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Consider the chance experiment in which both tennis racket head size and grip size are noted for a randomly selected customer at a particular store. The six possible outcomes (simple events) and their probabilities are displayed in the following table: a. The probability that grip size is \(4 \frac{1}{2}\) in. (event \(\mathrm{A}\) ) is $$ P(A)=P\left(O_{2} \text { or } O_{5}\right)=.20+.15=.35 $$ How would you interpret this probability? b. Use the result of Part (a) to calculate the probability that grip size is not \(4 \frac{1}{2}\) in. c. What is the probability that the racket purchased has an oversize head (event \(B\) ), and how would you interpret this probability? d. What is the probability that grip size is at least \(4 \frac{1}{2}\) in.?

Short Answer

Expert verified
The probabilities are as follows: a) There is a 35% chance that a randomly selected customer will choose a grip size of \(4 \frac{1}{2}\) in. b) There's a 65% chance a customer will choose a racket with a grip size not equal to \(4 \frac{1}{2}\) in. c) The probability \(P(B)\) is the chance that a customer will choose an oversize head racket. d) The probability \(P(C)\) is the chance a customer will choose a racket with a grip size of \(4 \frac{1}{2}\) in. or more. Exact numerical values for \(P(B)\) and \(P(C)\) depend on the missing values in the question.

Step by step solution

01

Interpret the Probability of Event A

The question asks to interpret \(P(A)=.35\). This stands for 'The probability that grip size is \(4 \frac{1}{2}\) inches is 0.35'. Interpretation: There is a 35% chance that a randomly selected customer at the store will choose a tennis racket with a grip size of \(4 \frac{1}{2}\) inches.
02

Calculate the Probability of the complement of Event A

The complement of an event A (denoted \(A'\)) consists of all outcomes not in A. So, to calculate the probability that grip size is not \(4 \frac{1}{2}\) inches, we subtract \(P(A)\) from 1: \(P(A') = 1 - P(A) = 1 - 0.35 = 0.65\). So there's a 65% chance a randomly selected customer will choose a racket with a grip size not equal to \(4 \frac{1}{2}\) inches.
03

Determine the Probability of Event B

The problem might give the probabilities for event B. Then, it's just a matter of summing those probabilities. Similar to Step 1, add up the probabilities of simple outcomes that result in an oversize head. Let's represent this probability as \(P(B)\). The interpretation is: there's a \(P(B)\) chance that a randomly selected customer at the store will choose a racket with an oversize head.
04

Calculate the Probability that Grip Size is at least \(4 \frac{1}{2}\) inches

Find all outcomes where the grip size is \(4 \frac{1}{2}\) inches or more and add their probabilities. Let's denote this probability by \(P(C)\). So, \(P(C)\) is the chance a randomly selected customer will choose a racket with a grip size of \(4 \frac{1}{2}\) in. or more.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chance Experiment
A chance experiment is a process or action with a variety of possible outcomes, where the result is determined randomly. Think of it like a game where you can't predict the exact ending each time you play. In our exercise, the chance experiment involves selecting a customer at a store and noting their choice in tennis racket head and grip size. Each time you perform this experiment, you might get different combinations, like different head sizes or grip sizes.

The beauty of a chance experiment lies in its unpredictability. This unpredictability is what makes it a "chance" or "random" experiment. It's important to identify all possible outcomes of the experiment before determining probabilities, as each represents a simple event. In the exercise's context, the simple events are different combinations of racket head sizes and grip sizes.
  • Unpredictability is key.
  • All outcomes are predetermined but occur randomly.
  • Outcomes are also termed as simple events.
Through this framework, probability transforms randomness into a quantifiable metric, allowing us to anticipate the likeliness of each outcome.
Event Outcome
Event outcomes are the specific results we observe after conducting a chance experiment. Each outcome has its probability of occurring. In our scenario, the outcomes concern the combination of a racket's grip size and head size. An event can be a single outcome or a combination of outcomes.

For example, if event A represents the grip size being exactly 4 ½ inches, the probability of this event can be calculated by summing the probabilities of all simple events that fall under event A.
  • The probability of an event is always a number between 0 and 1.
  • Outcomes are the basic components of events.
  • Events can sometimes be described as "favorable" outcomes for a given probability question.
Understanding the probability of event outcomes is crucial when predicting how likely an event is to occur. It's the fundamental building block of probability calculations.
Complementary Probability
Complementary probability refers to the probability of the opposite of an event happening. If you know the probability of an event occurring, you can easily find its complementary probability by subtracting the event's probability from 1. This is because the sum of the probabilities of an event and its complement is always equal to 1.

In our exercise, if there's a 35% chance (0.35 probability) that a racket with a grip size of 4 ½ inches will be chosen, then the probability of choosing a racket with a different grip size would be 1 - 0.35 = 0.65 or 65%.
  • The complement of an event is denoted as \( A' \).
  • The formula: \( P(A') = 1 - P(A) \).
  • This concept is crucial for calculations where the probability of the direct event is not readily available.
By understanding complementary probability, you can deduce missing data points and complete the picture of the scenario's probabilities.
Interpretation of Probability
Interpreting the probability of an event is about understanding what the numerical value means in real-world terms. Probability values provide a measure of how likely an event is to occur and are always expressed as numbers between 0 and 1.

For instance, if the probability of selecting a racket with a grip size of 4 ½ inches is 0.35, this translates to a 35% chance. It implies that in repeated trials of the experiment, 35% of the time, the selected racket will have a grip size of 4 ½ inches.
  • Probabilities closer to 1 indicate a higher likelihood.
  • Probabilities near 0 suggest a lesser chance.
  • Understanding probability anchor decisions, forecasts, and strategies in real-life situations.
Proper interpretation of these values gives weight to decision making, allowing prediction over random outcomes and fostering a better comprehension of data-driven scenarios.

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Most popular questions from this chapter

A certain university has 10 vehicles available for use by faculty and staff. Six of these are vans and four are cars. On a particular day, only two requests for vehicles have been made. Suppose that the two vehicles to be assigned are chosen in a completely random fashion from among the 10 . a. Let \(E\) denote the event that the first vehicle assigned is a van. What is \(P(E)\) ? b. Let \(F\) denote the probability that the second vehicle assigned is a van. What is \(P(F \mid E)\) ? c. Use the results of Parts (a) and (b) to calculate \(P(E\) and \(F)\) (Hint: Use the definition of \(P(F \mid E) .)\)

6.3 Consider the chance experiment in which the type of transmission- automatic (A) or manual (M) - is recorded for each of the next two cars purchased from a certain dealer. a. What is the set of all possible outcomes (the sample space)? b. Display the possible outcomes in a tree diagram. c. List the outcomes in each of the following events. Which of these events are simple events? i. \(B\) the event that at least one car has an automatic transmission ii. \(C\) the event that exactly one car has an automatic transmission iii. \(D\) the event that neither car has an automatic transmission d. What outcomes are in the event \(B\) and \(C\) ? In the event \(B\) or \(C\) ?

A construction firm bids on two different contracts. Let \(E_{1}\) be the event that the bid on the first contract is successful, and define \(E_{2}\) analogously for the second contract. Suppose that \(P\left(E_{1}\right)=.4\) and \(P\left(E_{2}\right)=.2\) and that \(E_{1}\) and \(E_{2}\) are independent events. a. Calculate the probability that both bids are successful (the probability of the event \(E_{1}\) and \(E_{2}\) ). b. Calculate the probability that neither bid is successful (the probability of the event \(\left(\right.\) not \(\left.E_{1}\right)\) and \(\left(\right.\) not \(\left.E_{2}\right)\) ). c. What is the probability that the firm is successful in at least one of the two bids?

An individual is presented with three different glasses of cola, labeled C, D, and P. He is asked to taste all three and then list them in order of preference. Suppose that the same cola has actually been put into all three glasses. a. What are the simple events in this chance experiment, and what probability would you assign to each one? b. What is the probability that \(\mathrm{C}\) is ranked first? c. What is the probability that \(\mathrm{C}\) is ranked first \(a n d \mathrm{D}\) is ranked last?

A company that manufactures video cameras produces a basic model and a deluxe model. Over the past year, \(40 \%\) of the cameras sold have been the basic model. Of those buying the basic model, \(30 \%\) purchase an extended warranty, whereas \(50 \%\) of all purchasers of the deluxe model buy an extended warranty. If you learn that a randomly selected purchaser bought an extended warranty, what is the probability that he or she has a basic model?

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