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91Ó°ÊÓ

In a small city, approximately \(15 \%\) of those eligible are called for jury duty in any one calendar year. People are selected for jury duty at random from those eligible, and the same individual cannot be called more than once in the same year. What is the probability that a particular eligible person in this city is selected two years in a row? three years in a row?

Short Answer

Expert verified
The probability that an eligible person is selected for jury duty two years in a row is \(0.0225\) and three years in a row is \(0.003375\).

Step by step solution

01

Understand the given situation and the probability for each independent event

The probability of a person being called for jury duty in a particular year is \(15\%\) or \(0.15\). Given that the individual cannot be called more than once in the same year, each year's selection is an independent event.
02

Apply the multiplication rule for independent events for two years

The probability of two independent events A and B happening is given by P(A and B) = P(A) * P(B). In this case, both probabilities are \(0.15\). So, P(person selected two years in a row) = P(selected in first year) * P(selected in the second year) = \(0.15 * 0.15 = 0.0225\).
03

Apply the multiplication rule for independent events for three years

The same rule can be applied for three years. So, P(person selected three years in a row) = P(selected in first year) * P(selected in the second year) * P(selected in the third year) = \(0.15 * 0.15 * 0.15 = 0.003375\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability, understanding independent events is crucial. Independent events are those where the occurrence of one event does not affect the probability of the other. For instance, consider two coin flips. Each flip is independent of the previous one, meaning the result of the first flip has no effect on the outcome of the second flip. The same rule applies when selecting people for jury duty across different years in the given exercise. If a person is selected one year, it does not influence whether they'll be selected in subsequent years.

Here's why: Candidates are chosen randomly, and previous selections do not alter their chances in future draws. This randomness and lack of influence from previous events confirm the independence of each year's selection. Thus, when calculating the probability of sequential selections, we assume independence.
Multiplication Rule
The multiplication rule is a key principle in calculating probabilities for independent events. This rule states that if you want to find the probability of two (or more) independent events happening together, you multiply their individual probabilities.

Consider an example where we want to know the probability of rolling a 3 on two consecutive rolls with a fair six-sided die. Each independent roll has a probability of \( \frac{1}{6} \). By applying the multiplication rule, you multiply these probabilities: \( \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \).

In the exercise, the probability of a person being chosen for jury duty in any single year is 0.15. To find the probability of being selected for two consecutive years, you'd calculate: \( 0.15 \times 0.15 = 0.0225 \). If you extend this to three years, you continue multiplying 0.15 for each additional year: \( 0.15 \times 0.15 \times 0.15 = 0.003375 \).

This simplicity and clarity in the process make the multiplication rule highly useful for handling multiple independent events.
Probability Calculation
Probability calculation often begins with understanding the total number of outcomes and desired outcomes. In simple terms, probability is the chance or likelihood of an event happening among all possible outcomes.

The formula to calculate basic probability is: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \]

For example, if the probability of being selected for jury duty is given as 15%, it means there is a 0.15 probability each year. To determine more complex scenarios, such as being selected for consecutive years, you'd utilize both the concept of independent events and the multiplication rule to refine these probability calculations. In the given scenario, calculating the probability over multiple years involved understanding how individual yearly probabilities contribute to the overall likelihood of being chosen consecutively. By handling such calculations carefully, you not only arrive at the correct answer but also enhance your comprehension of probability theory as a whole.

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Most popular questions from this chapter

A mutual fund company offers its customers several different funds: a money market fund, three different bond funds, two stock funds, and a balanced fund. Among customers who own shares in just one fund, the percentages of customers in the different funds are as follows: \(\begin{array}{lr}\text { Money market } & 20 \% \\ \text { Short-term bond } & 15 \% \\ \text { Intermediate-term bond } & 10 \% \\ \text { Long-term bond } & 5 \% \\ \text { High-risk stock } & 18 \% \\ \text { Moderate-risk stock } & 25 \% \\ \text { Balanced fund } & 7 \%\end{array}\) A customer who owns shares in just one fund is to be selected at random. a. What is the probability that the selected individual owns shares in the balanced fund? b. What is the probability that the individual owns shares in a bond fund? c. What is the probability that the selected individual does not own shares in a stock fund?

The article "Anxiety Increases for Airline Passengers After Plane Crash" (San Luis Obispo Tribune, November 13,2001 ) reported that air passengers have a 1 in 11 million chance of dying in an airplane crash. This probability was then interpreted as "You could fly every day for 26,000 years before your number was up." Comment on why this probability interprctation is mislcading.

After all students have left the classroom, a statistics professor notices that four copies of the text were left under desks. At the beginning of the next lecture, the professor distributes the four books at random to the four stu- dents \((1,2,3\), and 4\()\) who claim to have left books. One possible outcome is that 1 receives 2 's book, 2 receives 4 's book, 3 receives his or her own book, and 4 receives 1 's book. This outcome can be abbreviated \((2,4,3,1)\). a. List the 23 other possible outcomes. b. Which outcomes are contained in the event that exactly two of the books are returned to their correct owners? As- suming equally likely outcomes, what is the probability of this event? c. What is the probability that exactly one of the four students receives his or her own book? d. What is the probability that exactly three receive their own books? e. What is the probability that at least two of the four students receive their own books?

A shipment of 5000 printed circuit boards contains 40 that are defective. Two boards will be chosen at random, without replacement. Consider the two events \(E_{1}=\) event that the first board selected is defective and \(E_{2}=\) event that the second board selected is defective. a. Are \(E_{1}\) and \(E_{2}\) dependent events? Explain in words. b. Let not \(E_{1}\) be the event that the first board selected is not defective (the event \(E_{1}^{C}\) ). What is \(P\left(\right.\) not \(\left.E_{1}\right)\) ? c. How do the two probabilities \(P\left(E_{2} \mid E_{1}\right)\) and \(P\left(E_{2} \mid\right.\) not \(\left.E_{1}\right)\) compare? d. Based on your answer to Part (c), would it be reasonable to view \(E_{1}\) and \(E_{2}\) as approximately independent?

USA Today (June 6,2000 ) gave information on seat belt usage by gender. The proportions in the following table are based on a survey of a large number of adult men and women in the United States: $$ \begin{array}{l|cc} \hline & \text { Male } & \text { Female } \\ \hline \text { Uses Seat Belts Regularly } & .10 & .175 \\ \begin{array}{l} \text { Does Not Use Seat Belts } \\ \text { Regularly } \end{array} & .40 & .325 \\ \hline \end{array} $$ Assume that these proportions are representative of adults in the United States and that a U.S. adult is selected at random. a. What is the probability that the selected adult regularly uses a seat belt? b. What is the probability that the selected adult regularly uses a seat belt given that the individual selected is male? c. What is the probability that the selected adult does not use a seat belt regularly given that the selected individual is female? d. What is the probability that the selected individual is female given that the selected individual does not use a seat belt regularly? e. Are the probabilities from Parts (c) and (d) equal? Write a couple of sentences explaining why this is so.

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