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A radio station that plays classical music has a "by request" program each Saturday evening. The percentages of requests for composers on a particular night are as follows: $$ \begin{array}{lr} \text { Bach } & 5 \% \\ \text { Beethoven } & 26 \% \\ \text { Brahms } & 9 \% \\ \text { Dvorak } & 2 \% \\ \text { Mendelssohn } & 3 \% \\ \text { Mozart } & 21 \% \\ \text { Schubert } & 12 \% \\ \text { Schumann } & 7 \% \\ \text { Tchaikovsky } & 14 \% \\ \text { Wagner } & 1 \% \end{array} $$ Suppose that one of these requests is to be selected at random. a. What is the probability that the request is for one of the three B's (Bach, Beethoven, or Brahms)? b. What is the probability that the request is not for one of the two \(S^{\prime}\) s? c. All of the listed composers wrote at least one symphony except Bach and Wagner. What is the probability that the request is for a composer who wrote at least one symphony?

Short Answer

Expert verified
a. The probability that the request is for one of the Bach, Beethoven, or Brahms is 40%. b. The probability that the request is not for one of the two S's (Schubert, Schumann) is 81%. c. The probability that the request is for a composer who wrote at least one symphony is 94%.

Step by step solution

01

Solution for Part a

For Bach, Beethoven, and Brahms, the probabilities are 5%, 26%, and 9% respectively. Adding these probabilities gives the probability that the request is for one of the three B's. Following the addition rule in Probability, \(P(Bach, Beethoven, Brahms)= P(Bach) + P(Beethoven) + P(Brahms)\) which is \(5\% + 26\% + 9\%= 40\%.\)
02

Solution for Part b

The probabilities for Schubert and Schumann are 12% and 7% respectively. Adding these gives the combined probability of the requests for these two composers. The complement probability can be calculated as 1 minus the combined probability of Schubert and Schumann, in percentage. Following the rule for complement in Probability, \(P(not Schubert, Schumann)= 1 - P(Schubert, Schumann)= 1 - 19\% = 81\%.\)
03

Solution for Part c

From the question, only Bach and Wagner did not write at least one symphony. Their probabilities are 5% and 1% respectively. The probability of a request for a composer who wrote at least one symphony is calculated by subtracting the combined probability of Bach and Wagner from 1, in percentage, that is, \(P(Composer wrote >=1 symphony)= 1 - P(Bach, Wagner)= 1 - 6\% = 94\%.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Addition Rule in Probability
Understanding the addition rule in probability is essential when you are trying to find the likelihood of any one of several different events happening. In our textbook problem, we're looking at the probability of music requests for certain composers on a radio station. Specifically, if we want to know what the chance is that a request is for Bach, Beethoven, or Brahms – the three B's – we use the addition rule. This rule allows us to add together the independent probabilities of each event to obtain the total probability of any one of them occurring.

Here's the math behind it: Given that the probability of a request for Bach is 5%, for Beethoven it's 26%, and for Brahms, it's 9%; we add these percentages to get the combined probability for any one of the three B's. Using the formula \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\), since we have independent events that don't occur simultaneously, the formula simplifies to just \(P(Bach) + P(Beethoven) + P(Brahms)\), resulting in a 40% chance.

Remember, this rule is only accurate when the events are mutually exclusive, meaning they cannot happen at the same time. In the context of our problem, a request can't be for Bach and Beethoven at the same time - it can only be for one composer.
Complement Probability
The complement rule in probability is just as crucial as the addition rule, especially when it's easier to calculate the chances of something not happening rather than what we're directly interested in. Using the radio station problem, we can illustrate the complement rule by finding the probability that a request is not for one of the two S's—Schubert or Schumann.

To do this, we first need the combined probability of the two S's, which is the sum of their individual probabilities (12% + 7% = 19%). The complement rule states that the probability of not landing on the two S's is 1 (representing certainty, or 100%) minus the probability of the events occurring. Mathematically, we express this as \(P(\text{not } S) = 1 - P(S)\), which in our example would be \(1 - 0.19 = 0.81\) or 81%.

The complement rule is exceptionally handy when dealing with high probabilities or a large number of possible outcomes. It simplifies the calculation and can quickly reveal the chances of an event not happening, which in many scenarios is exactly the information needed.
Probability Calculation
The probability calculation encompasses methods and rules to find the likelihood of events. It's fundamental to understanding randomness and predicting outcomes. When we look into whether a music request is for a composer who wrote at least one symphony (excluding Bach and Wagner), we again use complementary probability.

Calculating this probability involves subtracting the probability of the event we don't want (requests for Bach or Wagner) from the total probability. The sum of their probability is 6% (Bach's 5% and Wagner's 1%), and using the complement rule, we subtract this from 100%, which thus gives us a 94% probability. The mathematical expression for this scenario is \(P(\text{composer wrote } \geq1 \text{ symphony}) = 1 - P(Bach \cup Wagner)\), which simplifies to \(1 - 0.06 = 0.94\).

It's important to grasp that while rules like addition and complement are straightforward, considerations must be taken regarding the independence of events and the total probability space. Always ensure that the probabilities add up to 100%, and verify whether events can occur simultaneously or not to use the correct formula for your probability calculations.

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Most popular questions from this chapter

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