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Suppose that the distribution of scores on an exam is closely described by a normal curve with mean \(100 .\) The 16 th percentile of this distribution is \(80 .\) a. What is the 84 th percentile? b. What is the approximate value of the standard deviation of exam scores? c. What \(z\) score is associated with an exam score of 90 ? d. What percentile corresponds to an exam score of \(140 ?\) e. Do you think there were many scores below 40 ? Explain.

Short Answer

Expert verified
a. The 84th percentile is 120; b. The standard deviation is 20; c. The z score associated with an exam score of 90 is -0.5; d. The percentile corresponding to an exam score of 140 is the 97.72nd percentile; e. There were likely very few scores below 40, as this score is more than 3 standard deviations below the mean.

Step by step solution

01

Calculate the Standard Deviation

Percentiles are indicators of how a given result compares to all others in the set. In a normal distribution, we know that the 16th percentile point is 1 standard deviation below the mean. The mean is 100 and the 16th percentile is 80. So, the standard deviation \(\sigma\) is \(100 - 80 = 20\).
02

Find the 84th Percentile

The 84th percentile is one standard deviation above the mean in a normal distribution. Since the standard deviation is 20 and the mean is 100, the 84th percentile is \(100+20 = 120\).
03

Determine the z-score for an exam score of 90

The z-score is a measure of how many standard deviations away a value is from the mean. It's calculated as \((x - µ)/σ\), where x is the value, µ is the mean, and σ is the standard deviation. So, z for an exam score of 90 is \(\(90 - 100) / 20 = -0.5\)
04

Find the Percentile Ranking for a score of 140

An exam score of 140 is 2 standard deviations above the mean. The corresponding percentile can be found by checking the standard normal distribution tables which indicate that a z-score of 2 corresponds to the 97.72nd percentile.
05

Interpret Scores Below 40

A score of 40 is 3 standard deviations below the mean. In a normal distribution, 99.7% of values lie within 3 standard deviations of the mean, so it is expected that very few scores were below 40.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentiles
Percentiles are a way to understand how a score compares to others in a set. They indicate the percentage of scores that fall below a particular value. In a normal distribution, different percentiles have typical positions.
Here are some key facts about percentiles:
  • The 16th percentile means that 16% of all scores are below this value.
  • Percentiles are often used in standardized testing to compare a student's performance to their peers.
  • The 84th percentile means that 84% of all scores are below this one, making it a higher score than most. Because the normal curve is symmetric, if the 16th percentile is a certain distance below the mean, the 84th percentile is the same distance above the mean.
When we know the 16th percentile score and the mean, we can calculate the standard deviation, which helps us find other percentiles. For example, in the given exam problem, with a mean score of 100, the 16th percentile is at 80, allowing us to find the 84th percentile at 120.
Understanding percentiles helps learners position their performance and expectations relative to others, especially in normally distributed data.
Standard Deviation
Standard deviation is a crucial concept in statistics that measures the spread of a set of values around the mean. It tells us how much variation or dispersion there is from the average. In a normal distribution, most values lie within a range defined by the standard deviation. Here are some important points:
  • One standard deviation from the mean in each direction covers about 68% of the data.
  • Two standard deviations include about 95%, and three standard deviations nearly 99.7%.
  • A small standard deviation means values are close to the mean; a large one indicates values are spread out over a wider range.
In our example, the standard deviation is 20. This tells us that the scores vary, on average, by 20 points above or below the mean of 100. Using standard deviation helps us identify outliers and understand the distribution of scores. It's essential for interpreting data variability and making informed decisions in contexts like education and finance.
Z-Score
A z-score, or standard score, tells us how many standard deviations a data point is from the mean. It is a helpful tool for comparing individual scores to a group average, especially in the context of a normal distribution. To calculate a z-score, use the formula:
  • \[z = \frac{x - \mu}{\sigma}\]
  • where:
    • \[x\] is the individual score,
    • \[\mu\] is the mean, and
    • \[\sigma\] is the standard deviation.
For example, if we want to find the z-score for a score of 90:
  • Subtract the mean (100) from 90, which gives -10.
  • Divide by the standard deviation (20) to get a z-score of -0.5.
This z-score of -0.5 indicates that a score of 90 is half a standard deviation below the mean. Z-scores allow easy comparison across different datasets by standardizing scores, making them useful in educational assessments, finance, and psychology to gauge individual performance relative to a broader set of data.

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Most popular questions from this chapter

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