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"N.Y. Lottery Numbers Come Up 9-1-1 on \(9 / 11 "\) was the headline of an article that appeared in the San Francisco Chronicle (September 13, 2002). More than 5600 people had selected the sequence \(9-1-1\) on that date, many more than is typical for that sequence. \(\mathrm{A}\) professor at the University of Buffalo is quoted as saying, "I'm a bit surprised, but I wouldn't characterize it as bizarre. It's randomness. Every number has the same chance of coming up.' a. The New York state lottery uses balls numbered \(0-9\) circulating in three separate bins. To select the winning sequence, one ball is chosen at random from each bin. What is the probability that the sequence \(9-1-1\) is the sequence selected on any particular day? (Hint: It may be helpful to think about the chosen sequence as a three-digit number.) b. What approach (classical, relative frequency, or subjective) did you use to obtain the probability in Part (a)? Explain.

Short Answer

Expert verified
a. The probability of the sequence 9-1-1 being selected on any particular day is 1/1000. \nb. The approach used to calculate this probability is the classical approach.

Step by step solution

01

Determine the Total Number of Outcomes

There are three bins with balls numbered 0-9 in each bin. Therefore, the total number of combinations, or 'outcomes', for the winning lottery sequence is \(10 \times 10 \times 10\) since there are 10 possibilities for each of the three draws
02

Calculate Favorable Outcomes

The sequence 9-1-1 is only one specific combination out of the total possible combinations. So, there is only 1 favorable outcome for this event.
03

Use the Probability Formula

The classical probability formula is used here. The formula is \(P(E) = \frac{n(E)}{n(S)}\), where n(E) is the number of favorable outcomes and n(S) is the total number of outcomes. Substituting our values, we get \(P(E) = \frac{1}{10 \times 10 \times 10} = \frac{1}{1000}\)
04

Identifying the Approach

The approach used to calculate the probability in Step 3 is classical because it doesn't rely on collected data (relative frequency) or personal judgement (subjective). It strictly depends on the assumption that each outcome (number sequence in this case) is equally likely to occur, which is the definition of classical probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Classical Probability
When we refer to classical probability, we invoke a sense of predictability that each of several possible outcomes is equally likely to occur. Think of it as flipping a fair coin; you’re equally likely to get heads as you are to get tails because there are clearly two distinct outcomes that can arise from your action.

In the case with the New York state lottery example, to calculate the probability of getting the sequence 9-1-1, one must first acknowledge that choosing one number from each of the three separate bins has an equal chance of occurring. In other words, getting a 0 from the first bin is just as likely as getting a 9 from the third bin.

Understanding Equal Likelihood

With each bin having 10 equally likely outcomes (0 through 9), there's complete symmetry in possible results when one ball is drawn from each bin. The classical approach assumes each three-digit number combination generated this way has the same chance of being drawn, regardless of any patterns or personal significance those numbers may have.
Probability Formulas
Probability formulas are the backbone of quantifying the chance of an event occurring. The most fundamental of these is the classical probability formula: \[ P(E) = \frac{n(E)}{n(S)} \]This formula might look terse, but it's deceptively simple. Here, \( P(E) \) represents the probability of event E happening, \( n(E) \) is the number of favorable outcomes for event E, and \( n(S) \) the total number of possible outcomes in the sample space S.

Favorable vs. Total Outcomes

In our lottery example, \( n(E) \) is 1, because the winning combination 9-1-1 is a single event, and \( n(S) \) is 1000, as it is the product of 10 possible outcomes for each of the three bins. Dividing the single favorable outcome by the total number of possible combinations leads to the probability of the 9-1-1 sequence being drawn, which is \( \frac{1}{1000} \). This simple formulation can be applied to many scenarios in probability, making it a go-to tool for beginners and experts alike.
Probability Outcomes
Probability outcomes are essentially the possible results of an event, like the different sides of a die or, in the case of our New York lotto example, the various three-number combinations from 000 to 999. These form the sample space of the event—the collection of all possible outcomes.

Sample Space Size Impacts Probability

The larger the sample space, the lower the probability of any single outcome occurring, assuming each outcome is equally likely. With the lottery, there are 1000 different three-digit sequences that can arise from the mix of numbers 0-9 in each of the three bins, making the sample space quite extensive. This expansive sample space leads to the specific sequence 9-1-1 having a probability of \( \frac{1}{1000} \), which is quite small.

Understanding probability outcomes isn't just about counting the possibilities but also realizing that each has an associated probability which, in the classical sense, derives from its part of the whole. This concept is critical not only for straightforward scenarios like lotteries but also for more complex situations in statistical and probabilistic studies.

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Most popular questions from this chapter

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