/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The paper "Fffects of Fast-Food ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The paper "Fffects of Fast-Food Consumption on Fnergy Intake and Diet Quality Among Children in a National Household Survey" (Pediatrics [2004]: 112-II8) investigated the effect of fast-food consumption on orher dierary variables. For a sample of 663 teens who reporred that they did not eat fast food during a rypical day, the mean daily calorie intake was 2258 and the sample standard deviation was \(1519 .\) For a sample of 413 reens who reported that they did eat fast food on a typical day, the mean calorie intake was 2637 and the standard deviation was 1138 . a. What assumptions about the two samples must be reasonable in order for the use of the two-sample confidence interval to be appropriate? b. Use the given information to estimate the difference in mean daily calorie intake for teens who do eat fast food on a typical day and those who do not.

Short Answer

Expert verified
The assumptions are: (1) The two groups of teens are independent from each other, (2) Each sample is normally distributed or large enough, and (3) The population standard deviations are equal. The difference in the mean daily calorie intake between teens who eat fast food and those who don't is approximately 379 calories per day.

Step by step solution

01

State the Assumptions

The appropriate assumptions that need to be considered are: 1. The two samples should be independent of each other.2. The data for each sample is drawn from a normal distribution or the sample size is large enough according to the Central Limit Theorem.3. The population standard deviations are equal. This is not mandatory but it simplifies the calculations.N.B. Note that failing to meet these assumptions doesn't necessarily invalidate the results, but it may impact their reliability.
02

Calculate the Difference in Mean Calorie Intake

The difference in mean daily calorie intake between teens who eat fast food and those who do not is given by the formula \[\Delta = \bar{X1} - \bar{X2}\]where \(\bar{X1}\) is the mean calorie intake of teens who eat fast food and \(\bar{X2}\) is the mean calorie intake of teens who do not eat fast food.So, \[\Delta = 2637 - 2258 = 379 kcal/day\]This means, on average, teens who eat fast food consume 379 more calories per day than those who do not.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Assumptions
When we attempt to estimate differences between groups in statistics, it's crucial to start with several key assumptions to ensure that the methods we use are appropriate and the results are valid. One assumption is that the samples we compare should be independent of each other. This means the data collected from one group should not influence or be related to the data from the other group.

Moreover, each sample's data should be drawn from a population that normally distributes or have a large enough sample size to invoke the Central Limit Theorem, lending to the distribution of sample means tending towards normality. While equal population standard deviations are not mandatory for all tests, assumption of such equality simplifies the calculation process. Without meeting these assumptions, especially in small sample sizes, the confidence interval might be less reliable.

It's paramount to remember that these assumptions provide a foundation for accurate statistical inference, helping to prevent skewed or misleading conclusions.
Mean Daily Calorie Intake
Understanding the mean daily calorie intake of different groups can be illuminating, especially when studying nutritional habits or assessing the impact of dietary choices on health. The mean is a measure of central tendency that summarizes the entire data set with a single number, representing the 'average' value.

In our context, we're comparing the average daily calorie intake between teens who eat fast food and those who don't, which can illuminate potential differences in dietary behaviors and their resulting health implications. Tracking calorie intake is essential in research linked to obesity, metabolic syndrome, and other diet-related conditions, making it a critical data point in nutritional epidemiology.
Fast-Food Consumption Effect
Fast food is notorious for being high in calories, fat, and sodium, and understanding its impact on daily calorie intake is essential for public health research. When investigating the effect of fast food on diet quality among teens, as the paper in our exercise does, we're essentially trying to quantify how the inclusion of fast food alters average calorie intake

The difference in mean calorie intake between the two groups—those who consumed fast food and those who did not—helps us understand the potential dietary impact of fast-food consumption. Discovering that teens who consume fast food ingest significantly more calories on average might inform interventions for nutrition education and health promotion.
Central Limit Theorem
The Central Limit Theorem (CLT) is a fundamental concept in the field of statistics that explains why the distribution of sample means tends to be normal, or bell-shaped, as the sample size becomes large, regardless of the shape of the population distribution.

For practical applications like ours, where we compare mean calorie intake, the CLT reassures us that the sampling distribution of the mean will approximate normality, particularly when we have a large sample size. This is why even when individual dietary intake data might not be normally distributed, the mean of a sufficiently large sample can still be treated as if it came from a normal distribution, enabling us to use techniques such as confidence intervals to infer about the population mean.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The director of the Kaiser Family Foundation's Program for the Study of Entertainment Media and Health said, "It's not just teenagers who are wired up and tuned in, its babies in diapers as well." A study by Kaiser Foundation provided one of the first looks at media use among the very youngest children- those from 6 months to 6 years of age (Kaiser Family Foundation. 2003 , www .kff.org). Because previous research indicated that children. who have a TV in their bedroom spend less time reading than other children, the authors of the Foundation study were interested in learning about the proportion of kids who have a TV in their bedroom. They collected data from two independent random samples of parents. One sample consisted of parents of children age 6 months to 3 years old. The second sample consisted of parents of children age 3 to 6 years old. They found that the proportion of children who had a TV in their bedroom was \(.30\) for the sample of children age 6 months to 3 years and \(.43\) for the sample of children age 3 to 6 years old. Suppose that the two sample sizes were each 100 . a. Construct and interpret a \(95 \%\) confidence interval for the proportion of children age 6 months to 3 years who have a TV in their bedroom. Hint: This is a one-sample confidence interval. b. Construct and interpret a \(95 \%\) confidence interval for the proportion of children age 3 to 6 years who have a 'TV in their bedroom. c. Do the confidence intervals from Parts (a) and (b) overlap? What does this suggest about the two population proportions? d. Construct and interpret a \(95 \%\) confidence interval for the difference in the proportion that have TVs in the bedroom for children age 6 months to 3 years and for children age 3 to 6 years. e. Is the interval in Part (d) consistent with your answer in Part (c)? Explain.

An experiment to determine if an online intervention can reduce references to sex and substance abuse on social networking web sites of adolescents is described in the paper "Reducing At-Risk Adolescents' Display of Risk Behavior on a Social Networking Web Site" (Archives of Pediatrics and Adolescent Medicine I2009 \(\mathrm{k}\). 35-41). Rescarchers selected public MySpace profiles of people who described themselves as between 18 and 20 years old and who referenced sex or substance use (alcohol or drugs) in their profiles. The selected subjects were assigned at random to an intervention group or a control group. Those in the intervention group were sent an c-mail from a physician about the risks associated with having a public profile and of referencing sex or substance use in their profile. Three months later, networking sites were revisited to see if any changes had been made. The following excerpt is from the paper: a. The quote from the paper references four hypothesis tests. For each test, indicate what hypotheses you think were tested and whether or not the null hypothesis was rejected. b. Based on the information provided by the hypothesis tests, what conclusions can be drawn about the effectiveness of the e-mail intervention?

Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse types ("Comparative Study of Two Computer Mouse Designs." Cornell Human Factors Laboratory Technical Report RP7992). The difference in wrist extension was computed by subtracting extension for mouse type \(\mathrm{B}\) from the wrist extension for mouse type A for each student. The mean difference was reported to be \(8.82\) degrees. Assume that it is reasonable to regard this sample of 24 people as representative of the population of computer users. a. Suppose that the standard deviation of the differences was 10 degrees. Is there convincing evidence that the mean wrist extension for mouse type \(\mathrm{A}\) is greater than for mouse type B? Use a .05 significance level. b. Suppose that the standard deviation of the differences was 26 degrees. Is there convincing evidence that the mean wrist extension for mouse type \(\mathrm{A}\) is greater than for mouse type B? Use a .05 significance level. c. Briefly explain why a different conclusion was reached in the hypothesis rests of Parts (a) and (b).

The positive effect of water fluoridation on dental health is well documented. One study that validates this is described in the article "Impact of Water Fluoridation on Children's Dental Health: A Controlled Study of Two Pennsylvania Communities" (American Statistical Association Proceedings of the Social Statistics Section [1981]: 262-265). Two communities were compared. One had adopted fluoridation in 1966 , whereas the other had no such program. Of 143 randomly selected children from the town without fluoridated water, 106 had decayed reeth, and 67 of 119 randomly selected children from the town with fluoridated water had decayed teeth. Let \(p_{1}\) denote proportion of all children in the community with fluoridated water who have decayed teeth, and let \(p_{2}\) denote the analogous proportion for children in the community with unfluoridated water. Estimate \(p_{1}-p_{2}\) using a \(90 \%\) confidence interval. Does the interval contain 0 ? Interpret the interval.

Some commercial airplanes recirculate approximately \(50 \%\) of the cabin air in order to increase fuel efficiency. The authors of the paper "Aircraft Cabin Air Redrculation and Symptoms of the Common Cold" (journal of the American Medical Association [2002]: 483-486) studied 1100 airline passengers who flew from San Francisco to Denver between January and April 1999\. Some passengers traveled on airplanes that recirculated air and others traveled on planes that did not recirculate air. Of the 517 passengers who flew on planes that did not recirculate air, 108 reported post-flight respiratory symptoms, while 111 of the 583 passengers on planes that did recirculate air reported such symptoms. Is there sufficient evidence to conclude that the proportion of passengers with post-flight respiratory symptoms differs for planes that do and do not recirculate air? Test the appropriate hypotheses using \(\alpha=.05\). You may assume that it is reasonable to regard these two samples as being independently selected and as representative of the two populations of interest.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.