/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Occasionally, warning flares of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Occasionally, warning flares of the type contained in most automobile emergency kits fail to ignite. A consumer advocacy group wants to investigate a claim against a manufacturer of flares brought by a person who claims that the proportion of defective flares is much higher than the value of \(.1\) claimed by the manufacturer. A large number of flares will be tested, and the results will be used to decide between \(H_{0}=\pi=.1\) and \(H_{a}: \bar{\pi}>.1\), where \(\pi\) represents the true proportion of defective flares made by this manufacturer. If \(H_{0}\) is rejected, charges of false advertising will be filed against the manufacturer. a. Explain why the alternative hypothesis was chosen to be \(H_{a}: \pi>.1\). b. In this context, describe Type I and Type II errors, and discuss the consequences of each.

Short Answer

Expert verified
The alternative hypothesis \(H_{a}: \pi>.1\) is chosen as the advocate suspects the defect rate to be greater than 0.1. A Type I error would falsely accuse the manufacturer of false advertising, leading to potential loss of reputation and legal sanctions for the manufacturer. A Type II error would mean failing to detect a true high defective rate, potentially jeopardizing consumer's safety.

Step by step solution

01

Identify why the alternative hypothesis was chosen.

The alternative hypothesis \(H_{a}: \pi>.1\) was chosen as the advocacy group or person suspect that the true proportion of defective flares is greater than 0.1. This suspicion is opposing the claim made by the manufacturer, hence it forms our alternative hypothesis. The idea here is to provide enough statistical evidence to support this hypothesis instead of the null hypothesis \(H_{0}: \pi = .1\) made by the manufacturer, which states that the proportion of defective flares is exactly 0.1.
02

Define Type I Error

A Type I error in this context would happen if the advocacy group incorrectly rejects the null hypothesis that the defect rate is 0.1 when in fact, it truly is 0.1. Essentially, a Type I error would mean that the group accuses the manufacturer of false advertising unjustly.
03

Define Type II Error

A Type II error in this context is failing to reject the null hypothesis when the alternative hypothesis is true. This means that if the true defect rate of flares by this manufacturer is higher than 0.1, but the statistics do not provide robust evidence to reject the null hypothesis, a Type II error would have occurred.
04

Discuss the Consequences of Type I and Type II Errors

For a Type I error, the consequence could be legal sanctions, loss of reputation, and financial losses for the manufacturer if the false claim is publicized. A Type II error would result in consumers being given faulty flares, potentially leading to safety risks if they are relying on the flares in an emergency situation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing in statistics, the null hypothesis, denoted as \( H_{0} \) serves as a baseline assumption for the statistical test. It usually states that there is 'no effect' or 'no difference' or, as in the context of our exercise, that a certain parameter such as the proportion of defective flares is equal to a specified value. In this case, \( H_{0}: \(\pi = .1\) \) suggests that the alleged proportion of defective flares made by the manufacturer is exactly 10%.
Typically, the goal of statistical testing is to gather enough evidence to reject the null hypothesis in favor of an alternative. The null hypothesis is presumed true unless statistical evidence suggests otherwise. Rejecting \( H_{0} \) is a statement that there is a statistically significant effect or difference that needs attention. If it's rejected incorrectly, however, there can be significant consequences, which we'll explore under the Type I error section.
Alternative Hypothesis
The alternative hypothesis, denoted as \( H_{a} \) or \( H_{1} \) is a statement that contradicts the null hypothesis and represents what the researcher is trying to demonstrate statistically. Alternative hypotheses are formulated based on suspicion, prior evidence, or research questions. In our exercise, the alternative hypothesis is \( H_{a}: \(\pi > .1\) \), proposing that the true proportion of defective flares is greater than the stated 10%.
A test's ability to find support for the alternative hypothesis relies on several factors, including the sample size and the level of statistical significance chosen. Establishing a significant difference that supports the alternative hypothesis could lead to changes in perception, policy, or practice regarding the topic under study.
Type I and Type II Errors
Hypothesis testing isn't infallible; it can result in Type I and Type II errors, which are essentially false positives and false negatives, respectively.

Type I Errors

A Type I error occurs when the null hypothesis is true, but we wrongly reject it. In the flare scenario, it corresponds to incorrect charges against the manufacturer for false advertising, when the flares' defect rate is genuinely at 10%. This error affects the manufacturer's credibility and might have legal and financial repercussions.

Type II Errors

Conversely, a Type II error happens when the null hypothesis is false, yet the test fails to reject it. That is, the defect rate is indeed higher than 10%, but our test doesn't provide sufficient evidence to support the claim. For consumers, such an error implies a risk of using defective flares, which is particularly dangerous in emergency situations. Both types of errors are related to the test's sensitivity and potential impacts on decision-making, indicating the careful balance needed between avoiding false positives and false negatives.
Statistical Evidence
In the context of hypothesis testing, statistical evidence refers to the data-based substantiation used to decide whether to reject the null hypothesis in favor of the alternative hypothesis. It's typically based on a test statistic that measures the degree of agreement between the sample data and the null hypothesis.
Evidence is evaluated against a predetermined significance level (often \( \alpha = 0.05 \)), which acts as a threshold for determining whether the observed results are likely due to random chance or to a true effect. If the test statistic falls into the critical region beyond this threshold, the evidence is considered strong enough to reject the null hypothesis. In our flare defect rate example, sufficient statistical evidence could lead to a conclusion that more than 10% of the flares are, in fact, defective — potentially bringing significant changes in manufacturing practices or regulatory actions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Although arsenic is known to be a poison, it also has some beneficial medicinal uses. In one study of the use of arsenic to treat acute promyelocytic leukemia (APL), a rare type of blood cell cancer, APL patients were given an arsenic compound as part of their treatment. Of those receiving arsenic, \(42 \%\) were in remission and showed no signs of leukemia in a subsequent examination (Washington Post, November 5,1998 ). It is known that \(15 \%\) of APL patients go into remission after the conventional treatment. Suppose that the study had included 100 randomly selected patients (the actual number in the study was much smaller). Is there sufficient evidence to conclude that the proportion in remission for the arsenic treatment is greater than \(.15\), the remission proportion for the conventional treatment? Test the relevant hypotheses using a. 01 significance level.

A survey of teenagers and parents in Canada conducted by the polling organization Ipsos ("Untangling the Web: The Facts About Kids and the Internet," January \(25 .\) 2006) included questions about Internet use. It was reported that for a sample of 534 randomly selected teens, the mean number of hours per week spent online was \(14.6\) and the standard deviation was \(11.6\). a. What does the large standard deviation, \(11.6\) hours, tell you about the distribution of online times for this sample of teens? b. Do the sample data provide convincing evidence that the mean number of hours that teens spend online is greater than 10 hours per week?

Consider the following quote from the article "Review Finds No Link Between Vaccine and Autism" (San Luis Obispo Tribune, October 19,2005 ): " 'We found no evidence that giving MMR causes Crohn's disease and/or autism in the children that get the MMR,' said Tom Jefferson, one of the authors of The Cochrane Review. 'That does not mean it doesn't cause it. It means we could find no evidence of it." (MMR is a measles-mumps-rubella vaccine.) In the context of a hypothesis test with the null hypothesis being that MMR does not cause autism, explain why the author could not just conclude that the MMR vaccine does not cause autism.

Let \(\mu\) denote the true average lifetime for a certain type of pen under controlled laboratory conditions. A test of \(H_{0}: \mu=10\) versus \(H_{a}: \mu<10\) will be based on a sample of size 36. Suppose that \(\sigma\) is known to be \(0.6\), from which \(\sigma_{x}=0.1\). The appropriate test statistic is then $$ z=\frac{\bar{x}-10}{0.1} $$ a. What is \(\alpha\) for the test procedure that rejects \(H_{0}\) if \(z \leq\) \(-1.28 ?\) b. If the test procedure of Part (a) is used, calculate \(\beta\) when \(\mu=9.8\), and interpret this error probability. c. Without doing any calculation, explain how \(\beta\) when \(\mu=9.5\) compares to \(\beta\) when \(\mu=9.8\). Then check your assertion by computing \(\beta\) when \(\mu=9.5\). d. What is the power of the test when \(\mu=9.8 ?\) when \(\mu=9.5 ?\)

The article "Caffeine Knowledge, Attitudes, and Consumption in Adult Women" (Journal of Nutrition Education [1992]: \(179-184\) ) reported the following summary statistics on daily caffeine consumption for a random sample of adult women: \(n=47, \bar{x}=215 \mathrm{mg}, s=\) \(235 \mathrm{mg}\), and the data values ranged from 5 to 1176 . a. Does it appear plausible that the population distribution of daily caffeine consumption is normal? Is it necessary to assume a normal population distribution to test hypotheses about the value of the population mean consumption? Explain your reasoning. b. Suppose that it had previously been believed that mean consumption was at most \(200 \mathrm{mg}\). Does the given information contradict this prior belief? Test the appropriate hypotheses at significance level. \(10 .\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.