/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Refer to Exercise 6.18. Adding p... [FREE SOLUTION] | 91Ó°ÊÓ

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Refer to Exercise 6.18. Adding probabilities in the first row of the given table yields \(P(\) midsize \()=.45\), whereas from the first column, \(\mathrm{P}\left(4 \frac{3}{8}\right.\) in. grip) \(=.30\). Is the following true? $$ P\left(\text { midsize } \text { or } 4 \frac{3}{8} \text { in. grip }\right)=.45+.30=.75 $$ Explain.

Short Answer

Expert verified
Without further information on the relationship between these events, it cannot be definitively stated whether \(P(\text{midsize or } 4 \frac{3}{8} \text{ in. grip}) = .45 + .30 = .75\). The question hinges on whether the events are mutually exclusive or not.

Step by step solution

01

Understanding Mutually Exclusive Events

Two events are said to be mutually exclusive if they cannot both occur at the same time. In this case, if 'midsize' and '4 3/8 inch grip' are mutually exclusive, the probability of either event occurring would indeed be the sum of their individual probabilities.
02

Considering Overlapping Events

If the events can occur simultaneously, they are not mutually exclusive and we risk 'double counting' when we simply add the probabilities. In such a case, the probability of either event occurring is equal to the sum of individual probabilities minus the probability of both events occurring together.
03

Conclusion

To determine whether \(P(\text{midsize or } 4 \frac{3}{8} \text{ in. grip}) = .45 + .30 = .75\) is true, we need additional information about whether these events can occur at the same time. Without this information, we cannot definitively say if the provided equation is accurate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
In probability theory, understanding mutually exclusive events is crucial. These are events that cannot occur at the same time. For example, when flipping a coin, the result can only be heads or tails, not both—these outcomes are mutually exclusive.

Mathematically, if we have two mutually exclusive events, A and B, their combined probability is the sum of their individual probabilities: \( P(A \text{ or } B) = P(A) + P(B) \). This is known as the Addition Rule for Mutually Exclusive Events.

In the problem presented, the term 'midsize' and the specification '4 \frac{3}{8} inch grip' would be considered mutually exclusive if a tennis racket cannot be both simultaneously. If that's the case, then logically, the probability that a racket is either midsize or has a 4 \frac{3}{8} inch grip would indeed be the sum of their individual probabilities, 0.45 and 0.30, respectively.
Overlapping Events
Unlike mutually exclusive events, overlapping events can occur at the same time. These might be two characteristics that are not mutually exclusive, like a person who is both a teacher and a parent.

When dealing with overlapping events, the addition of their probabilities must account for their intersection to avoid double-counting. The correct formula in such cases is: \( P(A \text{ or } B) = P(A) + P(B) - P(A \cap B) \), where \( P(A \cap B) \) is the probability of both A and B occurring together.

In the context of our textbook problem, if the 'midsize' tennis rackets can sometimes have a '4 \frac{3}{8} inch grip', then the events overlap. The probability equation in question would not be correct unless we subtract the probability that a racket is both midsize and has a 4 \frac{3}{8} inch grip. Without that piece of information, we cannot ascertain the true probability of getting either a midsize racket or one with a 4 \frac{3}{8} inch grip.
Probability Theory
Probability theory is a mathematics branch that deals with the likelihood of different events occurring. It is foundational for various fields such as statistics, finance, and risk assessment.

The fundamental principle of probability is that the sum of probabilities for all possible outcomes in a space is 1. When it comes to events, probabilities range between 0 and 1, with 0 indicating an impossible event and 1 a certain one.

Understanding events as mutually exclusive or overlapping is essential in applying probability theory correctly. Students must recognize the type of events they are working with in problems, as this determines the mathematical approach to finding probabilities. The application of the correct formula, whether for mutually exclusive events or overlapping ones, leads to accurate solutions and greater comprehension of the complex scenarios that probability theory often deals with.

Essentially, good grasp of probability theory helps students not just in mathematics, but in making informed decisions based on likelihoods in everyday life.

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Most popular questions from this chapter

Suppose that, starting at a certain time, batteries coming off an assembly line are examined one by one to see whether they are defective (let \(\mathrm{D}=\) defective and \(\mathrm{N}=\) not defective). The chance experiment terminates as soon as a nondefective battery is obtained. a. Give five possible experimental outcomes. b. What can be said about the number of outcomes in the sample space? c. What outcomes are in the event \(E\), that the number of batteries examined is an even number?

Suppose that a box contains 25 bulbs, of which 20 are good and the other 5 are defective. Consider randoml selecting three bulbs without replacement. Let \(E\) denote the event that the first bulb selected is good, \(F\) be the event that the second bulb is good, and \(G\) represent the event that the third bulb selected is good. a. What is \(P(E)\) ? b. What is \(P(F \mid E)\) ? c. What is \(P(G \mid E \cap F)\) ? d. What is the probability that all three selected bulbs are good?

Components of a certain type are shipped to a supplier in batches of \(10 .\) Suppose that \(50 \%\) of all batches contain no defective components, \(30 \%\) contain one defective component, and \(20 \%\) contain two defective components. A batch is selected at random. Two components from this batch are randomly selected and tested. a. If the batch from which the components were selected actually contains two defective components, what is the probability that neither of these is selected for testing? b. What is the probability that the batch contains two defective components and that neither of these is selected for testing? c. What is the probability that neither component selected for testing is defective? (Hint: This could happen with any one of the three types of batches. A tree diagram might help.)

A mutual fund company offers its customers several different funds: a money market fund, three different bond funds, two stock funds, and a balanced fund. Among customers who own shares in just one fund, the percentages of customers in the different funds are as follows: \(\begin{array}{lr}\text { Money market } & 20 \% \\ \text { Short-term bond } & 15 \% \\ \text { Intermediate-term bond } & 10 \% \\ \text { Long-term bond } & 5 \% \\ \text { High-risk stock } & 18 \% \\ \text { Moderate-risk stock } & 25 \% \\ \text { Balanced fund } & 7 \%\end{array}\) A customer who owns shares in just one fund is to be selected at random. a. What is the probability that the selected individual owns shares in the balanced fund? b. What is the probability that the individual owns shares in a bond fund? c. What is the probability that the selected individual does not own shares in a stock fund?

A transmitter is sending a message using a binary code, namely, a sequence of 0's and 1's. Each transmitted bit \((0\) or 1\()\) must pass through three relays to reach the receiver. At each relay, the probability is \(.20\) that the bit sent on is different from the bit received (a reversal). Assume that the relays operate independently of one another: transmitter \(\rightarrow\) relay \(1 \rightarrow\) relay \(2 \rightarrow\) relay \(3 \rightarrow\) receiver a. If a 1 is sent from the transmitter, what is the probability that a 1 is sent on by all three relays? b. If a 1 is sent from the transmitter, what is the probability that a 1 is received by the receiver? (Hint: The eight experimental outcomes can be displayed on a tree diagram with three generations of branches, one generation for each relay.)

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