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Twenty-five percent of the customers entering a grocery store between 5 P.M. and 7 P.M. use an express checkout. Consider five randomly selected customers, and let \(x\) denote the number among the five who use the express checkout. a. What is \(p(2)\), that is, \(P(x=2)\) ? b. What is \(P(x \leq 1)\) ? c. What is \(P(2 \leq x)\) ? (Hint: Make use of your computation in Part (b).) d. What is \(P(x \neq 2) ?\)

Short Answer

Expert verified
The answer involves four parts as it's a multi-part problem: Part a, compute the binomial probability with \(x=2\); Part b, sum the probabilities for \(x=0\) and \(x=1\); Part c, subtract the result from Part b from 1; And for Part d, subtract computation from part a from 1.

Step by step solution

01

Calculation for Part a

To calculate \(P(x=2)\), we'll use the binomial distribution probability formula, with \(n=5\), \(x=2\), and \(p=0.25\). The formula becomes \(P(2; 5, 0.25) = C(5, 2) * 0.25^2 * (1 - 0.25)^{5 - 2}\). Doing the calculation gives the answer for Part a.
02

Calculation for Part b

Part b asks for \(P(x \leq 1)\), which means the probability that either 0 or 1 customer uses the express checkout. In this case, we can calculate the sum of the binomial probabilities for \(x=0\) and \(x=1\) over the 5 customers. This requires two sub-calculations: \(P(0; 5, 0.25) = C(5, 0) * 0.25^0 * (1 - 0.25)^{5 - 0}\) and \(P(1; 5, 0.25) = C(5, 1) * 0.25^1 * (1 - 0.25)^{5 - 1}\). Add these two probabilities to get the answer for Part b.
03

Calculation for Part c

This requires calculation for \(P(2 \leq x)\), that is the probability that at least 2 customers use the express checkout. This computation can be reduced by 1-the probability computed in Part b (because the sum of all probabilities equals 1). So, \(P(2 \leq x)= 1 -P(x \leq 1)\). This opposite event method helps us avoid calculating each individual probability for \(x = 2,3,4,5\).
04

Calculation for Part d

To solve for \(P(x \neq 2)\), we can use the concept of complementary probability again. This event is the opposite of \(x = 2\), so we can compute this probability by \(P(x \neq 2) = 1 - P(x = 2)\), where \(P(x = 2)\) was calculated in part a.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the mathematical framework for predicting the likelihood of different outcomes in a random experiment. It provides tools to quantify and compute these probabilities. One essential component is the understanding of random variables and their distributions. In this example, the problem revolves around using express checkout, which can be modeled using a binomial distribution.

A binomial distribution is utilized when you have a fixed number of trials (like our five customers), two possible outcomes (express checkout or not), and a constant probability of success (0.25 in this case). Calculating probabilities in a binomial setting often involves using the binomial coefficient, which represents the number of ways to choose a specific number of successes from the total number of trials.
  • Calculate possible outcomes using binomial coefficients.
  • Use formulas to find probabilities for exact outcomes or ranges (such as using express checkout exactly twice).
Express Checkout Usage
Express checkout usage in this context refers to a customer's decision to use the express line, which is a scenario common in probability questions. Here, express checkout acts as a binary variable, where a customer either uses it or not.

The probability in our problem is given as 0.25 or 25%, indicating one fourth of the randomly selected customers would typically use this line. Understanding the nature of express checkout usage involves recognizing that it mirrors other similar probability events where each event is independent, meaning one customer's choice doesn't affect another's. These independent events allow for using a binomial distribution.
  • Identifies the usage rate with given probability (25%).
  • Independent choices allow for simple probability assumptions and models.
Complementary Probability
Complementary probability refers to calculating the likelihood of the occurrence of events by considering their opposite. In probability theory, the sum of the probabilities of all outcomes must equal 1.

For instance, to find the probability of at least two customers using the express checkout \(P(2 \leq x)\), we subtract the probability of fewer than two customers \(P(x \leq 1)\) from 1, as these are complementary events. This method is efficient when directly calculating probabilities for numerous outcomes is complex:
  • Provides a shortcut to calculate difficult probabilities.
  • Utilizes the fundamental total probability rule where \(P(A) + P(A^c) = 1\).
Random Variables
Random variables are a foundational concept in probability theory. They represent numerical outcomes from random processes. Here, the random variable \(x\) stands for the number of customers using express checkout.

Random variables can take on different values depending on the outcome of the underlying random process. For each specific value of \(x\), the probability is calculated using binomial distribution principles. Often, these probabilities are used to make further predictions or inferences about the population or process:
  • Represents possible scenarios in a structured way, adhering to defined probabilities.
  • Makes calculations intuitive and manageable through statistical rules.

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Most popular questions from this chapter

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