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The article "Fish Oil Staves Off Schizophrenia" (USA Today. February 2, 2010) describes a study in which 81 patients age 13 to 25 who were considered atrisk for mental illness were randomly assigned to one of two groups. Those in one group took four fish oil capsules daily. The other group took a placebo. After 1 year, \(5 \%\) of those in the fish oil group and \(28 \%\) of those in the placebo group had become psychotic. Is it appropriate to use the two-sample \(z\) test of this section to test hypotheses about the difference in the proportions of patients receiving the fish oil and the placebo treatments who became psychotic? Explain why or why not.

Short Answer

Expert verified
Yes, it is appropriate to use the two-sample z test to test hypotheses about the difference in the proportions of patients receiving the fish oil and the placebo treatments who became psychotic because all the assumptions for a two-sample z test are met.

Step by step solution

01

Understand the 2-sample z test

A 2-sample z test is suitable for comparing the proportions of two different, independent groups when it is not known if the populations they come from are normally distributed, or the sample size is large enough. It's based on the Central Limit Theorem and assumes that the sampling distribution approaches normal distribution as the sample size increases.
02

Analyze the conditions for applying 2-sample z test

The conditions for conducting a 2-sample z test include: The samples must be independent. The sample sizes must be large enough. The Sample size times the population proportion and the sample size times the population proportion complement for both groups should be greater than or equal to 5. Hence we need to verify if these conditions are met in our case.
03

Check the conditions with the given data

With 81 patients divided into 2 groups, we have independent samples. Also, the number of successes and failures in each sample (psychotic and not psychotic) exceed 5, allowing us to invoke the Central Limit Theorem. Thus our sample size can be considered large enough.
04

Final decision

Since all the conditions are met (sample sizes are large, samples are independent), it seems appropriate to use a 2-sample z test to compare proportions. It will help test the hypothesis that the proportion of patients becoming psychotic varies between those who took fish oil and those who took a placebo.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental concept in statistics that helps us understand the behavior of sample means. Essentially, the CLT tells us that as the sample size becomes large enough, the sampling distribution of the sample mean will tend to approximate a normal distribution, regardless of the shape of the population distribution. This approximation gets better with larger sample sizes.
User
This is particularly useful when conducting hypothesis tests, like the two-sample z test. In the context of proportion comparison, the CLT allows us to assume that the differences in sample proportions can be treated as normally distributed. That's why we could consider using a z test in our exercise even if the original distributions are unknown.
Because of the CLT, researchers are able to make inferences about population parameters using sample statistics, provided the sample size is sufficient. A common rule of thumb is that a sample size of 30 or more is often enough for the CLT to hold, though in the context of proportions, a different rule applies, based on the number of observed successes and failures. This was apparent in the exercise where the sample was large enough for the CLT to justify the use of a z test.
Hypothesis Testing
Hypothesis testing is a method used in statistics to determine if there is enough evidence to reject a null hypothesis in favor of an alternative hypothesis. It is a formal process that involves several steps:
  • Define the null and alternative hypotheses (H鈧 and H鈧).
  • Determine the significance level (alpha), often set at 0.05.
  • Calculate the test statistic using the data.
  • Compare the test statistic to a critical value to decide on the hypothesis.
This process is used to make decisions about the population based on sample data. In the exercise provided, we use a two-sample z test to compare proportions of patients becoming psychotic between the fish oil and placebo groups.
Hypothesis testing begins with setting up two opposing hypotheses: the null hypothesis (\(H_0\)) and the alternative hypothesis (\(H_1\)). For instance, the null hypothesis might be that there is no difference in proportions, while the alternative might be that there is a significant difference.
The key here is that hypothesis testing gives a structured way to assess if the observed effects in the sample are statistically significant or if they could likely be attributed to random chance.
Sampling Distribution
A sampling distribution is the probability distribution of a given statistic based on a random sample. It is critical in inferential statistics because it allows us to estimate population parameters based on sample data. The sampling distribution concept is closely related to the Central Limit Theorem, which ensures that under certain conditions, the sampling distribution of the sample mean will be approximately normal.
In the exercise scenario, we calculate the sampling distribution of the difference in proportions between two independent groups. Because the sample sizes are adequate, the distribution of this difference is approximately normal. This approximation is crucial because it enables us to apply the two-sample z test.
  • The sampling distribution considers both the variability between samples and within them.
  • It's particularly significant because the properties of these distributions allow the use of statistical tests, like the z test, to infer about the population.
Understanding sampling distributions helps us make reasoned conclusions about the whole population from a sample, by evaluating and comparing the variability and behavior of samples across repeated trials.
Proportion Comparison
Proportion comparison is a statistical method used to evaluate the differences in proportions between two groups. In this method, we are often interested in comparing either two different categories within the same sample or across two independent samples.
The exercise involves comparing the proportion of patients becoming psychotic in the fish oil group versus those in the placebo group using a two-sample z test. Since both sample sizes in our exercise meet the necessary conditions (independence, large enough for normal approximation), we use this test to determine if the observed difference in proportions is statistically significant.
  • This involves calculating sample proportions for each group and using the test to determine any significant differences.
  • We focus on potential differences to make inferences about the effectiveness of fish oil compared to a placebo.
Proportion comparison is particularly powerful in clinical studies like ours since it helps quantify the effect of treatments (like fish oil) on disease outcomes. By comparing proportions, it enables us to understand the likelihood and strength of these observed effects.

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Most popular questions from this chapter

Consider two populations for which \(\mu_{1}=30\), \(\sigma_{1}=2, \mu_{2}=25\), and \(\sigma_{2}=3\). Suppose that two independent random samples of sizes \(n_{1}=40\) and \(n_{2}=50\) are selected. Describe the approximate sampling distribution of \(\bar{x}_{1}-\bar{x}_{2}\) (center, spread, and shape).

In December 2001 , the Department of Vererans Affairs announced that it would begin paying benefits to soldiers suffering from Lou Gehrig's disease who had served in the Gulf War (The New york Times, December 11,2001 ). This decision was based on an analysis in which the Lou Gehrig's disease incidence rate (the proportion developing the disease) for the approximately 700,000 soldiers sent to the Gulf between August 1990 and July 1991 was compared to the incidence rate for the approximately \(1.8\) million other soldiers who were not in the Gulf during this time period. Based on these data, explain why it is not appropriate to perform a formal inference procedure (such as the two-sample \(z\) test) and yet it is still reasonable to conclude that the incidence rate is higher for Gulf War veterans than for those who did not serve in the Gulf War.

The paper "If It's Hard to Read, It's Hard to Do" (Psychological Science [20081: 986-988) described an interesting study of how people perceive the effort required to do certain tasks. Each of 20 students was randomly assigned to one of two groups. One group was given instructions for an exercise routine that were printed in an easy-to-read font (Arial). The other group received the same set of instructions, but printed in a font that is considered difficult to read (Brush). After reading the instructions, subjects estimated the time (in minutes) they thought it would take to complete the exercise routine. Summary statistics are given below. The authors of the paper used these data to carry out a two-sample \(t\) test, and concluded that at the 10 significance level, there was convincing evidence that the mean estimated time to complete the exercise routine was less when the instructions were printed in an easy-to-read font than when printed in a difficult-to-read font. Discuss the appropriateness of using a two-sample \(t\) test in this situation.

After the 2010 earthquake in Haiti, many charitable organizations conducted fundraising campaigns to raise money for emergency relief. Some of these campaigns allowed people to donate by sending a text message using a cell phone to have the donated amount added to their cell-phone bill. The report "Early Signals on Mobile Philanthropy: Is Haiti the Tipping Point?" (Edge Research, 2010) describes the results of a national survey of 1526 people that investigated the ways in which people made donations to the Haiti relief effort. The report states that \(17 \%\) of Gen \(Y\) respondents (those born between 1980 and 1988 ) and \(14 \%\) of Gen \(\mathrm{X}\) respondents (those born between 1968 and 1979 ) said that they had made a donation to the Haiti relief effort via text message. The percentage making a donation via text message was much lower for older respondents. The report did not say how many respondents were in the Gen \(Y\) and Gen \(X\) samples, but for purposes of this exercise, suppose that both sample sizes were 400 and that it is reasonable to regard the samples as representative of the Gen \(\mathrm{Y}\) and Gen \(\mathrm{X}\) populations. a. Is there convincing evidence that the proportion of those in Gen \(\mathrm{Y}\) who donated to Haiti relief via text message is greater than the proportion for Gen X? Use \(\alpha=.01\) b. Estimate the difference between the proportion of Gen \(\mathrm{Y}\) and the proportion of Gen \(\mathrm{X}\) that made a donation via text message using a \(99 \%\) confidence interval. Provide an interpretation of both the interval and the associated confidence level.

The press release referenced in the previous exercise also included data from independent surveys of teenage drivers and parents of teenage drivers. In response to a question asking if they approved of laws banning the use of cell phones and texting while driving, \(74 \%\) of the teens surveyed and \(95 \%\) of the parents surveyed said they approved. The sample sizes were not given in the press release, but for purposes of this exercise, suppose that 600 teens and 400 parents of teens responded to the surveys and that it is reasonable to regard these samples as representative of the two populations. Do the data provide convincing evidence that the proportion of teens that approve of cell- phone and texting bans while driving is less than the proportion of parents of teens who approve? 'Test the relevant hypotheses using a significance level of \(.05\).

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