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The accompanying data on number of minutes used for cell phone calls in 1 month was generated to be consistent with summary statistics published in a report of a marketing study of San Diego residents (TeleTruth. March 2009 ) $$ \begin{array}{rrrrrrrrrr} 189 & 0 & 189 & 177 & 106 & 201 & 0 & 212 & 0 & 306 \\ 0 & 0 & 59 & 224 & 0 & 189 & 142 & 83 & 71 & 165 \\ 236 & 0 & 142 & 236 & 130 & & & & & \end{array} $$ a. Compute the values of the quartiles and the interquartile range for this data set. b. Explain why the lower quartile is equal to the minimum value for this data set. Will this be the case for every data set? Explain.

Short Answer

Expert verified
The quartile values are Q1=0, Q2=142, Q3=212 and Inter Quartile Range (IQR)= 212. The lower quartile is equal to the minimum value for this data set as it contains a larger percentage of zero values which pull down the 25th percentile (Q1) to zero. However, this might not be the case for every dataset; every data distribution is different and hence can't guarantee Q1 to be always equal to the minimum value.

Step by step solution

01

Sort the data

In order to find the quartiles and the interquartile range, you need to first write the data in ascending order from smallest to largest.
02

Calculate Q1 (First quartile)

The first quartile, denoted as Q1, represents the 25th percentile of the data. It is calculated by dividing the ordered dataset into four equal parts. As per the formula Q1= 1/4 *(n+1)th term, where n is the total number of observations.
03

Calculate Q2 (Second quartile/Median)

The second quartile (Q2), often also referred to as the median, represents the midpoint or the 50th percentile of the data. Here we will calculate it as Q2= 1/2 *(n+1)th term
04

Calculate Q3 (Third quartile)

The third quartile, denoted as Q3, represents the 75th percentile of the data. It is basically calculated by summing up the second half of the data. We calculate it as Q3= 3/4 *(n+1)th term
05

Compute Interquartile range (IQR)

The interquartile range, often referred to as IQR, is a measure of dispersion and it can be found by subtracting Q1 from Q3 (IQR = Q3 - Q1).
06

Understanding the significance of quartile in the dataset

The lower quartile (Q1) is equal to the minimum value for this data set because the given dataset includes a large number of zeroes. This might not be the case in every dataset. Lower quartile refers to the value below which lies 25% of the data. If this 25% of the data includes the minimum values in a higher quantity then only can it be possible for the lower quartile to be equal to the minimum value of the data set. Therefore, whether this will be the case for every data set depends on the nature of the data sets.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quartiles
Quartiles are values that divide a set of data into four equal parts. They are crucial in understanding the distribution of data and are denoted as Q1 (first quartile), Q2 (second quartile or median), and Q3 (third quartile). Imagine sorting data from least to greatest; Q1 is the 'middle' value of the first half, Q2 is the central most value of the entire set, and Q3 is the 'middle' value of the second half.

This means that Q1 is the 25th percentile, Q2 is the 50th percentile, and Q3 is the 75th percentile of the data set. For example, if you sorted the given cell phone data, your first quartile (Q1) would capture the lower 25% of your data including the frequent zeroes, hence why Q1 could be equal to the minimum value of the dataset. This method of data analysis gives us a clear view of the distribution and helps identify which values fall into the lower, middle, and upper portions of the dataset.
Interquartile Range
The interquartile range (IQR) is a measure of statistical dispersion, which is essentially the spread of the data points. It's the difference between the third quartile (Q3) and the first quartile (Q1) of a dataset. To calculate the IQR, we subtract the value of Q1 from Q3: \( IQR = Q3 - Q1 \). This metric is particularly insightful as it encapsulates the middle 50% of a dataset, thus allowing us to understand the range within which the bulk of our data lies, exempt from the influence of outliers.

Why is this important? The IQR helps identify variability and outliers in your data. For the mobile phone usage case, the IQR would tell us the range of minutes within which most of the phone call durations are concentrated, providing insights into typical user behavior, without being skewed by those who rarely or extensively use their phones.
Data Dispersion
Data dispersion refers to the spread or variability within a set of data points. The descriptive statistics that detail this spread include range, variance, standard deviation, and interquartile range (IQR). Measuring dispersion is critical as it helps us understand how spread out the data is, offering insights into the reliability of the mean.

For instance, a cell phone data set with a high level of dispersion would suggest that users have a wide range of different usage habits, from very low to very high minutes of usage. Conversely, a low dispersion indicates that most users' behavior is similar, with their usage minutes clustering tightly around the mean. Such an understanding of dispersion is beneficial for a business aiming to tailor services or offers to its customer base.
Percentiles
Percentiles are measurements that partition a data set into 100 equal parts, which are useful in ranking and comparing values within the data. The 50th percentile, for example, is the median, indicating that half of the data is below this value. If we say that a cell phone user at the 90th percentile uses 250 minutes per month, it means that 90% of the users spend 250 minutes or less on their phones.

Understanding percentiles in practical terms can be vital. For businesses, percentiles can guide decision-making processes such as setting thresholds for customer usage-based classifications or developing targeted marketing campaigns for different percentile groups based on their usage patterns. It is worth noting that percentiles, like quartiles, can also highlight outliers by showing how certain data points stand in relation to the rest of the data.

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Most popular questions from this chapter

Give two sets of five numbers that have the same mean but different standard deviations, and give two sets of five numbers that have the same standard deviation but different means.

A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (in seconds) to complete the escape ("Oxygen Consumption and Ventilation During Escape from an Offshore Platform," Ergonomics [1997]: 281-292): \(\begin{array}{lllllllll}389 & 356 & 359 & 363 & 375 & 424 & 325 & 394 & 402 \\\ 373 & 373 & 370 & 364 & 366 & 364 & 325 & 339 & 393 \\ 392 & 369 & 374 & 359 & 356 & 403 & 334 & 397 & \end{array}\) a. Construct a stem-and-leaf display of the data. Will the sample mean or the sample median be larger for this data set? b. Calculate the values of the sample mean and median. c. By how much could the largest time be increased without affecting the value of the sample median? By how much could this value be decreased without affecting the sample median?

The article "Comparing the Costs of Major Hotel Franchises" (Real Estate Review [1992]: 46-51) gave the following data on franchise cost as a percentage of total room revenue for chains of three different types: Budget \(\begin{array}{llllllll} & 2.7 & 2.8 & 3.8 & 3.8 & 4.0 & 4.1 & 5.5 \\\ & 5.9 & 6.7 & 7.0 & 7.2 & 7.2 & 7.5 & 7.5 \\ & 7.7 & 7.9 & 7.9 & 8.1 & 8.2 & 8.5 & \\ \text { ge } & 1.5 & 4.0 & 6.6 & 6.7 & 7.0 & 7.2 & 7.2 \\ & 7.4 & 7.8 & 8.0 & 8.1 & 8.3 & 8.6 & 9.0 \\ \text { ss } & 1.8 & 5.8 & 6.0 & 6.6 & 6.6 & 6.6 & 7.1 \\ & 7.2 & 7.5 & 7.6 & 7.6 & 7.8 & 7.8 & 8.2 \\ & 9.6 & & & & & & \end{array}\) \(\begin{gathered}\text { Midrange } \\ \text { First-class } \\ & 7 \\ 7\end{gathered}\) Construct a boxplot for each type of hotel, and comment on interesting features, similarities, and differences.

The following data are cost (in cents) per ounce for nine different brands of sliced Swiss cheese (www .consumerreports.org): \(\begin{array}{lllllllll}29 & 62 & 37 & 41 & 70 & 82 & 47 & 52 & 49\end{array}\) a. Compute the variance and standard deviation for this data set. b. If a very expensive cheese with a cost per slice of 150 cents was added to the data set, how would the values of the mean and standard deviation change?

The amount of aluminum contamination (in parts per million) in plastic was determined for a sample of 26 plastic specimens, resulting in the following data ("The Log Normal Distribution for Modeling Quality Data When the Mean is Near Zero." Journal of Quality Technology \([1990]: 105-110)\) : \(\begin{array}{rrrrrrrrr}30 & 30 & 60 & 63 & 70 & 79 & 87 & 90 & 101 \\ 102 & 115 & 118 & 119 & 119 & 120 & 125 & 140 & 145 \\ 172 & 182 & 183 & 191 & 222 & 244 & 291 & 511 & \end{array}\) Construct a boxplot that shows outliers, and comment on the interesting features of this plot.

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