/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Sea bream are one type of fish t... [FREE SOLUTION] | 91Ó°ÊÓ

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Sea bream are one type of fish that are often raised in large fish farming enterprises. These fish are usually fed a diet consisting primarily of fish meal. The authors of the paper describe a study to investigate whether it would be more profitable to substitute plant protein in the form of sunflower meal for some of the fish meal in the sea bream's diet. The accompanying data are consistent with summary quantities given in the paper for \(x=\) percentage of sunflower meal in the diet and \(y=\) average weight of fish after 248 days (in grams). \begin{tabular}{cc} Sunflower Meal (\%) & Average Fish Weight \\ \hline 0 & 432 \\ 6 & 450 \\ 12 & 455 \\ 18 & 445 \\ 24 & 427 \\ 30 & 422 \\ 36 & 421 \\ \hline \end{tabular} The estimated regression line for these data is \(\hat{y}=448.536-0.696 x\) and the standardized residuals are as given. \begin{tabular}{cc} Sunflower Meal (\%), \(x\) & Standardized Residual \\ \hline 0 & \(-1.96\) \\ 6 & \(0.58\) \\ 12 & \(1.42\) \\ 18 & \(0.84\) \\ 24 & \(-0.46\) \\ 30 & \(-0.58\) \\ 36 & \(-0.29\) \\ \hline \end{tabular} Construct a standardized residual plot. What does the plot suggest about the adequacy of the simple linear regression model?

Short Answer

Expert verified
The short answer depends on the observed standardized residual plot. If the points are randomly scattered around zero, then the linear regression model fits well. If there is a visible pattern besides randomness, for instance, a curve, then the simple linear regression model might not be the suitable fit.

Step by step solution

01

Plotting the Standardized Residuals

For each value of \(x\) (Sunflower Meal percentage), plot the corresponding standardized residual on the y-axis. We're visualizing the difference between the observed weight of the fish (\(y\)) for a given sunflower meal percentage and the predicted weight of the fish by the regression model 'on a standardized scale'. The data pairs to plot are as follows: (0,-1.96), (6,0.58), (12,1.42), (18,0.84), (24,-0.46), (30,-0.58), (36,-0.29).
02

Interpreting the Residual Plot

Observe the nature of the scatter plot. If the data seems to be randomly spread around the x-axis (mean residual is zero), this indicates that the linear regression model fits well. However, if there seems to be a pattern, such as a curve or a systematic tendency for the residuals to be either positive or negative at particular values of \(x\), this suggests that the linear regression model may not be a suitable fit for the data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standardized Residuals
Standardized residuals are a crucial part of assessing a linear regression model. They tell us how far off our predictions are from the actual values in terms of standard deviations. Additionally, they help determine whether our model might have some biases or inconsistencies. To calculate a standardized residual, you subtract the predicted value from the observed value, then divide this by the standard deviation of the residuals. This standardizes the value so it can be easily interpreted, typically as z-scores. This means that residuals with a magnitude greater than 2 are considered unusual or suggest that the data point doesn't fit the model prediction well. In our example, each value of sunflower meal has a corresponding standardized residual. For instance, at 12% sunflower meal, the standardized residual is 1.42. This tells us that the observed weight is about 1.42 standard deviations above the predicted weight. By looking at all the standardized residuals, especially those greater than 2 or less than -2, we can identify potential outliers or problematic areas in our model.
Residual Plot Interpretation
Interpreting a residual plot involves examining the residual values plotted against an independent variable, in our case, the percentage of sunflower meal. The goal is to see how those residuals distribute relative to the x-axis. If the residuals appear to be randomly scattered around the horizontal line (indicating a mean residual of zero), this suggests that the model has accounted for most or all of the variability in the data. Random scatter implies that the assumption of linearity is valid for this dataset. However, if the points demonstrate a pattern—like clustering, or forming a curve—this indicates that the linear model may not be suitable. Patterns can mean that there's a systematic error in the model, perhaps because some predictor or variable wasn't accounted for. In our example with sea bream, the residual plot should show random scatter across all levels of sunflower meal if the linear model is apt.
Model Fit Evaluation
Evaluating the fit of a linear regression model ties together analysis of standardized residuals and interpretation of the residual plot. It is about assessing how well the model explains the variation in the dataset.For model fit evaluation, there are a few aspects to consider:
  • Goodness of fit: Determines how well the model's predicted values match the observed data. Usually, it's measured using the coefficient of determination, denoted as \(R^2\). Higher values close to 1 suggest a very good fit.
  • Residual analysis: A close examination of standardized residuals and patterns in the residual plot tells us about potential errors in the model’s predictions or assumptions.
  • Outliers and leverage points: Check for data points with high standardized residuals. These could exert undue influence or suggest errors in the dataset or its expectations.
In our data about sunflower meal and sea bream weights, consistent spread in standardized residuals across all levels of the independent variable could confirm the model is suitable. Observing a good \(R^2\) value further solidifies confidence in the regression line.

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Most popular questions from this chapter

Occasionally an investigator may wish to compute a confidence interval for \(\alpha\), the \(y\) intercept of the true regression line, or test hypotheses about \(\alpha\). The estimated \(y\) intercept is simply the height of the estimated line when \(x=0\), since \(a+b(0)=a\). This implies that \(s_{0}\) the estimated standard deviation of the statistic \(a\), results from substituting \(x^{*}=0\) in the formula for \(s_{a+b \alpha}\). The desired confidence interval is then \(a \pm(t\) critical value \() s_{a}\) and a test statistic is $$ t=\frac{a-\text { hypothesized value }}{s_{a}} $$ a. The article used the simple linear regression model to relate surface temperature as measured by a satellite \((y)\) to actual air temperature \((x)\) as determined from a thermocouple placed on a traversing vehicle. Selected data are given (read from a scatterplot in the article). $$ \begin{array}{rrrrrrrr} x & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ y & -3.9 & -2.1 & -2.0 & -1.2 & 0.0 & 1.9 & 0.6 \end{array} $$ \(\begin{array}{llll}x & 5 & 6 & 7\end{array}\) \(\begin{array}{llll}y & 2.1 & 1.2 & 3.0\end{array}\) Estimate the population regression line. b. Compute the estimated standard deviation \(s_{a r}\). Carry out a test at level of significance \(.05\) to see whether the \(y\) intercept of the population regression line differs from zero. c. Compute a \(95 \%\) confidence interval for \(\alpha\). Does the result indicate that \(\alpha=0\) is plausible? Explain.

A sample of small cars was selected, and the values of \(x=\) horsepower and \(y=\) fuel efficiency \((\mathrm{mpg})\) were determined for each car. Fitting the simple linear regression model gave the estimated regression equation \(\hat{y}=44.0-.150 x .\) a. How would you interpret \(b=-.150\) ? b. Substituting \(x=100\) gives \(\hat{y}=29.0\). Give two different interpretations of this number. c. What happens if you predict efficiency for a car with a 300-horsepower engine? Why do you think this has occurred? d. Interpret \(r^{2}=0.680\) in the context of this problem. e. Interpret \(s_{e}=3.0\) in the context of this problem.

The article gave the following data (read from a scatterplot) on \(y=\) glucose concentration \((\mathrm{g} / \mathrm{L})\) and \(x=\) fermentation time (days) for a blend of malt liquor. $$ \begin{array}{rrrrrrrrr} x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ y & 74 & 54 & 52 & 51 & 52 & 53 & 58 & 71 \end{array} $$ a. Use the data to calculate the estimated regression line. b. Do the data indicate a linear relationship between \(y\) and \(x\) ? Test using a \(.10\) significance level. c. Using the estimated regression line of Part (a), compute the residuals and construct a plot of the residuals versus \(x\) (that is, of the \((x\), residual \()\) pairs). d. Based on the plot in Part (c), do you think that the simple linear regression model is appropriate for describing the relationship between \(y\) and \(x\) ? Explain.

If the sample correlation coefficient is equal to 1, is it necessarily true that \(\rho=1\) ? If \(\rho=1\), is it necessarily true that \(r=1 ?\)

The accompanying data were read from a plot (and are a subset of the complete data set) given in the article . The data represent the mean response times for a group of individuals with closed-head injury (CHI) and a matched control group without head injury on 10 different tasks. Each observation was based on a different study, and used different subjects, so it is reasonable to assume that the observations are independent. \begin{tabular}{ccc} & \multicolumn{2}{l} { Mean Response Time } \\ \cline { 2 - 3 } Study & Control & CHI \\ \hline 1 & 250 & 303 \\ 2 & 360 & 491 \\ 3 & 475 & 659 \\ 4 & 525 & 683 \\ 5 & 610 & 922 \\ 6 & 740 & 1044 \\ 7 & 880 & 1421 \\ 8 & 920 & 1329 \\ 9 & 1010 & 1481 \\ 10 & 1200 & 1815 \\ \hline \end{tabular} a. Fit a linear regression model that would allow you to predict the mean response time for those suffering a closed-head injury from the mean response time on the same task for individuals with no head injury. b. Do the sample data support the hypothesis that there is a useful linear relationship between the mean response time for individuals with no head injury and the mean response time for individuals with CHI? Test the appropriate hypotheses using \(\alpha=.05\). c. It is also possible to test hypotheses about the \(y\) intercept in a linear regression model. For these data, the null hypothesis \(H_{0}: \alpha=0\) cannot be rejected at the \(.05\) significance level, suggesting that a model with a \(y\) intercept of 0 might be an appropriate model. Fitting such a model results in an estimated regression equation of \(\mathrm{CHI}=1.48(\) Control \()\) Interpret the estimated slope of \(1.48\).

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