/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Give as much information as you ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 15: Problem 1

Give as much information as you can about the \(P\) -value for an upper-tailed \(F\) test in each of the following situations. a. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=15, F=5.37\) b. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=15, F=1.90\) c. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=15, F=4.89\) d. \(\mathrm{df}_{1}=3, \mathrm{df}_{2}=20, F=14.48\) e. \(\mathrm{df}_{1}=3, \mathrm{df}_{2}=20, F=2.69\) f. \(\mathrm{df}_{1}=4, \mathrm{df}_{2}=50, F=3.24\)

Short Answer

Expert verified
The exact P-values can not be stated unless the F distribution table or statistical software is available. However, the main point is to understand that the P-value can be calculated given the degrees of freedom and an F value for an upper-tailed F test. This P-value tells us the probability of getting the observed data, given that the null hypothesis is true.

Step by step solution

01

Calculate the P-value for first scenario

Make use of an F distribution table, calculator, or statistical software to find the P-value for a scenario where \(\mathrm{df}_{1}=4\), \(\mathrm{df}_{2}=15\), and \(F=5.37\).
02

Calculate the P-value for second scenario

Determine the P-value given that \(\mathrm{df}_{1}=4\), \(\mathrm{df}_{2}=15\), and \(F=1.90\).
03

Calculate the P-value for third scenario

Find out the P-value for the scenario where \(\mathrm{df}_{1}=4\), \(\mathrm{df}_{2}=15\), and \(F=4.89\).
04

Calculate the P-value for fourth scenario

Obtain the P-value for the situation when \(\mathrm{df}_{1}=3\), \(\mathrm{df}_{2}=20\), and \(F=14.48\).
05

Calculate the P-value for fifth scenario

Determine the P-value for the scenario where \(\mathrm{df}_{1}=3\), \(\mathrm{df}_{2}=20\), and \(F=2.69\).
06

Calculate the P-value for sixth scenario

Confirm the P-value for the setting where \(\mathrm{df}_{1}=4\), \(\mathrm{df}_{2}=50\), and \(F=3.24\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The article "Heavy Drinking and Problems Among Wine Drinkers" (Journal of Studies on Alcohol [1999]: 467-471) analyzed drinking problems among Canadians. For each of several different groups of drinkers, the mean and standard deviation of "highest number of drinks consumed" were calculated: \(\bar{x}\) $$\begin{array}{lccc} & \overline{\boldsymbol{x}} & \boldsymbol{s} & {n} \\ \hline \text { Beer only } & 7.52 & 6.41 & 1256 \\ \text { Wine only } & 2.69 & 2.66 & 1107 \\ \text { Spirits only } & 5.51 & 6.44 & 759 \\ \text { Beer and wine } & 5.39 & 4.07 & 1334 \\ \text { Beer and spirits } & 9.16 & 7.38 & 1039 \\ \text { Wine and spirits } & 4.03 & 3.03 & 1057 \\ \text { Beer, wine, and spirits } & 6.75 & 5.49 & 2151 \end{array}$$ Assume that each of the seven samples studied can be viewed as a random sample for the respective group. Is there sufficient evidence to conclude that the mean value of highest number of drinks consumed is not the same for all seven groups?

Consider the accompanying data on plant growth after the application of different types of growth hormone. $$\begin{array}{llrlrl} & \mathbf{1} & 13 & 17 & 7 & 14 \\ & \mathbf{2} & 21 & 13 & 20 & 17 \\ \text { Hormone } & \mathbf{3} & 18 & 14 & 17 & 21 \\ & \mathbf{4} & 7 & 11 & 18 & 10 \\ & \mathbf{5} & 6 & 11 & 15 & 8 \end{array}$$ a. Carry out the \(F\) test at level \(\alpha=.05\). b. What happens when the T-K procedure is applied? (Note: This "contradiction" can occur when is "barely" rejected. It happens because the test and the multiple comparison method are based on different distributions. Consult your friendly neighborhood statistician for more information.)

The article "Utilizing Feedback and Goal Setting to Increase Performance Skills of Managers" (Academy of Management Journal \([1979]: 516-526\) ) reported the results of an experiment to compare three different interviewing techniques for employee evaluations. One method allowed the employee being evaluated to discuss previous evaluations, the second involved setting goals for the employee, and the third did not allow either feedback or goal setting. After the interviews were concluded, the evaluated employee was asked to indicate how satisfied he or she was with the interview. (A numerical scale was used to quantify level of satisfaction.) The authors used ANOVA to compare the three interview techniques. An \(F\) statistic value of \(4.12\) was reported. a. Suppose that a total of 33 subjects were used, with each technique applied to 11 of them. Use this information to conduct a level \(.05\) test of the null hypothesis of no difference in mean satisfaction level for the three interview techniques. b. The actual number of subjects on which each technique was used was \(45 .\) After studying the \(F\) table, explain why the conclusion in Part (a) still holds.

The degree of success at mastering a skill often depends on the method used to learn the skill. The article "Effects of Occluded Vision and Imagery on Putting Golf Balls" (Perceptual and Motor Skills [1995]: \(179-186\) ) reported on a study involving the following four learning methods: (1) visual contact and imagery, (2) nonvisual contact and imagery, (3) visual contact, and (4) control. There were 20 subjects randomly assigned to each method. The following summary information on putting performance score was reported: $$\begin{array}{cccccc} \text { Method } & 1 & 2 & 3 & 4 & \\ \hline \bar{x} & 16.30 & 15.25 & 12.05 & 9.30 & \overline{\bar{x}}=13.23 \\ s & 2.03 & 3.23 & 2.91 & 2.85 & \end{array}$$ a. Is there sufficient evidence to conclude the mean putting performance score is not the same for the four methods? b. Calculate the \(95 \%\) T-K intervals, and then use the underscoring procedure described in this section to identify significant differences among the learning methods.

An investigation carried out to study the toxic effects of mercury was described in the article "Comparative Responses of the Action of Different Mercury Compounds on Barley" (International Journal of Environmental Studies \([1983]: 323-327\) ). Ten different concentrations of mercury \((0,1,5,10,50,100,200,300,400\), and \(500 \mathrm{mg} / \mathrm{L})\) were compared with respect to their effects on average dry weight (per 100 seven- day-old seedlings). The basic experiment was replicated four times for a total of 40 dryweight observations (four for each treatment level). The article reported an ANOVA \(F\) statistic value of \(1.895 .\) Using a significance level of \(.05\), test the null hypothesis that the true mean dry weight is the same for all 10 concentration levels.
See all solutions

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Read Explanation

Discrete Mathematics

Read Explanation

Logic and Functions

Read Explanation

Pure Maths

Read Explanation

Mechanics Maths

Read Explanation

Probability and Statistics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.