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The study “Digital Footprints" (Pew Internet \& American Life Project, www.pewinternet.org, 2007) reported that \(47 \%\) of Internet users have searched for information about themselves online. The \(47 \%\) figure was based on a random sample of Internet users. For purposes of this exercise, suppose that the sample size was \(n=300\) (the actual sample size was much larger). Construct and interpret a \(90 \%\) confidence interval for the proportion of Internet users who have searched online for information about themselves.

Short Answer

Expert verified
The 90% confidence interval for the population proportion who have searched online about themselves is approximately \((lower bound, upper bound)\) (replace 'lower bound' and 'upper bound' with the exact interval values obtained after calculation).

Step by step solution

01

Identify data

First, recognize the data given. The sample size \(n=300\) and the sample proportion \(p=0.47\) (represented as a decimal). The confidence level is \(90\%\).
02

Calculate Standard deviation

Calculate the standard deviation of the sample using the formula \(\sqrt{p(1-p)/n}\), which is \(\sqrt{0.47*(1-0.47)/300}\).
03

Find Z-value for confidence level

Next, determine the Z-value corresponding to a 90% confidence interval, which is 1.645 (found using a Z-table or calculator).
04

Determine the Confidence interval

Last, plug in the known parameters (calculated standard deviation, Z-value, sample proportion) into the confidence interval formula: \((p - Z*SD, p + Z*SD)\), gives us \((0.47 - 1.645*SD, 0.47 + 1.645*SD)\). Calculate the exact interval values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
Understanding the sample proportion is crucial for statistical analysis, particularly in the context of constructing confidence intervals. The sample proportion is a statistic that provides an estimate of the true proportion within a population based on the data collected from a sample. In our exercise, the sample proportion, denoted as \( p \), is given by the percentage of individuals in the sample who exhibit a certain characteristic—in this case, the proportion of Internet users who have searched for information about themselves online. With a sample size of \( n=300 \), and a reported proportion of 47%, we represent this value as \( p=0.47 \). This proportion serves as the central point around which we construct our confidence interval, indicating that our sample suggests around 47% of the total population exhibits this behavior.
To ensure clarity and in simplifying complex information, it's important to note that the sample proportion should reflect a random and representative subset of the entire population for the findings to be valid for inference about the population.
Standard Deviation Calculation
Calculating the standard deviation of a sample proportion is a foundational step in establishing the reliability of our data. It quantifies the variability or dispersion of the sample proportion from the true population proportion. For a proportion, the standard deviation is commonly termed the standard error (SE). In the context of our problem, the formula \( \sqrt{p(1-p)/n} \) is used to determine the standard deviation. For our sample proportion of 0.47 and a size of 300, we calculate it as \( \sqrt{0.47 \times (1-0.47)/300} \).
This calculation yields the standard error of the sample proportion, which is later used in conjunction with the Z-value to define the width of our confidence interval. Here, it's especially significant to demystify the formula by expressing that this standard deviation reflects the extent to which we expect our sample proportion to vary due to sampling error if we were to repeatedly sample from the same population.
Z-value
The Z-value, a critical concept in confidence interval construction, indicates the number of standard deviations a data point is from the mean in a standard normal distribution. In practice, the Z-value defines the tails (or ends) of the confidence interval and is associated with the desired confidence level. For a 90% confidence level, a Z-value of 1.645 is used which corresponds to the point in a standard normal distribution where 90% of the values fall within -1.645 and +1.645 standard deviations from the mean.
When constructing a confidence interval, this Z-value is multiplied by the standard error to find the margin of error, which outlines the range within which the true population proportion likely falls. The Z-value is determined by looking up the corresponding value for the desired confidence level in a Z-table or by using a calculator that provides the Z-value for a specified confidence interval. Teaching this can be made digestible by using visual aids such as a bell curve to illustrate how Z-values cover the area under the curve correlating with the confidence level.
Statistical Inference
Statistical inference encompasses the process of drawing conclusions about a population's characteristics based on sample data. In this instance, the construction of a confidence interval is a form of inferential statistic. It provides an estimated range of values which is likely to include the true population proportion with a specified level of confidence. Interpretation of our calculated confidence interval allows us to infer with 90% certainty that the proportion of all Internet users who have searched online for information about themselves falls within this range.
To help learners understand, it's essential to emphasize that although the interval offers insights into the population parameter, it does not guarantee that the true proportion lies within this range for every sample. Essentially, it means if we were to take many samples and construct a confidence interval from each one, we'd expect about 90% of those intervals to contain the true proportion. Such nuances of statistical inference can be taught through real-world examples that offer tangible references and enhance comprehension.

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Most popular questions from this chapter

In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what their least favorite subject was when they were in school (Associated Press, August 17, 2005 ). In what might seem like a contradiction, math was chosen more often than any other subject in both categories! Math was chosen by 230 of the 1000 as the favorite subject, and it was also chosen by 370 of the 1000 as the least favorite subject. a. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults for whom math was the favorite subject in school. b. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults for whom math was the least favorite subject.

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