/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Mobile homes are tightly constru... [FREE SOLUTION] | 91Ó°ÊÓ

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Mobile homes are tightly constructed for energy conservation. This can lead to a buildup of indoor pollutants. The paper "A Survey of Nitrogen Dioxide Leyels Inside Mobile Homes" ( Journal of the Air Pollution Control Association [1988]: \(647-651\) ) discussed various aspects of \(\mathrm{NO}_{2}\) concentration in these structures. a. In one sample of mobile homes in the Los Angeles area, the mean \(\mathrm{NO}_{2}\) concentration in kitchens during the summer was \(36.92 \mathrm{ppb}\), and the standard deviation was \(11.34\). Making no assumptions about the shape of the \(\mathrm{NO}_{2}\) distribution, what can be said about the percentage of observations between \(14.24\) and \(59.60\) ? b. Inside what interval is it guaranteed that at least \(89 \%\) of the concentration observations will lie? c. In a sample of non-Los Angeles mobile homes, the average kitchen \(\mathrm{NO}_{2}\) concentration during the winter was \(24.76\) ppb, and the standard deviation was \(17.20 .\) Do these values suggest that the histogram of sample observations did not closely resemble a normal curve? (Hint: What is \(\bar{x}-2 s\) ?)

Short Answer

Expert verified
a. Approximately 74.43% observations lies within the given range b. The observations will lie within a range of 2.9 ppb to 70.9 ppb c. The given values suggest that the histogram of the observations does not closely resemble a normal curve.

Step by step solution

01

Answering Sub-Question a

The statement must explain something about the nature of the distribution. In this case, no assumption about the shape of the distribution is made, letting us leverage Chebyshev's theorem. It says that at least \((1-1/k^2) \%\) of the data is within \(k\) standard deviations of the mean. The interval 14.24 and 59.6 is approximately \(±1.97σ\) from the mean. This suggests that approximately \(1-1/1.97² = 0.7443\) or 74.43% of the observations lie within this range.
02

Answering Sub-Question b

Chebyshev's theorem is applied here again to answer second question. Given the guarantee of at least 89% of concentration observations, thus \(1-1/k^2 ≥ 0.89\). Implies, \(k^2 ≤ 1/(1-0.89)\), therefore, \(k ≤ 3\). So, the values will lie within a range of \(±3σ\) from the mean i.e. \(36.92 - 3(11.34)\) to \(36.92 + 3(11.34)\) or approximately 2.9 ppb to 70.9 ppb.
03

Answering Sub-Question c

The last part doesn't give any specific distribution, and we are asked about the resemblance of observations with normal curve. We check if the values lie within a range of \(±2σ\) from mean. Here, \(\bar{x}-2s\) = \(24.76 - 2(17.20) = -9.64\). This negative value suggests that the histogram of the observations doesn't closely resemble a normal curve, because under a normal distribution, this would imply negative concentration, which isn't possible in reality.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chebyshev's Theorem
Chebyshev's theorem is a fundamental statistical concept used when we want to understand data distributions without assuming a normal distribution pattern. This theorem offers a universal rule for any dataset, regardless of shape, and it states that for any number of standard deviations away from the mean, the proportion of observations lying within that range is at least a certain percentage. This percentage is calculated as \[1 - \frac{1}{k^2}\],where \(k\) is the number of standard deviations.In practical terms, if you do not know whether your data follows a normal distribution, Chebyshev's theorem gives you a useful tool to estimate how data is likely spread around the mean. For example, if you're looking at data falling within about \(2\) standard deviations from the mean (as in the problem), Chebyshev's theorem tells you that at least \[1 - \frac{1}{2^2} = 1 - 0.25 = 0.75\] (75\%) of the observations fall within these bounds. This provides a reliable range for data analysis, especially in fields where data does not conform neatly to normality.
Normal Distribution
The normal distribution is a continuous probability distribution, perfectly symmetrical, and bell-shaped when plotted on a graph. This is often referred to as a Gaussian distribution. Properties of normal distributions include:
  • The mean, median, and mode are all equal.
  • The curve is symmetric around the mean.
  • Most observations cluster around the mean, with probabilities decreasing as we move away.
Normal distribution is key in statistics because many phenomena naturally follow this pattern, making it a cornerstone for statistical inference and hypothesis testing. In a normal distribution, about \(68\%\) of data falls within one standard deviation of the mean, \(95\%\) within two standard deviations, and \(99.7\%\) within three standard deviations.In contrast, if observations are too dispersed, or oddly shaped, they suggest the data does not conform to a normal distribution. For instance, in question part c, if a calculated range results in unrealistic values (like a concentration lower than zero), it signals the observations diverge significantly from the normal curve expectations, implying possibly skewed data in practice.
Standard Deviation
Standard deviation is a critical measure in statistics that quantifies the amount of variation or dispersion in a set of values. When you calculate the standard deviation, what you're really exploring is how spread out each value is from the average (or mean). It is denoted by \(\sigma\) for populations or \(s\) for samples.A smaller standard deviation indicates that the values tend to be close to the mean, while a larger standard deviation implies more spread out data. Its calculation involves finding the square root of the variance, which is the average of the squared differences from the Mean: \[s = \sqrt{\frac{1}{N-1} \sum_{i=1}^{N} (x_i - \bar{x})^2}\],where \(N\) is the number of observations, and \(x_i\) are the individual observations.Understanding standard deviations is crucial. For instance, in the mobile home pollution data, standard deviation helps us determine how tightly clustered the NO\(_2\) values are around the mean. This insight aids in identifying whether certain concentrations are typical, or if they represent unusual outliers.
Mean
The mean, commonly referred to as the average, is one of the most fundamental concepts in statistics. It represents the central value for a set of numbers and provides the best estimate of the typical value in a distribution. The mean is calculated by summing up all the data points and then dividing by the number of values: \[ \bar{x} = \frac{\sum_{i=1}^{N} x_i}{N}\].In practical uses, the mean gives us a quick snapshot of the data's general behavior. For instance, in the NO\(_2\) concentration study within mobile homes, the mean tells us the typical concentration level one might expect. However, relying solely on the mean can sometimes mislead, especially if the data contains exceptional outliers. In such cases, integrating the mean with measures of variation, like the standard deviation, ensures a more accurate insight into the data's true nature.The exercise relies on the mean to determine central tendencies of nitrogen dioxide concentrations in different scenarios, guiding us to better understand environmental pollution risks in mobile homes. This basic statistical measure provides a foundation from which other analyses, including variance and standard deviation, can branch off for richer, more detailed data interpretation.

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Most popular questions from this chapter

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