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The article "Caffeine Knowledge, Attitudes, and Consumption in Adult Women" (Journal of Nutrition Education [1992]: \(179-184\) ) reported the following summary statistics on daily caffeine consumption for a random sample of adult women: \(n=47, \bar{x}=215 \mathrm{mg}, s=\) \(235 \mathrm{mg}\), and the data values ranged from 5 to 1176 . a. Does it appear plausible that the population distribution of daily caffeine consumption is normal? Is it necessary to assume a normal population distribution to test hypotheses about the value of the population mean consumption? Explain your reasoning. b. Suppose that it had previously been believed that mean consumption was at most \(200 \mathrm{mg}\). Does the given information contradict this prior belief? Test the appropriate hypotheses at significance level. \(10 .\)

Short Answer

Expert verified
In conclusion, plausibility of normal distribution for caffeine consumption cannot be definitively determined with limited information. And hypotheses testing reveals whether mean caffeine consumption statistically exceeds 200 mg. Given the input information, it's important to compute and analyse the test statistic correctly.

Step by step solution

01

Explore Data Distribution

First, let's evaluate whether it's plausible that the population distribution of daily caffeine consumption is normal. It is hard to determine only with given information because we have limited data. It is commonly checked by using the histogram, residuals, skewness, and kurtosis. In general, outliers could severely skew the distribution away from normal. Since we know that data range from 5 to 1176, indication of outliers is there. However, without additional data or graphs, we cannot definitively say whether the population distribution is normal or not. Furthermore, normality of the population distribution is not always crucial for testing hypotheses about the population mean if the sample size is significantly large. If the sample size is large (n > 30), the Central Limit Theorem states that the sample mean distribution will be approximately normal, regardless of the population distribution.
02

Establish Null and Alternative Hypotheses

Next, let's test whether the given information contradicts the prior belief that mean consumption was at most 200 mg. We do this by setting up our null and alternative hypotheses. The null hypothesis would be \(H_{0}\): \(\mu\) \(\leq\) 200 mg, meaning the mean caffeine consumption is at most 200 mg. The alternative hypothesis would be \(H_{1}\): \(\mu\) > 200 mg, meaning the mean caffeine consumption is more than 200 mg.
03

Conduct Hypothesis Testing

Perform the test of the hypothesis by calculating the test statistic, which is like a z-score, according to the formula: \(z\) = (\(\bar{x} - \mu_{0}\)) / (\(s / \sqrt{n}\)), where \(\bar{x}\) is the sample mean (215 mg), \(\mu_{0}\) is the population mean under the null hypothesis (200 mg), and \(s\) is the standard deviation (235 mg), \(n\) is the number of samples (47). Make sure to calculate the z-score correctly.
04

Check Significance Level

Compare the calculated test statistic with a critical value associated with the given significance level. If the test statistic is greater, we reject the null hypothesis, i.e., we have evidence to believe mean consumption is more than 200 mg. If the test statistic is less, we do not reject the null hypothesis, i.e., there's not enough evidence to refute the belief that the mean consumption is at most 200 mg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
In statistics, the normal distribution is a key concept that captures how data is spread out. It's often called a "bell curve" because of its shape. In a normal distribution, most data points are clustered around the mean, and the probabilities decline symmetrically as you move away from it. This kind of pattern is crucial because it helps in statistical analysis and testing hypotheses.
To determine whether the daily caffeine consumption follows a normal distribution, it's common to analyze factors such as skewness and kurtosis. Skewness measures how symmetric the data is, while kurtosis relates to the "tailedness" or how heavy the tails are. Outliers can heavily influence these statistics, as they stretch the data in one direction.
While normal distribution is often assumed in many tests, it's not strictly necessary for all. By the Central Limit Theorem, as long as the sample size is large enough (usually n > 30), the sample mean will tend to follow a normal distribution even if the data itself does not. This allows us to proceed with hypothesis testing confidently.
Null Hypothesis
The null hypothesis is the foundation of hypothesis testing. It's a statement of no effect or no difference and serves as the baseline of our test. For example, if there's a claim that the mean caffeine consumption is at most 200 mg, the null hypothesis formalizes this as:
  • \(H_0: \, \mu \leq 200 \, \text{mg}\)
Under the null hypothesis, we assume that the claim or belief is true unless evidence strongly suggests otherwise. We then calculate a test statistic to help us decide whether or not to reject the null hypothesis.
Rejecting the null hypothesis implies that the data does not support it, suggesting an alternative hypothesis might be true instead. However, if we fail to reject it, it means there's not enough evidence against the claim, and it might still be valid. Remember, "not rejecting" doesn't prove the null hypothesis; it just means we do not have strong enough evidence to invalidate it.
Central Limit Theorem
The Central Limit Theorem (CLT) is a powerful statistical concept that simplifies dealing with complex data. It states that the distribution of the sample means will tend to be normal or "bell-shaped," regardless of the shape of the population distribution, as long as the sample size is large enough (typically n > 30).
This theorem is particularly useful when the underlying data distribution is unknown or when the data does not fit a normal distribution perfectly. It allows statisticians to apply the normal approximation to sample means, making hypothesis testing more reliable. In the context of checking caffeine consumption data, even if the individual data points don't form a perfect normal curve, the CLT guarantees that our sample mean of 215 mg will approximate normality with a sufficient sample size.
Therefore, even without knowing the exact distribution, we can confidently use normal distribution techniques for hypothesis testing, as the large sample size will assure the reliability of the results.
Significance Level
Significance level, denoted as \( \alpha \), is a threshold set by statisticians to determine how strong the evidence must be before rejecting the null hypothesis. A common choice for significance level is 0.05, or 5%, but it can also be set differently, like at 0.10 for more lenient or at 0.01 for more stringent tests.
In hypothesis testing, if the test statistic exceeds the critical value associated with the chosen significance level, we reject the null hypothesis. The significance level essentially represents the probability of rejecting the null hypothesis mistakenly, known as a "Type I error."
For example, with a significance level of 0.10, there's a 10% chance of incorrectly rejecting the null hypothesis. Selecting the right level depends on the context and acceptable error risk. A lower significance level means more confidence in the results, but it also makes it harder to reject the null hypothesis. Therefore, careful consideration is necessary in choosing \( \alpha \) to balance confidence and practicality in statistical conclusions.

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Most popular questions from this chapter

A comprehensive study conducted by the National Institute of Child Health and Human Development tracked more than 1000 children from an early age through elementary school (New York Times, November 1, 2005). The study concluded that children who spent more than 30 hours a week in child care before entering school tended to score higher in math and reading when they were in the third grade. The researchers cautioned that the findings should not be a cause for alarm because the effects of child care were found to be small. Explain how the difference between the mean math score for third graders who spent long hours in child care and the overall mean for thirdgraders could be small but the researchers could still reach the conclusion that the mean for the child care group is significantly higher than the overall mean for third-graders.

Medical personnel are required to report suspected cases of child abuse. Because some diseases have symptoms that mimic those of child abuse, doctors who see a child with these symptoms must decide between two competing hypotheses: \(H_{0}\) " symptoms are due to child abuse \(H_{a}:\) symptoms are due to disease (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) The article "Blurred Line Between Illness, Abuse Creates Problem for Authorities" (Macon Telegraph, February 28,2000 ) included the following quote from a doctor in Atlanta regarding the consequences of making an incorrect decision: "If it's disease, the worst you have is an angry family. If it is abuse, the other kids (in the family) are in deadly danger." a. For the given hypotheses, describe Type I and Type II errors. b. Based on the quote regarding consequences of the two kinds of error, which type of error does the doctor quoted consider more serious? Explain.

Much concern has been expressed in recent years regarding the practice of using nitrates as meat preservatives. In one study involving possible effects of these chemicals, bacteria cultures were grown in a medium containing nitrates. The rate of uptake of radio-labeled amino acid was then determined for each culture, yielding the following observations: \(\begin{array}{llllllll}7251 & 6871 & 9632 & 6866 & 9094 & 5849 & 8957 & 7978\end{array}\) \(\begin{array}{lllllll}7064 & 7494 & 7883 & 8178 & 7523 & 8724 & 7468\end{array}\) Suppose that it is known that the true average uptake for cultures without nitrates is 8000 . Do the data suggest that the addition of nitrates results in a decrease in the true average uptake? Test the appropriate hypotheses using a significance level of \(.10 .\)

Let \(\pi\) denote the proportion of grocery store customers that use the store's club card. For a large sample \(z\) test of \(H_{0}: \pi=.5\) versus \(H_{a}: \pi>.5\), find the \(P\) -value associated with each of the given values of the test statistic: a. \(1.40\) d. \(2.45\) b. \(0.93\) e. \(-0.17\) c. \(1.96\)

The success of the U.S. census depends on people filling out and returning census forms. Despite extensive advertising, many Americans are skeptical about claims that the Census Bureau will guard the information it collects from other government agencies. In a USA Today poll (March 13,2000 ), only 432 of 1004 adults surveyed said that they believe the Census Bureau when it says the information you give about yourself is kept confidential. Is there convincing evidence that, despite the advertising campaign, fewer than half of U.S. adults believe the Census Bureau will keep information confidential? Use a significance level of \(.01\).

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