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The true average diameter of ball bearings of a certain type is supposed to be \(0.5\) inch. What conclusion is appropriate when testing \(H_{0}: \mu=0.5\) versus \(H_{a}: \mu \neq\) \(0.5\) inch each of the following situations: a. \(n=13, t=1.6, \alpha=.05\) b. \(n=13, t=-1.6, \alpha=.05\) c. \(n=25, t=-2.6, \alpha=.01\) d. \(\quad n=25, t=-3.6\)

Short Answer

Expert verified
Based on the provided t-values and levels of significance: \n a) Not enough evidence to reject \(H_{0}\). The average diameter of ball bearings can be 0.5 inches. \n b) Not enough evidence to reject \(H_{0}\). The average diameter of ball bearings can be 0.5 inches. \n c) Not enough evidence to reject \(H_{0}\). The average diameter of ball bearings can be 0.5 inches. \n d) Reject \(H_{0}\). Evidence suggests the average diameter of ball bearings is not 0.5 inches.

Step by step solution

01

For the first case (a)

Find the critical value of t for a two-sided test at \(\alpha=.05\) level with (n-1) = 12 degrees of freedom. Using a t-distribution table or appropriate statistical software, the critical value is approximately ±2.1788. Comparing with the absolute value of t (=|1.6|), we find that 1.6 is less than 2.1788, so we do not reject \(H_{0}\) at this level of significance and conclude that the evidence is not strong enough to argue that the average diameter is different from 0.5 inches.
02

For the second case (b)

With the same degrees of freedom and \(\alpha\), but for t = -1.6, the conclusion is essentially the same because the absolute value of t is taken. So, the negative sign does not affect the overall decision. We still fail to reject \(H_{0}\).
03

For the third case (c)

Here, n=25 (degrees of freedom = 24) and \(\alpha=.01\). The two-sided critical value for this scenario is approximately ±2.797 (from a t-distribution table). The computed t statistic |-2.6| is less than 2.797, so we again cannot reject \(H_{0}\).
04

For the fourth case (d)

Assuming \(\alpha=.05\) for this case (since it is not provided) and having 24 degrees of freedom (n=25), the critical value is approximately ±2.064. Here, the test statistic |-3.6| is greater than 2.064, so we reject the null hypothesis and conclude that the evidence strongly suggests the average diameter is not 0.5 inches.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-distribution
In hypothesis testing, the t-distribution is essential, especially when dealing with smaller sample sizes. Unlike the normal distribution, the t-distribution is used when the population standard deviation is unknown. It helps in inferencing about the population mean.

The t-distribution is characterized by its shape, which varies according to the degrees of freedom. With fewer degrees of freedom, it tends to have heavier tails than the normal distribution. This characteristic allows for a better estimation of the mean in small samples.

As the sample size increases, the t-distribution approaches the normal distribution.
  • Crucial for smaller samples when compared to large datasets.
  • Utilizes sample data to estimate population parameters.
  • Changes shape depending on the degrees of freedom.
When conducting a t-test, we compare the calculated t statistic against critical t values from the t-distribution table. This helps determine if the observed data significantly differ from the null hypothesis.
significance level
In hypothesis testing, the significance level, denoted by \(\alpha\), is a threshold we use to decide whether to reject the null hypothesis. It represents the probability of making a Type I error, which means rejecting a true null hypothesis.

A common significance level is \(0.05\) or \(5\%\). This implies that we accept a \(5\%\) chance of incorrectly rejecting the null hypothesis. In specific cases, a more stringent level like \(0.01\) is used to minimize the risk of error even further.

When a test statistic falls within the critical region defined by \(\alpha\), we reject the null hypothesis. If it falls outside, we fail to reject it, thus staying within the accepted range of values.
  • Defines threshold for statistical significance.
  • Helps control the likelihood of false positives.
  • A lower \(\alpha\) increases confidence in results but reduces sensitivity.
Choosing the right significance level is crucial as it recounts the balance between being cautious about Type I errors and having meaningful, decisive tests.
degrees of freedom
Degrees of freedom (df) refer to the number of independent values or quantities which can be assigned to a statistical distribution. It plays a significant role, especially when working with estimates derived from samples.

In the t-distribution, degrees of freedom are calculated as \(n-1\), where \(n\) is the sample size. Essentially, it accounts for the number of values that can vary while keeping the sample mean constant.

As the degrees of freedom increase, the shape of the t-distribution becomes more like the normal distribution. This means greater precision in the estimation.
  • Important for determining the correct shape of the t-distribution.
  • Calculated easily as \(n-1\).
  • Affects the width of confidence intervals and the critical values for hypothesis tests.
Understanding degrees of freedom is crucial for interpreting the t-test results accurately and drawing reliable conclusions about the population mean.
null hypothesis
The null hypothesis is a central concept in hypothesis testing. It is typically denoted as \(H_0\) and represents a statement of 'no effect' or 'no difference.' In the given exercise, it states that the average diameter of ball bearings is \(0.5\) inches.

Testing involves determining whether there is enough evidence to reject \(H_0\) in favor of the alternative hypothesis, \(H_a\). This alternative suggests a difference or effect, like the mean diameter being different from \(0.5\) inches.

During testing, statistical data is evaluated to decide whether they significantly deviate from what \(H_0\) suggests.
  • Primary hypothesis tested in statistical experiments.
  • Typically signifies no change or effect.
  • Rejection leads to acceptance of evidence against \(H_0\).
The null hypothesis provides a basis for comparing the observed data to what we would expect if no significant effect or difference exists. It helps maintain an objective viewpoint when analyzing data and making deductions.

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Most popular questions from this chapter

A television manufacturer claims that (at least) \(90 \%\) of its TV sets will need no service during the first 3 years of operation. A consumer agency wishes to check this claim, so it obtains a random sample of \(n=100\) purchasers and asks each whether the set purchased needed repair during the first 3 years after purchase. Let \(\hat{p}\) be the sample proportion of responses indicating no repair (so that no repair is identified with a success). Let \(p\) denote the actual proportion of successes for all sets made by this manufacturer. The agency does not want to claim false advertising unless sample evidence strongly suggests that \(p<.9\). The appropriate hypotheses are then \(H_{0}: p=.9\) versus \(H_{a}: p<.9\). a. In the context of this problem, describe Type I and Type II errors, and discuss the possible consequences of each. b. Would you recommend a test procedure that uses \(\alpha=.10\) or one that uses \(\alpha=.01 ?\) Explain.

The power of a test is influenced by the sample size and the choice of significance level. a. Explain how increasing the sample size affects the power (when significance level is held fixed). b. Explain how increasing the significance level affects the power (when sample size is held fixed).

Do state laws that allow private citizens to carry concealed weapons result in a reduced crime rate? The author of a study carried out by the Brookings Institu-tion is reported as saying, "The strongest thing I could say is that I don't see any strong evidence that they are reducing crime" (San Luis Obispo Tribune, January \(23 .\) 2003). a. Is this conclusion consistent with testing \(H_{0}:\) concealed weapons laws reduce crime versus \(H_{a}:\) concealed weapons laws do not reduce crime or with testing \(H_{0}:\) concealed weapons laws do not reduce crime versus \(H_{a}:\) concealed weapons laws reduce crime Explain. b. Does the stated conclusion indicate that the null hypothesis was rejected or not rejected? Explain.

Give as much information as you can about the \(P\) -value of a \(t\) test in each of the following situations: a. Two-tailed test, \(\mathrm{df}=9, t=0.73\) b. Upper-tailed test, \(\mathrm{df}=10, t=-0.5\) c. Lower-tailed test, \(n=20, t=-2.1\) d. Lower-tailed test, \(n=20, t=-5.1\) e. Two-tailed test, \(n=40, t=1.7\)

A certain television station has been providing live coverage of a particularly sensational criminal trial. The station's program director wishes to know whether more than half the potential viewers prefer a return to regular daytime programming. A survey of randomly selected viewers is conducted. Let \(p\) represent the proportion of all viewers who prefer regular daytime programming. What hypotheses should the program director test to answer the question of interest?

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