/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 The eating habits of 12 bats wer... [FREE SOLUTION] | 91Ó°ÊÓ

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The eating habits of 12 bats were examined in the article "Foraging Behavior of the Indian False Vampire Bat" (Biotropica \([1991]: 63-67) .\) These bats consume insects and frogs. For these 12 bats, the mean time to consume a frog was \(\bar{x}=21.9 \mathrm{~min}\). Suppose that the standard deviation was \(s=7.7 \mathrm{~min} .\) Construct and interpret a \(90 \%\) confidence interval for the mean suppertime of a vampire bat whose meal consists of a frog. What assumptions must be reasonable for the one-sample \(t\) interval to be appropriate?

Short Answer

Expert verified
The 90% confidence interval for the mean time it takes for a vampire bat to consume a frog is approximately (18.0 minutes, 25.8 minutes). We are 90% confident that the true mean time lies within this range. The assumptions necessary for this interval to be valid include a random sample and an approximately normal distribution or a large enough sample size for the Central Limit Theorem to apply.

Step by step solution

01

Identify the given data

From the exercise, it's given that the sample mean, denoted as \(\bar{x}\), is 21.9 minutes, the standard deviation, denoted as \(s\), is 7.7 minutes, and the sample size, denoted as \(n\), is 12 bats. The confidence level is 90%.
02

Find the critical value

The critical value can be found using a t-distribution table. Given that the confidence level is 90% and the degrees of freedom is \(n-1 = 12 - 1 = 11\), the critical value (t*) for a two-tailed test is approximately 1.796.
03

Compute the Confidence Interval

The confidence interval is computed using the formula \(\bar{x} \pm t^* \cdot \frac{s}{\sqrt{n}}\). Substituting the given values, the confidence interval is \(21.9 \pm 1.796 \cdot \frac{7.7}{\sqrt{12}}\), which approximately equals \(21.9 \pm 3.91\), hence, the interval is (18.0, 25.8).
04

Interpret the result

The interpretation of the confidence interval is as follows: We are 90% confident that the mean time it takes for a vampire bat to consume a frog lies between 18.0 and 25.8 minutes.
05

Discuss Assumptions

The assumptions that need to be made for this one-sample t interval to be appropriate are: 1. The sample is random. 2. The distribution of the eating time is approximately normal or the sample size is large enough so that the Central Limit Theorem applies. Under these conditions, the calculation will provide a valid confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-distribution
The t-distribution is a fundamental tool when working with small sample sizes, like our 12 bats. It's especially useful for estimating population parameters when the standard deviation is unknown. Unlike the normal distribution, the t-distribution has thicker tails, allowing it to account for more variability when sample sizes are small. This characteristic makes the t-distribution crucial for constructing confidence intervals when the sample size is less than about 30. In our exercise, with 11 degrees of freedom (since degrees of freedom = number of samples - 1), we used the t-distribution to find the critical value. This critical value is essential in determining the range of our confidence interval, capturing the variability in our small sample with more accuracy than the normal distribution would.
Central Limit Theorem
The Central Limit Theorem (CLT) is a powerful statistical concept that helps us understand why and how we can make inferences about population means. It states that as the sample size becomes large, the distribution of the sample mean will approach a normal distribution, regardless of the original population distribution. While our sample size of 12 is relatively small, CLT assures us that the sample mean is approximately normally distributed, especially if the population distribution isn't too far from normal. This assumption allows us to use the t-distribution to calculate a confidence interval. It tells us that even with smaller samples, we can make reliable inferences about the population mean with the knowledge that the sample mean tends to behave predictably.
standard deviation
Standard deviation is a measure of how spread out the data points in a sample are around the mean. In the bat exercise, we found that the standard deviation was 7.7 minutes, indicating quite a bit of variability in how long bats take to eat a frog. This variability affects our confidence interval. A larger standard deviation means the data points are more spread out, making the interval wider to account for this uncertainty. When calculating the confidence interval, standard deviation plays a critical role in the formula: \[ CI = \bar{x} \pm t^* \frac{s}{\sqrt{n}} \]Where \(s\) is the standard deviation. This calculation essentially balances our need for precision against the natural variability in the data.
sample mean
The sample mean, denoted by \(\bar{x}\), serves as an estimate of the population mean. In our case, the sample mean was 21.9 minutes, representing the average time bats took to consume a frog. It's a central piece of our analysis because it acts as the midpoint in our confidence interval formula. The formula \[ CI = \bar{x} \pm t^* \frac{s}{\sqrt{n}} \]relies heavily on the sample mean to provide the starting point for our range. Since it's based on the sample, not the entire population, it's an approximation, but a well-calculated one due to the properties of the Central Limit Theorem and the choice of using a t-distribution. The sample mean gives us a practical way to estimate an overall average time, despite having data from only a small subset of the entire population.

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Most popular questions from this chapter

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