/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 The state of Georgia's HOPE scho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The state of Georgia's HOPE scholarship program guarantees fully paid tuition to Georgia public universities for Georgia high school seniors who have a B average in academic requirements as long as they maintain a B average in college. Of 137 randomly selected students enrolling in the Ivan Allen College at the Georgia Institute of Technology (social science and humanities majors) in 1996 who had a B average going into college, \(53.2 \%\) had a GPA below \(3.0\) at the end of their first year ("Who Loses HOPE? Attrition from Georgia's College Scholarship Program," Southern Economic Journal [1999]: 379-390). Do these data provide convincing evidence that a majority of students at Ivan Allen College who enroll with a HOPE scholarship lose their scholarship?

Short Answer

Expert verified
The conclusion depends on the comparison of the test statistic and the critical value. If the test statistic is greater than the critical value, there is evidence that a majority of students at Ivan Allen College who enroll with a HOPE scholarship lose their scholarship. If the test statistic is less than the critical value, there is not enough evidence to allege that a majority lose their scholarship.

Step by step solution

01

State the hypotheses

The first step in hypothesis testing is to specify the null hypothesis and the alternative hypothesis. The null hypothesis (Ho): The proportion of students at Ivan Allen College who lose their HOPE scholarship is \(50 \%\) or 0.5. This means that a majority of the students are not losing their scholarships.The alternative hypothesis (Ha): The proportion of students at Ivan Allen College who lose their HOPE scholarship is more than \(50 \%\) or 0.5. This implies that a majority of the students are losing their scholarships.
02

Calculate the Test Statistic

The test statistic in this case is a z-score. The formula for the z test statistic for a population proportion is \[ z = \frac{(p - p_{0})} {\sqrt{ \frac{(p_{0} \times (1 - p_{0}))} {n} }} \] where \( p \) is the sample proportion, \( p_{0} \) is the population proportion under the null hypothesis, and \( n \) is the sample size. In this case, \( p = 0.532 \), \( p_{0} = 0.5 \), and \( n = 137 \). Substitute these values into the formula and calculate the test statistic value.
03

Determine the critical value

The critical value corresponding to a level of significance \( \alpha = 0.05 \) for a one-tailed test and degrees of freedom \( df = n - 1 = 136 \) is approximately 1.645. This means that if the test statistic calculated is greater than 1.645, the null hypothesis will be rejected.
04

Compare the Test Statistic to the Critical Value

If the calculated test statistic is greater than the critical value, it is in the rejection region, so the null hypothesis can be rejected. If it's smaller, the null hypothesis cannot be rejected.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis, often denoted as \( H_0 \), is our initial claim that there is no effect or difference. It is a neutral statement that proposes there is no change or relationship present in the population parameters we are examining. In the context of our exercise, the null hypothesis suggests that the proportion of Ivan Allen College students losing their HOPE scholarship is 0.5, or 50%. This implies that there is no majority; students either lose or retain their scholarships at an equal rate.

- The null hypothesis is usually what researchers try to disprove or reject.- It's vital because it helps to provide a standard claim that skeptically assumes no impact from the tested variables.Understanding the null hypothesis is crucial in guiding the research conclusions and maintaining a level of skepticism until evidence proves otherwise.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_a \), challenges the null hypothesis. This hypothesis suggests that there is indeed an effect or a difference. In our exercise, the alternative hypothesis proposes that more than 50% of the students lose their HOPE scholarship, indicating a majority. This represents a significant deviation from what we would expect if there were no difference.

- The alternative hypothesis is what researchers aim to support with evidence.- Proving the alternative hypothesis often requires establishing enough statistical evidence against the null hypothesis.In statistical tests, the strength of the alternative hypothesis compared to the null is what often leads to deeper insights and scholarly conclusions.
Significance Level
The significance level, often denoted by \( \alpha \), is a critical concept in hypothesis testing. It represents the probability of rejecting the null hypothesis when it is actually true, commonly set at 0.05 or 5%. This level is a pre-determined threshold which helps to delineate the tolerance for error in our test.

- A smaller \( \alpha \), say 0.01, indicates a more strict test, reducing the likelihood of false positives.- Conversely, a larger \( \alpha \), say 0.1, increases the test's sensitivity but also increases the chance of accepting false positives.For our specific test, the 0.05 significance level guides us to a critical value, which will be used to determine whether our test statistic falls within a region to reject the null hypothesis.
Z-Score Calculation
The z-score in hypothesis testing tells us how many standard deviations a data point is from the mean. Here, it serves as our test statistic which helps to determine whether we should reject the null hypothesis or not. For population proportions, the z formula used is:

\[ z = \frac{(p - p_0)} {\sqrt{ \frac{(p_0 \times (1 - p_0))} {n} }}\]Where:
  • \( p \) is the sample proportion, in our case 0.532.
  • \( p_0 \) is the population proportion under the null hypothesis, here 0.5.
  • \( n \) is the sample size, which is 137.
Substituting these values in, the calculation determines how strongly the sample results support or contradict the null hypothesis. This calculated z-score is then compared against the critical value to decide the hypothesis's fate.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A hot tub manufacturer advertises that with its heating equipment, a temperature of \(100^{\circ} \mathrm{F}\) can be achieved in at most \(15 \mathrm{~min}\). A random sample of 25 tubs is selected, and the time necessary to achieve a \(100^{\circ} \mathrm{F}\) temperature is determined for each tub. The sample average time and sample standard deviation are \(17.5\) min and \(2.2\) min, respectively. Does this information cast doubt on the company's claim? Carry out a test of hypotheses using significance level \(.05 .\)

When a published article reports the results of many hypothesis tests, the \(P\) -values are not usually given. Instead, the following type of coding scheme is frequently used: \({ }^{*} p=.05,{ }^{* *} p=.01,{ }^{* * *} p=.001,{ }^{* * * *} p=.0001\). Which of the symbols would be used to code for each of the following \(P\) -values? a. \(.037\) c. 072 b. \(.0026\) d. \(.0003\)

Duck hunting in populated areas faces opposition on the basis of safety and environmental issues. The San Luis Obispo Telegram-Tribune (June 18,1991 ) reported the results of a survey to assess public opinion regarding duck hunting on Morro Bay (located along the central coast of California). A random sample of 750 local residents included 560 who strongly opposed hunting on the bay. Does this sample provide sufficient evidence to conclude that the majority of local residents oppose hunting on Morro Bay? Test the relevant hypotheses using \(\alpha=.01\).

Water samples are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharged water is at most \(150^{\circ} \mathrm{F}\), there will be no negative effects on the river's ecosystem. To investigate whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above \(150^{\circ} \mathrm{F}\), researchers will take 50 water samples at randomly selected times and record the temperature of each sample. The resulting data will be used to test the hypotheses \(H_{0}: \mu=150^{\circ} \mathrm{F}\) versus \(H_{a}: \mu>150^{\circ} \mathrm{F}\). In the context of this example, describe Type I and Type II errors. Which type of error would you consider more serious? Explain.

Ann Landers, in her advice column of October 24 , 1994 (San Luis Obispo Telegram-Tribune), described the reliability of DNA paternity testing as follows: "To get a completely accurate result, you would have to be tested, and so would (the man) and your mother. The test is 100 percent accurate if the man is not the father and \(99.9\) percent accurate if he is." a. Consider using the results of DNA paternity testing to decide between the following two hypotheses: \(H_{0}\) " a particular man is the father \(H_{a}:\) a particular man is not the father In the context of this problem, describe Type I and Type II errors. (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) b. Based on the information given, what are the values of \(\alpha\), the probability of Type I error, and \(\beta\), the probability of Type II error? c. Ann Landers also stated, "If the mother is not tested, there is a \(0.8\) percent chance of a false positive." For the hypotheses given in Part (a), what are the values of \(\alpha\) and \(\beta\) if the decision is based on DNA testing in which the mother is not tested?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.