r - 1 = 3 + 2\cdot9 \) simplify to \( r + 14 = 21 \).
02

Perform Addition Property of Equality to Isolate \( r \)

To isolate the \( r \) term, subtract 14 from both sides of the equation. This will give: \( r = 21 - 14 \).
03

Calculate the Value of \( r \)

Now, calculate the value of \( r \) from the equation in Step 2: \( r = 7 \).
04

Check Proposed Solution

Substitute \( r = 7 \) into the original equation to verify if the equation holds true. If it does, then the solution for \( r \) is correct. If not, recheck the steps.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Algebraic Equations
When faced with an algebraic equation, the ultimate goal is to find the value of the unknown variable that makes the equation true. The process usually involves several stages including simplifying expressions, performing operations equally on both sides, and keeping the equation balanced. It's crucial to work methodically, ensuring that each step sets the stage for the next, ultimately leading to a solution.
To illustrate, consider the equation from our exercise: \(13-3r+2+6r-2r-1=3+2\cdot9\). The initial step involves simplifying both sides by combining like terms—those with the same variable or constant—followed by applying properties of equality, such as the addition property, to isolate and solve for the unknown variable. The path to the solution is paced by logic and the structural rules of algebraic operations.
Combining Like Terms
Combining like terms is a method of simplification in algebra. Like terms are terms that have exactly the same variable raised to the same power. Only the coefficients of like terms are different, and it is the coefficients that you combine.
  • To combine like terms, sum up or subtract their coefficients.
  • This simplification makes the equation more manageable.
  • In the exercise, we combined terms with \(r\) and constants separately: \(-3r + 6r - 2r\) simplifies to \(r\), and \(13 + 2 - 1\) simplifies to \(14\).
Understanding how to combine like terms effectively is crucial for solving equations neatly and efficiently.
Isolating Variables
The step of isolating the variable is where we manipulate the equation to have the variable on one side and the constants on the other. This is often done through the addition or subtraction property of equality, which states that you can add or subtract the same number from both sides of the equation without changing its solution.
  • In our exercise, we subtracted 14 from both sides to isolate \(r\): \(r + 14 - 14 = 21 - 14\).
  • This simplification yields the isolated variable: \(r = 7\).
Isolating the variable is a pivotal step, as it unveils the solution to the equation, which is the value of the unknown variable.
Checking Solutions in Algebra
After solving an equation and obtaining a proposed solution, it's essential to verify its correctness. Checking the solution involves plugging the value of the variable back into the original equation and seeing if it results in a true statement.
  • In our example, substituting \(r = 7\) back into the original equation checks if the left-hand side equals the right-hand side.
  • If both sides are equal, the solution is confirmed to be correct.
  • If not, it indicates there may have been an error in the process which needs revisiting.
This final step is a good practice to ensure the integrity of your solution and reinforce your understanding of how to solve algebraic equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An elevator at a construction site has a maximum capacity of 3000 pounds. If the elevator operator weighs 245 pounds and each cement bag weighs 95 pounds, how many bags of cement can be safely lifted on the elevator in one trip?

According to the American Bureau of Labor Statistics, you will devote 37 years to sleeping and watching TV. The number of years sleeping will exceed the number of years watching TV by 19. Over your lifetime, how many years will you spend on each of these activities?According to the American Bureau of Labor Statistics, you will devote 32 years to sleeping and eating. The number of years sleeping will exceed the number of years eating by 24 Over your lifetime, how many years will you spend on each of these activities?

Let \(x\) represent the number. Use the given conditions to write an equation. Solve the equation and find the number. A number decreased by 23 is equal to \(214 .\) Find the number.

Let \(x\) represent the number. Use the given conditions to write an equation. Solve the equation and find the number. The product of 8 and a number is \(272 .\) Find the number.

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. Membership in a fitness club costs 500 dollars yearly plus 1 dollars per hour spent working out. A competing club charges 440 dollars yearly plus 1.75 dollars per hour for use of their equipment. How many hours must a person work out yearly to make membership in the first club cheaper than membership in the second club?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.