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91Ó°ÊÓ

Suppose that \(65 \%\) of all registered voters in a certain area favor a 7 -day waiting period before purchase of a handgun. Among 225 randomly selected voters, what is the probability that a. At least 150 favor such a waiting period? b. More than 150 favor such a waiting period? c. Fewer than 125 favor such a waiting period?

Short Answer

Expert verified
The probabilities that a. At least 150 voters favor such a waiting period is approximately 0.2999, b. More than 150 voters favor such a waiting period is approximately 0.2468, c. Fewer than 125 voters favor such a waiting period is approximately 0.0015. These are approximations using normal distribution and actual values may differ slightly.

Step by step solution

01

Normal Approximation Criteria

Verify if binsize * probability * (1 - probability) is greater than 5. If true, we can apply the normal approximation. For our case: \(225 * 0.65 * 0.35 = 51.1875\), so we can apply the normal approximation.
02

Calculate Mean and Standard Deviation

Calculate mean (\(mu\)) and standard deviation (\(sigma\)) of the distribution using formulas: \(mu = n*p\) and \(sigma = sqrt(n*p*(1 - p)\). where n is the number of trials (voters here - 225), p is the probability (0.65 in this case). Mean, \(mu = 225 * 0.65 = 146.25\) and Standard deviation, \(sigma = sqrt(225 * 0.65 * 0.35) = 7.153\).
03

Convert to Z-Scores

Convert the given numbers (150, 151, and 125) into z-scores using formula: \(z = (X - mu) / sigma\). z-score for 150 voters: \(z = (150 - 146.25) / 7.153 = 0.526\), for 151 voters: \(z = (151 - 146.25) / 7.153 = 0.664\) and for 125 voters: \(z = (125 - 146.25) / 7.153 = -2.97\).
04

Find Probabilities Using Z-Table

a. For 'at least 150 voters'', we are looking for \(P(X >= 150)\) or \(1 - P(z < 0.526)\) which equals to \(1 - 0.7001 = 0.2999\). b. For 'more than 150 voters', we are interested in \(P(X > 150)\) which equals to \(P(z > 0.664)\) and equals to \(1 - P(z < 0.664) = 1 - 0.7532 = 0.2468\). c. For 'fewer than 125 voters', we need to find \(P(X < 125)\) or \(P(z < -2.97)\) equals to 0.0015.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a measure of the likelihood that a particular event will occur. It is a fundamental concept in statistics used to understand how likely something is to happen given a certain set of circumstances. In our example, we are dealing with the probability of a voter favoring a 7-day waiting period before purchasing a handgun. The probability provided here is 65%, or 0.65.

When calculating probabilities, you may often deal with events that involve several trials. Such events are commonly referred to as repeated trials or multiple events, and they can be modeled using different probability distributions. These distributions help us to find probabilities of various outcomes. In cases with a large number of trials, like surveying 225 voters, approximations using normal distribution can be applied for more complex probability calculations.
  • The probability value of an event ranges from 0 to 1, with 0 meaning it's impossible and 1 meaning it's certain.
  • Probabilities can also be described in terms of percentages, e.g.,a 0.65 probability is the same as saying there is a 65% chance.
  • For individual events following the binomial model, the sum of probabilities of all possible outcomes should always equal 1.
Binomial Distribution
The binomial distribution is a common discrete probability distribution that describes the number of successes in a fixed number of independent trials, each with the same probability of success. In simpler terms, it’s a way to calculate the probability of achieving a set number of successes out of a set number of attempts.

For this exercise, the total number of trials is 225 (the number of voters), and the probability of success (a voter favoring the waiting period) for each trial is 0.65. The binomial distribution can model scenarios with these characteristics perfectly because each voter's opinion can be thought of as a separate trial with two possible outcomes: favoring or not favoring the waiting period.
  • The formula for finding the probability of exactly "k" successes in "n" trials is given by: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]

  • Here, \(\binom{n}{k}\) represents the combinations of "k" successes out of "n" trials.
  • The binomial distribution assumes all trials are independent and the probability of success remains constant.
Standard Deviation
Standard deviation is a measure of how spread out numbers are in a data set. Specifically, it quantifies the amount of variation or dispersion from the average (mean) in a distribution. In the context of probability, understanding the standard deviation helps us to comprehend how much variability is expected in the number of voters who favor the waiting period.

For a binomial distribution, the standard deviation is calculated using the formula: \[ \sigma = \sqrt{n \times p \times (1 - p)} \]. This formula tells us how much the number of successes (voters favoring the waiting period) can be expected to vary around the mean number of successes. In our case, the calculated standard deviation is 7.153 for the 225 voters.
  • A higher standard deviation indicates a greater spread of values. Lower suggests most values are close to the mean.
  • Standard deviation is especially useful in normal approximation as it helps transform raw scores into z-scores.
  • Z-scores allow you to find probabilities that specific values will occur by referring to the standard normal distribution.

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Most popular questions from this chapter

A city ordinance requires that a smoke detector be installed in all residential housing. There is concern that too many residences are still without detectors, so a costly inspection program is being contemplated. Let \(\pi\) be the proportion of all residences that have a detector. A random sample of 25 residences is selected. If the sample strongly suggests that \(\pi<.80\) (less than \(80 \%\) have detectors), as opposed to \(\pi \geq .80\), the program will be implemented. Let \(x\) be the number of residences among the 25 that have a detector, and consider the following decision rule: Reject the claim that \(\pi=.8\) and implement the program if \(x \leq 15\). a. What is the probability that the program is implemented when \(\pi=.80\) ? b. What is the probability that the program is not implemented if \(\pi=.70 ?\) if \(\pi=.60 ?\) c. How do the "error probabilities" of Parts (a) and (b) change if the value 15 in the decision rule is changed to 14 ?

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