/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Airlines sometimes overbook flig... [FREE SOLUTION] | 91Ó°ÊÓ

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Airlines sometimes overbook flights. Suppose that for a plane with 100 seats, an airline takes 110 reservations. Define the variable \(x\) as the number of people who actually show up for a sold-out flight. From past experience, the probability distribution of \(x\) is given in the following table: $$ \begin{array}{lrrrrrrrr} x & 95 & 96 & 97 & 98 & 99 & 100 & 101 & 102 \\ p(x) & .05 & .10 & .12 & .14 & .24 & .17 & .06 & .04 \\ x & 103 & 104 & 105 & 106 & 107 & 108 & 109 & 110 \\ p(x) & .03 & .02 & .01 & .005 & .005 & .005 & .0037 & .0013 \end{array} $$ a. What is the probability that the airline can accommodate everyone who shows up for the flight? b. What is the probability that not all passengers can be accommodated? c. If you are trying to get a seat on such a flight and you are number 1 on the standby list, what is the probability that you will be able to take the flight? What if you are number 3 ?

Short Answer

Expert verified
a. The probability that the airline can accommodate everyone who shows up for the flight is 0.92. b. The probability that not all passengers can be accommodated is 0.08. c. If you are trying to get a seat on such a flight and you are number 1 on the standby list, the probability that you will be able to take the flight is 0.92. If you are number 3 on the list, the probability that you can take the flight is 0.41.

Step by step solution

01

Probability that the airline can accommodate everyone

We need to add all the probabilities for \(x\) from 95 to 100, as they represent situations where every passenger can be accommodated. So, the probability = \(p(95) + p(96) + p(97) + p(98) + p(99) + p(100) = 0.05 + 0.10 + 0.12 + 0.14 + 0.24 + 0.17 = 0.92\).
02

Probability that not all passengers can be accommodated

As the total probability should be 1, the probability that the airline can't accommodate everyone = \(1 - p(\text{can accommodate everyone}) = 1 - 0.92 = 0.08\).
03

Probability number 1 on the standby list can take the flight

A person on the standby list can only take the flight if there are 100 or fewer people show up. Hence, this is the same as the probability calculated in Step 1.
04

Probability that person number 3 on the standby list can take the flight

The person at number 3 on the list can take the flight if 98 or fewer people show up. Therefore, we add up the probabilities for x from 95 to 98. So, the probability = \(p(95) + p(96) + p(97) + p(98) = 0.05 + 0.10 + 0.12 + 0.14 = 0.41\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Overbooking Flights
Overbooking flights is a common practice among airlines to compensate for the fact that not all passengers who have reservations will show up. It's a calculated risk, as they predict the no-show rate based on historical data. However, what happens when more passengers show up than there are seats available?

Airline companies use probability distribution to decide how much to overbook. They aim to maximize their profits while minimizing the chance of having to deny boarding to passengers. When analyzing overbooking, it's crucial to consider the cost of bumping passengers versus the cost of flying with empty seats.

To illustrate, let's assume an airline overbooks by 10 seats for a 100-seat flight, expecting some passengers not to arrive. They create a probability distribution for the expected number of show-ups. This distribution helps them to estimate the chances they can accommodate everyone and the risk they take with the overbooked seats.
Binomial Probability
Binomial probability is a type of probability that applies to situations where there are two possible outcomes - often classified as 'success' or 'failure'. In our flight example, a 'success' can be defined as a passenger showing up for the flight, while a 'failure' would be a passenger not showing up.

In binomial probability calculations, we have three key components: the number of trials, the probability of success in each trial, and the total number of successes we're interested in. The assumptions are that each passenger’s decision to show up is independent of the others, and the probability of showing up remains constant across trials.

The situation with the overbooked flight fits into this framework since we have a fixed number of passengers (trials), and we are interested in the number that turns up (successes) with a certain probability.
Probability Calculations
Probability calculations in overbooking scenarios involve summing the probabilities of individual outcomes to find the total likelihood of an event. For instance, to find out the probability that all passengers can be accommodated, we consider the sum of all probabilities where the number of show-ups is less than or equal to the number of seats.

This is calculated by adding the individual probabilities for every number of passengers from the minimum expected up to the capacity of the plane. As shown in the exercise, the probability is the sum of the probabilities from 95 to 100 arriving passengers. On the other hand, the complementary probability that not all passengers will be accommodated is simply 1 minus the probability that they all can be accommodated.

Understanding these calculations is essential for both airlines in managing risks and for passengers who might be curious about the likelihood of getting a seat, especially if they're on a standby list, where their probability of getting on the plane decreases the further down the list they are.

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