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Suppose that \(25 \%\) of the fire alarms in a large city are false alarms. Let \(x\) denote the number of false alarms in a random sample of 100 alarms. Give approximations to the following probabilities: a. \(P(20 \leq x \leq 30)\) b. \(\quad P(20

Short Answer

Expert verified
The solutions for each sub-part of the exercise are as follows: a. The approximate probability that 20 <= x <= 30 is 0.71. b. The approximate probability that 20 < x < 30 is 0.69. c. The approximate probability that x >= 35 is approximately 0.046. d. The approximate probability that x deviates more than 2 standard deviations from its expected value is 0.05.

Step by step solution

01

Calculation of mean and standard deviation

Calculate the mean and standard deviation using the formulae provided. Here n=100 (number of trials) and p=0.25 (probability of a false alarm).
02

Calculate z-scores

Calculate the z-scores for the x values indicated in each sub-problem. The z-score can be calculated using the formula \( z = (x - \mu) / \sigma \). Adjust for continuity correction by subtracting or adding 0.5 where necessary.
03

Lookup in z-table

Sketch the normal curve and mark the z-scores calculated on the graph, then look up the corresponding values in the standard z-score table.
04

Calculate the probabilities

Use these z-scores to calculate the probabilities asked in the problem. For ranges (a and b), subtract the z values; for the greater than or less than values (c), use 1 - z or simply z; and for d, calculate the z scores for the mean +/- 2*standard deviation, and subtract the two corresponding probabilities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

False Alarms
In our scenario, a false alarm refers to a situation where a fire alarm is triggered even though there is no fire. In the context of probability and statistics, we're estimating how often this might happen in a sample. With fire alarms in a large city, the data tells us that 25% of alarms are usually false. This percentage is what we call the probability, denoted as \( p = 0.25 \).
So, in a random sample of 100 alarms, you'd expect about 25 of them to be false alarms due to this probability rate. This lays the foundation for calculating further probabilities of false alarms in different scenarios.

Understanding false alarms is crucial for managing risk and ensuring that resources are efficiently used. If too many alarms are false, it might lead to complacency or wastage of emergency services.
Probability Calculation
Calculating probabilities involves determining the likelihood of an event—in this case, a certain number of false alarms. With a sample size of 100, we use the binomial distribution as our starting point because it's perfect for "success-failure" situations like false alarms.
The mean \( \mu \) of this distribution is given by the formula \( \mu = np \), where \( n \) is the number of trials and \( p \) is the probability of success (false alarm). So, \( \mu = 100 \times 0.25 = 25 \).
The standard deviation \( \sigma \), which we'll discuss later, is crucial for understanding how spread out these probabilities are. Once you've calculated \( \mu \) and \( \sigma \), you can use z-scores and tables to find the specific probabilities of interest.

Probability calculations help us quantify uncertainty, providing a clear picture of likely outcomes.
Z-Scores
Z-scores are a powerful tool in statistics. They help us understand where a data point stands relative to the mean. In our exercise, z-scores convert our binomial distribution problem into a normal distribution problem.
To calculate a z-score, we use: \( z = \frac{x - \mu}{\sigma} \). Here, \( x \) is the observed value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. For the continuity correction, necessary in binomial-to-normal approximation, we add or subtract 0.5 to \( x \) as appropriate.
By calculating z-scores for our range of interest, we can easily look them up in a z-table to find probabilities. This transformation makes heavy probability calculations simpler and more intuitive.

Understanding z-scores enhances our ability to interpret data, making it a cornerstone in statistical analysis.
Standard Deviation
Standard deviation \( \sigma \) is a measure of how spread out the numbers are in a data set. It’s essential for understanding how much variation from the mean exists. In the context of our false alarms exercise, it tells us how much the number of false alarms is likely to vary around the average.
The formula for standard deviation in a binomial distribution is \( \sigma = \sqrt{np(1-p)} \). For our alarms, this works out to \( \sigma = \sqrt{100 \times 0.25 \times (1 - 0.25)} = \sqrt{18.75} \approx 4.33 \).
Knowing this, we can calculate probabilities about how likely we are to be a certain distance from the mean, such as being two standard deviations away. This gives insight into the reliability and predictability of our false alarm data.

Standard deviation is key in summarizing data variability, offering insights into its consistency and stability.

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Most popular questions from this chapter

Let \(z\) denote a variable that has a standard normal distribution. Determine the value \(z^{*}\) to satisfy the following conditions: a. \(\quad P\left(zz^{*}\right)=.02\) e. \(\quad P\left(z>z^{*}\right)=.01\) f. \(\quad P\left(z>z^{*}\right.\) or \(\left.z<-z^{*}\right)=.20\)

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